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Puzzle 10/06/20: (B) XY

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Sun Jun 20, 2010 9:27 pm    Post subject: Puzzle 10/06/20: (B) XY Reply with quote

Code:
 +-----------------------+
 | 8 5 . | 4 1 . | . . . |
 | 1 4 . | 5 . . | . . . |
 | . . 3 | 7 . . | . . . |
 |-------+-------+-------|
 | 6 3 8 | 2 . 7 | . . . |
 | 5 . . | . 8 . | . . . |
 | . . . | 6 . 3 | . . 8 |
 |-------+-------+-------|
 | . . . | . . . | 1 6 5 |
 | . . . | . . . | 4 2 . |
 | . . . | . . 4 | 7 . 9 |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site

Code:
 after basics
 +--------------------------------------------------------------+
 |  8     5     279   |  4     1     269   |  36    379   267   |
 |  1     4     279   |  5     3     269   |  8     79    267   |
 |  29    6     3     |  7     29    8     |  5     14    14    |
 |--------------------+--------------------+--------------------|
 |  6     3     8     |  2     45    7     |  9     145   14    |
 |  5     27    24    |  9     8     1     |  36    347   67    |
 |  479   79    1     |  6     45    3     |  2     457   8     |
 |--------------------+--------------------+--------------------|
 |  3479  789   49    |  38    279   29    |  1     6     5     |
 |  79    18    6     |  18    79    5     |  4     2     3     |
 |  23    12    5     |  13    6     4     |  7     8     9     |
 +--------------------------------------------------------------+
 # 53 eliminations remain
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Mon Jun 21, 2010 3:33 pm    Post subject: Reply with quote

First time through this solved using an x-wing and an xy-wing (and maybe a UR1) so went back to look for a more-xy one stepper..

Quote:
xy-chain (with ANP) (2=4)r5c3 - (4=79)r68c1 - (7=2)r3c1; r12c3<>2
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Mon Jun 21, 2010 4:03 pm    Post subject: Reply with quote

Ouch !!! _ Embarassed _ Embarassed _ Embarassed

I was so fixated on an interesting UR solution that I forgot to cross-check the other potential solutions. Here's what caught my attention:

Code:
 after basics: the X-Wing is extraneous
 +--------------------------------------------------------------+
 |  8     5     279   |  4     1     269   |  36    379   267   |
 |  1     4     279   |  5     3     269   |  8     79    267   |
 |  29    6     3     |  7     29    8     |  5    *14   *14    |
 |--------------------+--------------------+--------------------|
 |  6     3     8     |  2    #45    7     |  9   #*145  *14    |
 |  5     27    24    |  9     8     1     |  36    347   67    |
 |  479   79    1     |  6    #45    3     |  2    #457   8     |
 |--------------------+--------------------+--------------------|
 |  3479  789   49    |  38    279   29    |  1     6     5     |
 |  79    18    6     |  18    79    5     |  4     2     3     |
 |  23    12    5     |  13    6     4     |  7     8     9     |
 +--------------------------------------------------------------+
 # 53 eliminations remain

 (*) <14> UR r34c89   (overlapping)
 (#) <45> UR r46c58

 ( <14> UR says r4c8<>14 ) and ( <45> UR says r4c8=1 or r6c8=7 )

Together, they force r6c8=7 and the puzzle cracks with singles remaining.
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Mon Jun 21, 2010 5:35 pm    Post subject: Reply with quote

That's the second of these overlapping URs in as many days... need to up my game on looking for UR moves, just doesn't come naturally!

And you have to play them concurrently for the elimination to appear..
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Tue Jun 22, 2010 6:24 am    Post subject: Reply with quote

I think that is what makes this a good puzzle - I too do not automatically look for uniqueness solutions - this one is elegant.

Fwiw, I saw an almost XY Wing <479> formation r68c1,r7c3 with the fin being 9 in r6c1.

If fin is TRUE (47=9)r6c1-(9=2)r3c1-r12c3=(2-4)r5c3 so r5c3<>4

If fin is FALSE then xy-wing<479> and r5c3<>4

Either way puzzle solved.

We know that the fin can not be 9 because the fin = TRUE chain would create no 4 in b4.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Tue Jun 22, 2010 3:49 pm    Post subject: Reply with quote

Type 1 UR (14)
W-Wing (29) uses both numbers and both were also transported
X-Wing (9)
UR (27) in boxes 13; either DP killer forces r8c1=9
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