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Free Press Jan 29, 2010

 
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Fri Jan 29, 2010 6:39 pm    Post subject: Free Press Jan 29, 2010 Reply with quote
Code:
Puzzle: FP012910
+-------+-------+-------+
| . . . | . . . | 5 . . |
| 8 1 . | 4 . . | 3 . 9 |
| . 6 5 | . 2 . | . . . |
+-------+-------+-------+
| 9 . . | 5 . . | . . . |
| 7 . 4 | . . . | 8 1 3 |
| . . . | . . 7 | . . 6 |
+-------+-------+-------+
| . . . | . 9 . | . 3 . |
| 6 . 1 | . . 4 | . 7 8 |
| . . 8 | . . . | . . . |
+-------+-------+-------+

Easier, I thought, than Thursday's.

Keith
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Fri Jan 29, 2010 7:40 pm    Post subject: Reply with quote
After basics:
Code:
 *--------------------------------------------------*
 | 34   7    9    | 16   8    36   | 5    24   124  |
 | 8    1    2    | 4    7    5    | 3    6    9    |
 | 34   6    5    | 19   2    39   | 147  8    147  |
 |----------------+----------------+----------------|
 | 9    8    6    | 5    3    1    | 47   24   247  |
 | 7    5    4    | 29   6    29   | 8    1    3    |
 | 1    2    3    | 8    4    7    | 9    5    6    |
 |----------------+----------------+----------------|
 | 25   4    7    | 26   9    8    | 16   3    15   |
 | 6    9    1    | 3    5    4    | 2    7    8    |
 | 25   3    8    | 7    1    26   | 46   9    45   |
 *--------------------------------------------------*

A linked skyscraper?
Quote:
(1=6)r1c4-(6)r7c4=(6-1)r7c7=(1)r3c7
=> r1c9,r3c4<>1
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Fri Jan 29, 2010 9:04 pm    Post subject: Reply with quote
M-wing: 16 are a complementary pair, pincers in R1C4, R7C9 take out 1 in R1C9, revealing a pair 24 in R1 ...

There are also a couple of UR eliminations, which I think do not help.

Keith
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Fri Jan 29, 2010 11:13 pm    Post subject: Reply with quote
It seems that the M-Wing sets up a Type 1 UR on 24. Without it, the Type 4 UR on 24 sets up the easiest BUG+2 you'll ever see.

(Are you saying the M-Wing by itself solves the puzzle?)
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Fri Jan 29, 2010 11:27 pm    Post subject: Reply with quote
Marty R. wrote:
(Are you saying the M-Wing by itself solves the puzzle?)
(1=6)r1c4-(6)r7c4=(6-1)r7c7=(1)r3c7
=> r1c9,r3c4<>1
Did it for me. Very Happy
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storm_norm



Joined: 18 Oct 2007
Posts: 1741
PostPosted: Fri Jan 29, 2010 11:46 pm    Post subject: Reply with quote
yep, the M-wing solves it.
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sat Jan 30, 2010 12:48 am    Post subject: Reply with quote
The M-wing puts the pair 24 in R1C89, and solves R1C1 as 3. The puzzle is done!

Keith
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Sat Jan 30, 2010 1:48 am    Post subject: Reply with quote
arkietech wrote:
Marty R. wrote:
(Are you saying the M-Wing by itself solves the puzzle?)
(1=6)r1c4-(6)r7c4=(6-1)r7c7=(1)r3c7
=> r1c9,r3c4<>1
Did it for me.

Dan, adding spaces and using one line would make your M-Wing easier to recognize as two candidate values across four cells.

(1=6)r1c4 - (6)r7c4 = (6-1)r7c7 = (1)r3c7 => r1c9,r3c4<>1
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Sat Jan 30, 2010 3:36 am    Post subject: Reply with quote
daj95376 wrote:
adding spaces and using one line would make your M-Wing easier to recognize as two candidate values across four cells.

(1=6)r1c4 - (6)r7c4 = (6-1)r7c7 = (1)r3c7 => r1c9,r3c4<>1


Thanks Danny, it does look better. I am not much on patterns. Ididn't know whether it was an m-wing, gm-wing, skyscraper with connections or just an AIC. Very Happy
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storm_norm



Joined: 18 Oct 2007
Posts: 1741
PostPosted: Sat Jan 30, 2010 6:44 am    Post subject: Reply with quote
arkietech wrote:
daj95376 wrote:
adding spaces and using one line would make your M-Wing easier to recognize as two candidate values across four cells.

(1=6)r1c4 - (6)r7c4 = (6-1)r7c7 = (1)r3c7 => r1c9,r3c4<>1


Thanks Danny, it does look better. I am not much on patterns. Ididn't know whether it was an m-wing, gm-wing, skyscraper with connections or just an AIC. Very Happy



don't mean to fry your noodle anymore, but you could make a case for the chain to be all of them.
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Tue Feb 02, 2010 2:48 pm    Post subject: Reply with quote
I believe that the UR24 is a one-stepper.

UR24[(1)r1c9 = (7)r4c9]r14c89 - (7=4)r4c7 - (4=6)r9c7 - (6=1)r7c7; r3c7|r7c9<>1

Ted
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