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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sat Jul 24, 2010 5:12 pm Post subject: Puzzle 10/07/24: B |
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Code: | +-----------------------+
| . . 9 | 7 5 . | . . . |
| . . . | 6 . . | 7 . 5 |
| 5 . 2 | . . 1 | 8 . . |
|-------+-------+-------|
| 9 2 . | 1 . . | . . 7 |
| 7 . . | . 3 9 | 6 8 . |
| . . 6 | . 2 7 | . . . |
|-------+-------+-------|
| . 1 5 | . 7 . | 4 . . |
| . . . | . 1 . | . . . |
| . 8 . | 9 . . | . . 1 |
+-----------------------+
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun Jul 25, 2010 12:04 am Post subject: |
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Three steps...............
Quote: | xyz-wing (345)r6c2; r6c1<>4 which opens up an
AXY-wing 3-48 vertex (38)r6c1, pincers (48)r1c1 & (34)r6c9 with fin (3)r1c1
If xy-wing is true; r1c9<>4
If fin is true: (3)r1c1-r2c2=r6c2-(3=4)r6c9; r1c9<>4 which opens up a
Kraken cell (348)r2c3
(3)r2c3-(3=4)r2c2; r1c1<>4
(4)r2c3; r1c1<>4
(8)r2c3-(8=4)r4c3-r5c2=(4)r2c2; r1c1<>4 |
Ted |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Sun Jul 25, 2010 11:30 am Post subject: |
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I got seriously bogged down looking at the UR(45) - but it yielded a one-stepper
Code: | Consider UR(45) r56c24 either r6c2=3 or r6c4=8.
Assume r6c4<>8, then I convinced myself (!) this leads to r6c4=8.
r6c4<>8 -- r6c2=3 -- r2c2=4 -- r1c1=8 -- r6c1<>8 -- r6c4=8
-- r6c9=4 -- r1c9=3 |
(Edit. I need some forum formatting lessons!)
I then did it "properly" using four steps..
Quote: | skyscraper(3);
xyz-wing(35-4) r6c2;
xy-wing(48-3) r1c1;
type 1 UR(45) |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Jul 25, 2010 9:46 pm Post subject: |
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Another case where I found I missed some basics after a few moves.
UR 45 makes a couple of deletions
ER (8)
XYZ-Wing (345)
X-Wing (3)
Type 1 UR (45) |
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