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maryland Guest
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Posted: Tue Jul 19, 2005 10:05 pm Post subject: Sunday, July 17 - 2 solutions |
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Did anyone else find that the 2's & 3's in the two top righthand side quadrants could be interchanged with no effect on the puzzle? |
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samgj Site Admin
Joined: 17 Jul 2005 Posts: 106 Location: Cambridge
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Posted: Wed Jul 20, 2005 12:06 pm Post subject: Re: Sunday, July 17 - 2 solutions |
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maryland wrote: | Did anyone else find that the 2's & 3's in the two top righthand side quadrants could be interchanged with no effect on the puzzle? |
Hi Maryland
But the 3 in the top right 3x3 box is fixed as one of the initial clues, or do I misunderstand?
Sam |
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maryland Guest
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Posted: Wed Jul 20, 2005 10:53 pm Post subject: Sunday, July 17 - 2 solutions |
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you are right -- sorry about that |
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linoliverpool
Joined: 21 Jul 2005 Posts: 4
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Posted: Thu Jul 21, 2005 8:00 am Post subject: Can someone please help me out on this puzzle!!!! |
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Hi All,
I am a firm believer in not adding numbers in and "trying" numbers and seeing if they work.
I am a fairly new starter at all these puzzles but I am stuck on this one.
I have entered a few numbers and can now not logically see any advancement to be made (without the try it and see method). I have put this puzzle in several sudoku solvers and asked suggestions and they all say - no next move can be calculated.
How do I go on from here! I have solved the puzzle by trial and error but that isnt the way they should be done.
I was going to paste the image in here but havent a URL for it so here is how far I have got
6-2---198
-4--9--36
3---6---4
----73-4-
---1-6---
-8-25--1-
825-1--63
93762--51
164---9--
please can someone explain how I progress - thanks a lot
Michael!!![/img] |
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pierceedd
Joined: 22 Jul 2005 Posts: 7 Location: New Jersey, USA
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Posted: Fri Jul 22, 2005 2:52 pm Post subject: Re: Can someone please help me out on this puzzle!-solution |
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I think the trick to this puzzle was realizing two pieces of information in the top row, middle column. The squares to the right of the 9 and 6 must contain either 1 or 2 (there's nowhere else in that group they can go). Consequently, the 8 must be in one of the two squares to the left of the 9 and 6. As a result of this, there is nowhere else in that entire column (the 4th column) that can have an 8. If you eliminate the other 8's in that column, the solution eventually works itself out.
John
linoliverpool wrote: | Hi All,
I am a firm believer in not adding numbers in and "trying" numbers and seeing if they work.
I am a fairly new starter at all these puzzles but I am stuck on this one.
I have entered a few numbers and can now not logically see any advancement to be made (without the try it and see method). I have put this puzzle in several sudoku solvers and asked suggestions and they all say - no next move can be calculated.
How do I go on from here! I have solved the puzzle by trial and error but that isnt the way they should be done.
I was going to paste the image in here but havent a URL for it so here is how far I have got
6-2---198
-4--9--36
3---6---4
----73-4-
---1-6---
-8-25--1-
825-1--63
93762--51
164---9--
please can someone explain how I progress - thanks a lot
Michael!!![/img] |
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linoliverpool
Joined: 21 Jul 2005 Posts: 4
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Posted: Mon Jul 25, 2005 9:04 am Post subject: |
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Everyone around the office is applauding.
Thanks |
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mld25 Guest
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Posted: Mon Jul 25, 2005 3:57 pm Post subject: |
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Ah, finally! That's been bugging me for ages...! |
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