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prakash
Joined: 02 Jan 2008 Posts: 67 Location: New Jersey, USA
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Posted: Sun Dec 19, 2010 3:28 pm Post subject: Dec 20 VH |
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One possibility ... X wing followed by BUG+1. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Dec 19, 2010 4:39 pm Post subject: |
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Prakash,
A couple of years ago, perhaps before your time, a message went out to all members requesting that puzzles not be posted or discussed here until the actual puzzle date.
Thanks,
Marty |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Sun Dec 19, 2010 6:47 pm Post subject: |
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Perhaps Prakash is in Austrailia enjoing their fine summer and a spot of cricket.. or at least somewhere far to the east of the USA?
The puzzle seems to be served based on the local time in your browser... |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Dec 19, 2010 8:52 pm Post subject: |
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peterj wrote: | Perhaps Prakash is in Austrailia enjoing their fine summer and a spot of cricket.. or at least somewhere far to the east of the USA?
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That's true, New Jersey per his location. |
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Clement
Joined: 24 Apr 2006 Posts: 1111 Location: Dar es Salaam Tanzania
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Posted: Sun Dec 19, 2010 10:30 pm Post subject: Dec 20 VH |
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W-Wing 27 in r2c2 & r9c7 strongly linked by 7 in col 3 removing 2 in r2c7 solves it.
Also
An XY-Wing 24 27 47 Pivoted in r9c3 eliminating 4 in r6c2 does it as well. |
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kuskey
Joined: 10 Dec 2008 Posts: 141 Location: Pembroke, NH
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Posted: Mon Dec 20, 2010 5:26 am Post subject: Dec 20 VH |
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In addition to the 2 single-steppers and 1 two-stepper already put forth, I came across the following:
(1) 4 w-wings on 27
(2) 2 w-wings on 24
(3) 3 xy-wings on 247 |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Mon Dec 20, 2010 8:58 am Post subject: |
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I think you can play a BUG+3 move without the x-wing if so inclined...
BUG-stoppers are (2)r2c3, (2)r3c3 and (2)r8c7. Either of the first two mean r6c3<>2; the last one using the strong link in row 9 also implies r6c3<>2
Code: | BUG+3
(2)r23c3 ; r6c3<>2
(2)r8c7 - (2)r9c7=r9c3 ; r6c3<>2 |
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