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VH++ 042523

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immpy

Joined: 06 May 2017
Posts: 574

Posted: Tue Apr 25, 2023 6:26 pm Post subject: VH++ 042523

Hello all, enjoy the puzzle.

Code:

+-------+-------+-------+
| 1 . . | . 8 . | . 9 6 |
| . 6 . | . . 1 | . 8 . |
| . 8 . | 9 6 . | . . . |
+-------+-------+-------+
| . . 3 | 1 2 6 | . . . |
| . 2 . | 8 9 4 | . 3 . |
| . 9 . | 5 7 . | 4 . . |
+-------+-------+-------+
| . . . | . 1 2 | . 6 . |
| . 7 . | 6 . . | . 4 . |
| 4 1 . | 7 3 . | . . 8 |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp

dongrave

Joined: 06 Mar 2014
Posts: 572

Posted: Wed Apr 26, 2023 1:40 pm Post subject:

Thanks for the puzzle immp!

After basics:

Code:

+----------------+-------------+-------------------+
| 1 35 4 | 23 8 57 | 2357 9 6 |
| 239 6 2579 | 23 4 1 | 2357 8 2357 |
| a23 8 257 | 9 6 57 | b12357 c1257 4 |
+----------------+-------------+-------------------+
| 57 4 3 | 1 2 6 | 8 57 9 |
| 57 2 1 | 8 9 4 | 6 3 57 |
| 6 9 8 | 5 7 3 | 4 d12 e12 |
+----------------+-------------+-------------------+
| 8 35 59 | 4 1 2 | 379 6 37 |
| 29-3 7 29 | 6 5 8 | 139 4 f13 |
| 4 1 6 | 7 3 9 | 25 25 8 |
+----------------+-------------+-------------------+

Then I used the following chain: 3r3c1 = (3-1)r3c7 = r3c8 - r6c8 = r6c9 - (1=3)r8c9 => r8c1 <> 3; stte.

Clement

Joined: 24 Apr 2006
Posts: 1113
Location: Dar es Salaam Tanzania

Posted: Sun Apr 30, 2023 4:02 pm Post subject: VH ++ 042523

Code:

+-------------------+---------------+-----------------------+
| 1 5-3 4 | 23 8 57 | 2357 9 6 |
| 239 6 2579 | 23 4 1 | 2357 8 2357 |
|f23 8 257 | 9 6 57 |e12357 1257 4 |
+-------------------+---------------+-----------------------+
| 57 4 3 | 1 2 6 | 8 57 9 |
| 57 2 1 | 8 9 4 | 6 3 57 |
| 6 9 8 | 5 7 3 | 4 12 12 |
+-------------------+---------------+-----------------------+
| 8 a35 59 | 4 1 2 |b3579 6 b37 |
| 29-3 7 29 | 6 5 8 |d139 4 c13 |
| 4 1 6 | 7 3 9 | 25 25 8 |
+-------------------+---------------+-----------------------+

Almost like dongrave
(3)r7c2 = r7c79 - (3=1)r8c9 - r8c7 = (1-3)r3c7 = (3)r3c1 => - 3r1c2,r8c1; stte

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