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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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 Posted: Wed Jan 05, 2022 12:59 pm Post subject: Jan 05 VH |
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code
Last edited by TomC on Wed Jan 05, 2022 1:10 pm; edited 1 time in total |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Wed Jan 05, 2022 1:15 pm Post subject: |
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| Code: |
+----------+--------+-------------+
| 3 7 4 | 6 1 5 | 2 9 8 |
| 6 2 5 | 9 4 8 | 17 3 17 |
| 1 9 8 | 7 3 2 | 45 46 56 |
+----------+--------+-------------+
| 57c 1 6 | 45 8 3 | 9 2 47b |
| 9 58 3 | 45 2 7 | 6 18 14a |
| 47 48 2 | 1 9 6 | 78 5 3 |
+---------+--------+--------------+
| 2 45 9 | 3 7 1 | 458 468 56 |
| 45d 3 7 | 8 6 9 | 145 14e 2 |
| 8 6 1 | 2 5 4 | 3 7 9 |
+----------+--------+-------------+
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Play this puzzle at the Daily Sudoku site
Pincers on <1> a-e or e-a removes <1> from r5c8 |
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Earl
Joined: 30 May 2007
Posts: 677
Location: Victoria, KS
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| Posted: Wed Jan 05, 2022 2:24 pm Post subject: Jan05 VH |
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Less, elegant, but:
145xyzwing@R8C7, -4R7C7; then:
458xywing@R7C2, -8R6C7
Early Earl |
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ZeroAssoluto
Joined: 05 Feb 2017
Posts: 933
Location: Rimini, Italy
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| Posted: Wed Jan 05, 2022 2:28 pm Post subject: |
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Hi everyone,
in one step:
AIC in r7c2
r7c2=4 and -4 in r8c1, r7c78
r7c2=5 r5c2=8 r5c7=1 r8c8=4 and -4 in r8c1, r7c78
or
XYZ-Wing 1,4,5 in r38c7,r8c8 and -4 in r7c7
and
XY-Wing 4,5,8 in r6c2,r7c27 and -8 in r6c7
Ciao Gianni |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Wed Jan 05, 2022 5:25 pm Post subject: |
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| I think Early Earl just beat you to the XY and XYZ wings Gianni. |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Thu Jan 06, 2022 8:13 pm Post subject: |
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Looking at this again, you don't need the 145 XYZ wing first
if the pivot in r7c2=5 then r8c7=5, r3c7=4, r7c7=8
if the pivot in r7c2=4 then r6c2=8
Pincers of 8 remove the 8 from r6c7 and solve the puzzle |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Jan 07, 2022 10:54 am Post subject: |
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| That’s right - similar to Gianni’s AIC in that the puzzle solved whatever value you put in the pivot |
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