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Earl
Joined: 30 May 2007 Posts: 677 Location: Victoria, KS
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Posted: Sun May 31, 2009 1:44 am Post subject: May 31 VH |
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It's high time we had a VH.
A TOWERING SOLUTION: a skyscraper <8> clears the path.
Early Earl |
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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Sun May 31, 2009 3:32 am Post subject: |
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Quote: | It's high time we had a VH.
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Earl,
May I remind you that Danny posts Very Hard puzzles in his forum everyday?
Last edited by storm_norm on Sun May 31, 2009 5:35 am; edited 1 time in total |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun May 31, 2009 4:45 am Post subject: |
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A W-Wing on 89 does it too. I'll echo Norm's suggestion to take a look at Danny's puzzles. |
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crunched
Joined: 05 Feb 2008 Posts: 168
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Posted: Sun May 31, 2009 7:18 am Post subject: |
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An x-y wing does it.
Below (all?) is stripped to the basics.
Code: |
+-------------+-----------------+---------------+
| 9 4 1 | 357 23567 236 | 236 278 2378 |
| 37 5 8 | 37 26 9 | 26 4 1 |
| 37 6 2 | 1 4 8 | 9 57 357 |
+-------------+-----------------+---------------+
| 1 7 59 | 6 89 4 | 25 3 258 |
| 6 89 359 | 2 389 7 | 1 58 4 |
| 48 2 34 | 38 1 5 | 7 9 6 |
+-------------+-----------------+---------------+
| 58 1 6 | 9 23578 23 | 4 257 2357 |
| 2 3 579 | 4 57 1 | 8 6 579 |
| 458 89 4579 | 3578 235678 236 | 235 1 23579 |
+-------------+-----------------+---------------+
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Play this puzzle online at the Daily Sudoku site |
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Clement
Joined: 24 Apr 2006 Posts: 1111 Location: Dar es Salaam Tanzania
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Posted: Sun May 31, 2009 10:50 am Post subject: Daily Sudoku: Sun 31-May-2009 VH |
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Finned X-Wing on 8 solves the puzzle.
There is a potential X-Wing on 8 in columns 1&4 i.e r69c14. The fin rule allows us to remove the 8 in r9c2 because, it shares the same unit (BOX) as the fin cell in r7c1. |
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Earl
Joined: 30 May 2007 Posts: 677 Location: Victoria, KS
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Posted: Sun May 31, 2009 3:39 pm Post subject: May 31 VH |
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"It's high time we had a VH" is a pun on the solution technique, a skyscraper.
Am I too subtle or too dense?
Earl
Last edited by Earl on Mon Jun 01, 2009 4:41 pm; edited 1 time in total |
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gindaani
Joined: 06 Mar 2009 Posts: 79
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Posted: Mon Jun 01, 2009 1:06 am Post subject: |
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The typical xy-wing is all it took for me. An 895 xy-wing for this one.
(I've taken to listing the pivot first in my xy-wing designations. So in this case 89 is the pivot. I think it makes them easier to spot.) |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Mon Jun 01, 2009 2:49 am Post subject: |
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gindaani wrote: | The typical xy-wing is all it took for me. An 895 xy-wing for this one.
(I've taken to listing the pivot first in my xy-wing designations. So in this case 89 is the pivot. I think it makes them easier to spot.) |
Or, you could say -589 where the - precedes the pincer candidate in any chain.
Keith |
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Sue
Joined: 06 Jan 2008 Posts: 6 Location: Adelaide
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Posted: Sun Jun 07, 2009 4:38 am Post subject: anyone can help to clarify |
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Dear posters,
I have got my puzzle to the bare bones as shown above, and have read the discussion here, studied xy wings and skyscrapers, but am not sure how to go ahead with it. Has anyone got the time to point out how the next steps would work?
thanks, sue |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Jun 07, 2009 5:16 am Post subject: |
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Sue,
If you've studied XY-Wings, then you know the basic rule. We start with a cell we call XY. That cell must see both an XZ and a YZ, then any cell that can see both XZ and YZ cannot contain Z. Our XY is the 89 in r5c2. The XZ is the 58 in r5c8 and the YZ is the 59 in r4c3. Thus, obviously, the Z is 5. Both r5c3 and r4c9 see both the XZ (58) and YZ (59), thus neither cell may contain Z (5).
Hope this helps. |
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crunched
Joined: 05 Feb 2008 Posts: 168
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Posted: Sun Jun 07, 2009 5:33 am Post subject: Re: anyone can help to clarify |
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Sue wrote: | Dear posters,
I have got my puzzle to the bare bones as shown above, and have read the discussion here, studied xy wings and skyscrapers, but am not sure how to go ahead with it. Has anyone got the time to point out how the next steps would work?
thanks, sue |
There is a star beside each of the xy pairs (89 59 58 ). The 89 is called the pivot. The 58 and the 59 are the "pincers" each containing a 5. They both "see" or touch the 5 in the cell with 25 and the cell with 258 in row 4 (marked with #). This removes those fives in the cells marked by #. One could also say that 58 and 59 are 2 wings stemming from the 89 cell, and that any number that is the same as the number that the wings have in common (5 in this case) can be brushed away.
Code: |
+-------------+-----------------+---------------+
| 9 4 1 | 357 23567 236 | 236 278 2378 |
| 37 5 8 | 37 26 9 | 26 4 1 |
| 37 6 2 | 1 4 8 | 9 57 357 |
+-------------+-----------------+---------------+
| 1 7 *59 | 6 89 4 |#25 3 #258 |
| 6 *89 359 | 2 389 7 | 1 *58 4 |
| 48 2 34 | 38 1 5 | 7 9 6 |
+-------------+-----------------+---------------+
| 58 1 6 | 9 23578 23 | 4 257 2357 |
| 2 3 579 | 4 57 1 | 8 6 579 |
| 458 89 4579 | 3578 235678 236 | 235 1 23579 |
+-------------+-----------------+---------------+
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Play this puzzle online at the Daily Sudoku site[/quote] |
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Sue
Joined: 06 Jan 2008 Posts: 6 Location: Adelaide
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Posted: Sun Jun 07, 2009 5:41 am Post subject: |
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Got it!
thats brilliant, thank you both of you |
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Sue
Joined: 06 Jan 2008 Posts: 6 Location: Adelaide
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Posted: Sun Jun 07, 2009 5:48 am Post subject: |
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I am looking at it again, and it seems that 58 can also be the pivot, and pince out the 9 in row5 column 3 |
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Sue
Joined: 06 Jan 2008 Posts: 6 Location: Adelaide
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Posted: Sun Jun 07, 2009 5:50 am Post subject: |
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Ha! I'm wrong. Duh |
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