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Jan 25 VH
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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania

PostPosted: Sun Jan 24, 2010 11:02 pm    Post subject: Jan 25 VH Reply with quote

Finned X-Wing in 1's r29c14. 1 in r9c6 can be eliminated by the fin principle as it shares the same box as the fin. This solves the puzzle in one step.
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gindaani



Joined: 06 Mar 2009
Posts: 79

PostPosted: Sun Jan 24, 2010 11:14 pm    Post subject: Reply with quote

23-5 xy wing is another one stepper, though it unravels slower than typical after the xy-wing.

Edit: That was for the Jan 23 puzzle. The Jan 25 puzzle wasn't even available when I posted this.


Last edited by gindaani on Tue Jan 26, 2010 4:30 pm; edited 1 time in total
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Mon Jan 25, 2010 1:13 am    Post subject: Reply with quote

Skyscraper on 1 for me.
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Mon Jan 25, 2010 3:06 am    Post subject: Reply with quote

w-wing 83 in row 1 and 3 does it also
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Earl



Joined: 30 May 2007
Posts: 677
Location: Victoria, KS

PostPosted: Mon Jan 25, 2010 3:39 am    Post subject: Jan 25 Vh Reply with quote

Remote pairs (36-38) will also do it in a single step.

Earl
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Ema Nymton



Joined: 17 Apr 2009
Posts: 89

PostPosted: Mon Jan 25, 2010 1:24 pm    Post subject: Reply with quote

.

Given:

Code:

+-------------+----------------+----------+
| 7  2   38   | 5     9   368  | 4  36 1  |
| 13 6   9    | 134   34  7    | 8  5  2  |
| 5  48  1348 | 2     38  1368 | 7  36 9  |
+-------------+----------------+----------+
| 48 3   4568 | 7     1   489  | 69 2  58 |
| 9  7   68   | 38    5   2    | 36 1  4  |
| 2  1   458  | 3489  6   3489 | 39 7  58 |
+-------------+----------------+----------+
| 6  489*1348 | 13489 348 5    | 2  49*7  |
| 48*5   2    | 6     7   489  | 1  49 3  |
| 13 49  7    | 1349  2   1349 | 5  8  6  |
+-------------+----------------+----------+


A) reference: r7c2, r7c8, r8c1-
Does the set-up of the numbers eliminate the '4' only from r7c3?

B) reference: r2c1, r2c4, r9c1, r9c4-
Does the set-up of the numbers eliminate the '1' from r9c6?

Ema
Again with the questions?
~@:o?
.
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Mon Jan 25, 2010 3:06 pm    Post subject: Reply with quote

So much stuff on <1>.

We can eliminate <1> from:
R9C16 by colouring wrap
R3C3 by an ER
R2C4 by skyscraper
etc.
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Mon Jan 25, 2010 3:53 pm    Post subject: Reply with quote

Quote:
A) reference: r7c2, r7c8, r8c1-
Does the set-up of the numbers eliminate the '4' only from r7c3?

That's an xyz wing. The 489 (or xyz) sees a 49 (xz) and a 48 (xy). Look for the common number that appears three times - in this case a 4. Then if you find another number that sees all three of the 489, 49 and 48 - whack the 4.
Alternatively, you might also wanna look for a better explanation.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Mon Jan 25, 2010 4:44 pm    Post subject: Reply with quote

cgordon wrote:
Quote:
A) reference: r7c2, r7c8, r8c1-
Does the set-up of the numbers eliminate the '4' only from r7c3?

That's an xyz wing. The 489 (or xyz) sees a 49 (xz) and a 48 (xy). Look for the common number that appears three times - in this case a 4. Then if you find another number that sees all three of the 489, 49 and 48 - whack the 4.
Alternatively, you might also wanna look for a better explanation.

Alternatively, although that is indeed an XYZ-Wing, the 489 is a naked triple in box 7, thus eliminating all other 489s in that box and rendering the Wing unnecessary.
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Mon Jan 25, 2010 6:07 pm    Post subject: Reply with quote

Oh - Right - that too... And there's me trying to impress!! Embarassed
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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania

PostPosted: Mon Jan 25, 2010 10:11 pm    Post subject: Reply with quote

Ema,
Try to assign any candidate in the Grid Reference. You will find that 1 in r9c6 is eliminated.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Mon Jan 25, 2010 10:31 pm    Post subject: Reply with quote

Quote:
B) reference: r2c1, r2c4, r9c1, r9c4-
Does the set-up of the numbers eliminate the '1' from r9c6?

I don't know if the 1 is eliminated via other means or not. But the four cells mentioned would be an X-Wing were it not for the extra 1 (the "fin") in r7c4.

