| View previous topic :: View next topic |
| Author |
Message |
Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
|
 Posted: Mon May 14, 2012 10:46 pm Post subject: May 15 VH |
 |
|
After the Basics | Code: |
+-----------+---------+----------+
| 2-48 24 7 | 3 6 9 | 48 5 1 |
| 48 6 3 | 1 7 5 | 48 2 9 |
| 5 1 9 | 2 8 4 | 7 6 3 |
+-----------+---------+----------+
| 7 8 6 | 4 5 13 | 13 9 2 |
| A13 5 2 | 8 9 7 | 6 B13 4 |
| 9 34 14 | 6 13 2 | 5 7 8 |
+-----------+---------+----------+
| 46 9 45 | 7 2 E13 | D13 8 56 |
| 1-36 7 15 | 9 F13 8 | 2 4 56 |
| 123 23 8 | 5 4 6 | 9 C13 7 |
+-----------+---------+----------+
|
XYZ-Wing 123 pivoted inr9c1; r8c1<>3 solves it.
The Romote Pairs 13, A=B=C=D=E=F do the same eliminaton.
Also the Type 1 UR 48 in Grid r12c17; r1c1<>48 |
|
| Back to top |
|
 |
George Woods
Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK
|
| Posted: Tue May 15, 2012 10:09 am Post subject: almost identical solution |
|
|
| There is an ER solution. The Strong link on 3 in row 5 means that r9c8 cannot be 3 'cos that would imply no room for a 3 in box 7. This is highly related to the solutions above. and indeed if r9c8 were 3 than another intrpreation following the 3s in row 5 would put two 3s in row 9! |
|
| Back to top |
|
|
Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
|
| Posted: Tue May 15, 2012 2:30 pm Post subject: |
|
|
| I used the XYZ-Wing, but the same elimination can also be made via Finned X-Wing. |
|
| Back to top |
|
|
|
|
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
|
Powered by phpBB © 2001, 2005 phpBB Group
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
