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Ema Nymton
Joined: 17 Apr 2009 Posts: 89
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Posted: Mon Feb 15, 2010 4:18 pm Post subject: Feb 15 H |
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Code: |
+---------------+------------------+-----------+
| 2346 5 8 | 129 1349 349 | 7 69 23 |
| 2346 7 46 | 5 8 349 | 1 69 23 |
| 9 23 1 | 26 36 7 | 4 5 8 |
+---------------+------------------+-----------+
| 148 1489 3 | 7 149 49 | 5 2 6 |
| 1467 149 2 | 169 134569 34569 | 8 137 147 |
| 5 14A 467 | 8 1346 2 | 9 137 147C|
+---------------+------------------+-----------+
| 17 6 9 | 4 2 8 | 3 17 5 |
| 28 28 5 | 3 7 1 | 6 4 9 |
| 1347 134* 47 | 69 569 569 | 2 8 17B |
+---------------+------------------+-----------+
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Does r6c2 (14), r6c9 (147), and r9c9 (17) remove '1' from r9c2 (134)?
Ema
~@:o|
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Mon Feb 15, 2010 4:38 pm Post subject: |
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That is an XYZ-Wing of sorts (XYZ, XZ, YZ). Normally XYZ-Wings have the XYZ and one other cell in the same box and an elimination is made from any cells that sees all three cells of the Wing. No cells see all three here, so in and of itself, that cell combination doesn't make an elimination.
Of course, if r6c9 were 47, it would be a nice little XY-Wing which would take out the 1. |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Mon Feb 15, 2010 7:03 pm Post subject: |
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did you see the 439 triple in col 6? |
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Ema Nymton
Joined: 17 Apr 2009 Posts: 89
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Posted: Mon Feb 15, 2010 9:18 pm Post subject: |
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arkietech wrote: | did you see the 439 triple in col 6? |
Now that you mention it, no I did not. Now that I used it, I can solve the puzzle.
Thank you.
~@:o)
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