The Finned X-Wing technique in that grid shown would eliminate the 1 from r9c6.
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Mon Jan 25, 2010 10:45 pm    Post subject: Reply with quote

Quote:
B) reference: r2c1, r2c4, r9c1, r9c4-
Does the set-up of the numbers eliminate the '1' from r9c6?

Let me redeem myself here - it's an ER!!

There are only two <1>s in C1.
If R9C1 is a <1> obviously R9C6 cannot be a 1.
If R2C1 is a <1> then R3C6 is the only <1> left in box2 - ergo R9C6 still cannot be a <1>
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Wendy W



Joined: 04 Feb 2008
Posts: 144

PostPosted: Tue Jan 26, 2010 12:39 am    Post subject: Reply with quote

Like a new convert, I am seeing skyscrapers everywhere...one took out the 8 from R4C6; then an xyz wing took out the 9 from R6C4; then another skyscaper took out the 1 from R2C4 and solved the puzzle.
LUV 'EM!
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strmckr



Joined: 18 Aug 2009
Posts: 64

PostPosted: Tue Jan 26, 2010 5:49 am    Post subject: Reply with quote

my path...
singles first:
Code:
.----------------.-------------------.------------.
| 7    2    38   | 5      9    368   | 4   36  1  |
| 134@ 6    9    | 134@   34   7     | 8   5   2  |
| 5    48   1348 | 2      348  13468 | 7   36  9  |
:----------------+-------------------+------------:
| 48   3    4568 | 7      1    489   | 69  2   58 |
| 9    7    68   | 38     5    2     | 36  1   4  |
| 2    1    458  | 3489   6    3489  | 39  7   58 |
:----------------+-------------------+------------:
| 6    489  1348@|13489@  348  5     | 2   49  7  |
| 48   5    2    | 6      7    489   | 1   49  3  |
| 134@ 49   7    | 1349   2    1349  | 5   8   6  |
'----------------'-------------------'------------'


hybrid wing: 1- r2c1 =1= r2c4 -1- r7c4 =1= r7c3 =3= r9c1 -3 => r9c1<>1, r2c1<>3

singles to the end.
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Tue Jan 26, 2010 8:39 am    Post subject: Reply with quote

here is a walkthrough...

1-25-10-VH

I almost make a blunder. but I saw a useless xy-wing extension, that proved fatal.
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Wendy W



Joined: 04 Feb 2008
Posts: 144

PostPosted: Tue Jan 26, 2010 4:00 pm    Post subject: Reply with quote

Wow, way cool, Norm!
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kragzy



Joined: 01 May 2007
Posts: 112
Location: Australia

PostPosted: Sun Feb 07, 2010 10:30 pm    Post subject: Reply with quote

Dulaby's recent posts don't make sense (e.g. the 6 is a given in Box 5).

Like Wendy, I'm a new convert to skyscrapers and now I can't believe that I resisted learning about them for so long. (Thanks to Keith and others for helping me with a couple "diabolicals" recently).

I used a skyscraper on 1 to solve this puzzle and now, going back to it, I cannot find any XY or XYZ wings that solve it. Is this a first for DailySudoku? A puzzle that cannot be solved with standard wings alone?
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Sun Feb 07, 2010 11:01 pm    Post subject: Reply with quote

After basics:
Code:
+-------------------+-------------------+-------------------+
| 7     2     38    | 5     9     368   | 4     36    1     |
| 13    6     9     | 134   34    7     | 8     5     2     |
| 5     48    1348  | 2     38    1368  | 7     36    9     |
+-------------------+-------------------+-------------------+
| 48    3     4568  | 7     1     489   | 69    2     58    |
| 9     7     68    | 38    5     2     | 36    1     4     |
| 2     1     458   | 3489  6     3489  | 39    7     58    |
+-------------------+-------------------+-------------------+
| 6     489   13    | 13489 348   5     | 2     49    7     |
| 48    5     2     | 6     7     489   | 1     49    3     |
| 13    49    7     | 1349  2     1349  | 5     8     6     |
+-------------------+-------------------+-------------------+
There is a UR, but in terms of this site's usual methods for VH puzzles, an X-wing 8 and a couple of XYZ-wings will do it.

Keith
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kragzy



Joined: 01 May 2007
Posts: 112
Location: Australia

PostPosted: Mon Feb 08, 2010 12:07 am    Post subject: Reply with quote

I must be losing my grip. I can see the X wing on 8 (removes 8s from R3C3,6 and R7C4) and I can see XYZ wings on 368 (B2), 458 (B4) and 489 (B7), but none of them produce a result. At least not for me.

Please show me the one/s that I am missing before I slash my wrists! Shocked
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