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Vanhegan extreme

 
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Wed Nov 26, 2008 4:43 pm    Post subject: Vanhegan extreme Reply with quote

Puzzle 6-625372, rated 2.1.0.1.1

If anyone wants to take a shot at this, I'd be interested to see what's there. I found nothing and had to use a couple of rounds of Medusa.

Code:

+-------+-------+-------+
| . . 7 | . 4 . | 9 . . |
| . 8 . | 1 . . | . . . |
| 4 2 . | 5 . 9 | . . . |
+-------+-------+-------+
| . . 5 | . . 4 | . . . |
| 7 1 8 | . . . | 6 2 4 |
| . . . | 8 . . | 5 . . |
+-------+-------+-------+
| . . . | 6 . 2 | . 8 9 |
| . . . | . . 1 | . 6 . |
| . . 3 | . 9 . | 1 . . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Wed Nov 26, 2008 6:12 pm    Post subject: Reply with quote

Code:
.------------------------.------------------------.------------------------.
| 1356    356     7      | 23      4       368    | 9       135     123568 |
| 3569    8       69     | 1       2367    367    | 2347    3457    23567  |
| 4       2       16     | 5       3678    9      | 378     137     13678  |
:------------------------+------------------------+------------------------:
| 2369    369     5      | 27      1267    4      | 378     1379    1378   |
| 7       1       8      | 9       35      35     | 6       2       4      |
| 2369    3469    2469   | 8       1267    67     | 5       1379    137    |
:------------------------+------------------------+------------------------:
| 15      457     14     | 6       357     2      | 347     8       9      |
| 2589    4579    249    | 347     3578    1      | 2347    6       2357   |
| 2568    4567    3      | 47      9       578    | 1       457     257    |
'------------------------'------------------------'------------------------'

1. (2)r1c4 = (2-8)r1c9 = (8)r1c6 - (8)r9c6 = (8-2)r9c1 = (2)r9c9 - (2)r8c7 = (2)r2c7; r2c5 <> 2
2. XYZ - wing {1,3,5} in box 1
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Wed Nov 26, 2008 9:16 pm    Post subject: Reply with quote

Code:
 +--------------------------------------------------------------------------------+
 |  1356    356     7       |  23      4       368     |  9       135     123568  |
 |  3569    8       69      |  1       2367    367     |  2347    3457    23567   |
 |  4       2       16      |  5       3678    9       |  378     137     13678   |
 |--------------------------+--------------------------+--------------------------|
 |  2369    369     5       |  27      1267    4       |  378     1379    1378    |
 |  7       1       8       |  9       35      35      |  6       2       4       |
 |  2369    3469    2469    |  8       1267    67      |  5       1379    137     |
 |--------------------------+--------------------------+--------------------------|
 |  15      457     14      |  6       357     2       |  347     8       9       |
 |  2589    4579    249     |  347     3578    1       |  2347    6       2357    |
 |  2568    4567    3       |  47      9       578     |  1       457     257     |
 +--------------------------------------------------------------------------------+
 # 122 eliminations remain

Code:
1) Sometimes, extending an AIC into a non-AIC is useful.

extended     | ----------------- AIC ---------------- |
[r1c9]=2 =>  [r9c9]=2=[r9c1]=8=[r9c6]-8-[r1c6]=8=[r1c9]  =>  [r1c9]<>2

2) Same XYZ-Wing as Norm.

Sorry, but NL notation seems the most comfortable for me here.
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Asellus



Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA

PostPosted: Wed Nov 26, 2008 10:15 pm    Post subject: Reply with quote

daj95376 wrote:
Sometimes, extending an AIC into a non-AIC is useful.

Your elimination is an AIC:
(2)r1c9 - (2)r9c9=(2-8)r9c1=(8)r9c6 - (8)r1c6=(8-2)r1c9; r1c9<>2

In NL:
[r1c9]-2-[r9c9]=2=[r9c1]=8=[r9c6]-8-[r1c6]=8=[r1c9] => [r1c9]<>2
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Thu Nov 27, 2008 2:49 am    Post subject: Reply with quote

Asellus wrote:
daj95376 wrote:
Sometimes, extending an AIC into a non-AIC is useful.

Your elimination is an AIC:
(2)r1c9 - (2)r9c9=(2-8)r9c1=(8)r9c6 - (8)r1c6=(8-2)r1c9; r1c9<>2

In NL:
[r1c9]-2-[r9c9]=2=[r9c1]=8=[r9c6]-8-[r1c6]=8=[r1c9] => [r1c9]<>2

The last time I looked, the green logic represents weak inference ... and prohibits the chain from being an AIC.
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Asellus



Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA

PostPosted: Thu Nov 27, 2008 4:09 am    Post subject: Reply with quote

daj95376 wrote:
The last time I looked, the green logic represents weak inference ... and prohibits the chain from being an AIC.

Not at all. It is an AIC loop with a weak link discontinuity. (2)r1c9 is weakly linked to the <8> in the same cell and to the <2> at r9c9. These in turn are strongly linked by the AIC. The Nice Loop convention of linking "cells" rather than candidate digits obscures this, perhaps. Clearly notated discontinuous AIC loops always begin and end with the items at the discontinuity. Some people omit the discontinuity in their notation, but it is there nonetheless.
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Thu Nov 27, 2008 5:31 am    Post subject: Reply with quote

Asellus wrote:
Not at all. It is an AIC loop with a weak link discontinuity.

Yes Exclamation

I'd drilling the basic AIC rules into my head, and I'm still adjusting to the concept of an AIC loop with a weak link. Given my failing memory anymore, odds are that I'll repeat this mistake. Sorry Exclamation
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