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Dec 20 VH

 
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prakash



Joined: 02 Jan 2008
Posts: 67
Location: New Jersey, USA

PostPosted: Sun Dec 19, 2010 3:28 pm    Post subject: Dec 20 VH Reply with quote

One possibility ... X wing followed by BUG+1.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sun Dec 19, 2010 4:39 pm    Post subject: Reply with quote

Prakash,

A couple of years ago, perhaps before your time, a message went out to all members requesting that puzzles not be posted or discussed here until the actual puzzle date.

Thanks,
Marty
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Sun Dec 19, 2010 6:47 pm    Post subject: Reply with quote

Perhaps Prakash is in Austrailia enjoing their fine summer and a spot of cricket.. or at least somewhere far to the east of the USA?

The puzzle seems to be served based on the local time in your browser...
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sun Dec 19, 2010 8:52 pm    Post subject: Reply with quote

peterj wrote:
Perhaps Prakash is in Austrailia enjoing their fine summer and a spot of cricket.. or at least somewhere far to the east of the USA?

That's true, New Jersey per his location. Laughing
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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania

PostPosted: Sun Dec 19, 2010 10:30 pm    Post subject: Dec 20 VH Reply with quote

W-Wing 27 in r2c2 & r9c7 strongly linked by 7 in col 3 removing 2 in r2c7 solves it.
Also
An XY-Wing 24 27 47 Pivoted in r9c3 eliminating 4 in r6c2 does it as well.
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kuskey



Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH

PostPosted: Mon Dec 20, 2010 5:26 am    Post subject: Dec 20 VH Reply with quote

In addition to the 2 single-steppers and 1 two-stepper already put forth, I came across the following:
(1) 4 w-wings on 27
(2) 2 w-wings on 24
(3) 3 xy-wings on 247
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Mon Dec 20, 2010 8:58 am    Post subject: Reply with quote

I think you can play a BUG+3 move without the x-wing if so inclined...

BUG-stoppers are (2)r2c3, (2)r3c3 and (2)r8c7. Either of the first two mean r6c3<>2; the last one using the strong link in row 9 also implies r6c3<>2

Code:
BUG+3
(2)r23c3 ; r6c3<>2
(2)r8c7 - (2)r9c7=r9c3 ; r6c3<>2
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