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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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 Posted: Sun Jan 30, 2011 9:56 pm Post subject: telegraph 1-28-11 |
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030059600004000000000076008310000065502000809480000071200740000000000700008320010
| Code: |
+-------+-------+-------+
| . 3 . | . 5 9 | 6 . . |
| . . 4 | . . . | . . . |
| . . . | . 7 6 | . . 8 |
+-------+-------+-------+
| 3 1 . | . . . | . 6 5 |
| 5 . 2 | . . . | 8 . 9 |
| 4 8 . | . . . | . 7 1 |
+-------+-------+-------+
| 2 . . | 7 4 . | . . . |
| . . . | . . . | 7 . . |
| . . 8 | 3 2 . | . 1 . |
+-------+-------+-------+
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Play online |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Jan 30, 2011 11:42 pm Post subject: |
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| Quote: | W-Wing (67); r9c2<>7
XY-Wing (342), flightless with transport; r1c4, r2c9<>2 |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jan 31, 2011 6:49 pm Post subject: |
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I found an extended xy wing (pivot 34 - wings 24 and 23 -23- 23) - at least I think I did - I have problems with these. This left a Type 4 UR on 24. But then I got stuck.
Sure can't see a wing for <67>. My R9C2 is still 679. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jan 31, 2011 8:09 pm Post subject: |
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Craig,
This is my post-basics grid. The 67s in boxes 47 are linked by the 6s in c3. After eliminating the 7 from r9c2, r9c1 is the only 7 left in box 7.
| Code: |
+--------------+-----------+-------------+
| 78 3 17 | 128 5 9 | 6 24 247 |
| 678 567 4 | 128 13 23 | 15 9 27 |
| 9 2 15 | 4 7 6 | 135 35 8 |
+--------------+-----------+-------------+
| 3 1 79 | 29 8 47 | 24 6 5 |
| 5 67 2 | 16 13 47 | 8 34 9 |
| 4 8 69 | 5 69 23 | 23 7 1 |
+--------------+-----------+-------------+
| 2 569 356 | 7 4 1 | 59 8 36 |
| 1 45 35 | 69 69 8 | 7 245 234 |
| 67 4679 8 | 3 2 5 | 49 1 46 |
+--------------+-----------+-------------+
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Play this puzzle online at the Daily Sudoku site |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jan 31, 2011 8:23 pm Post subject: |
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| Quote: | | The 67s in boxes 47 are linked by the 6s in c3. |
Sorry Marty: I don't understand that at all.
Craig |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jan 31, 2011 8:47 pm Post subject: |
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Craig,
There are two 6s in c3. If r63=6, then r5c2 must =7. If r7c3=6, then r9c1 must =7, meaning at least one of the 67 cells must be =7, so the two cells act as pincers. That is the essence of a W-Wing; two identical pairs, each of which sees one end of a strong link on one of the numbers. |
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