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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Sun May 04, 2008 6:08 am Post subject: competition #1027 |
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competition #1027
Code: | . 4 .|. . .|. . .
. . .|8 . 9|. 4 .
. . 1|5 . .|8 . .
-----+-----+-----
4 . .|. 9 .|. 7 3
. . 8|. 1 .|9 . .
3 6 .|. 2 .|. . 5
-----+-----+-----
. . .|. 8 6|7 . .
. 7 .|9 . 4|. . .
. . .|. . .|. 1 . |
Code: | .------------------.------------------.------------------.
| 8 4 37 | 27 367 1 | 356 2359 269 |
| 25 35 237 | 8 367 9 | 36 4 1 |
| 6 9 1 | 5 4 23 | 8 23 7 |
:------------------+------------------+------------------:
| 4 1 5 | 6 9 8 | 2 7 3 |
| 7 2 8 | 3 1 5 | 9 6 4 |
| 3 6 9 | 4 2 7 | 1 8 5 |
:------------------+------------------+------------------:
| 259 35 4 | 1 8 6 | 7 2359 29 |
| 1 7 236 | 9 35 4 | 356 235 8 |
| 59 8 36 | 27 357 23 | 4 1 69 |
'------------------'------------------'------------------' |
the xy-chain that finishes this off has two ends in the same box.
------
extreme # 84
Code: | 6 2 9|. . .|. 1 .
3 . .|. . .|8 9 6
. . .|7 . .|. . .
-----+-----+-----
. . 5|. 3 9|. 7 .
. . .|. . .|. . .
. 7 .|4 5 .|3 . .
-----+-----+-----
. . .|. . 1|. . .
4 9 3|. . .|. . 1
. 1 .|. . .|5 4 8 |
Code: | .---------------------.---------------------.---------------------.
| 6 2 9 | 3 8 45 | 47 1 457 |
| 3 45 7 | 125 12 245 | 8 9 6 |
| 158 458 148 | 7 9 6 | 24 235 2345 |
:---------------------+---------------------+---------------------:
| 28 468 5 | 1268 3 9 | 1246 7 24 |
| 289 3 2468 | 1268 126 7 | 12469 2568 2459 |
| 1289 7 1268 | 4 5 28 | 3 268 29 |
:---------------------+---------------------+---------------------:
| 2578 568 268 | 26 4 1 | 2679 236 2379 |
| 4 9 3 | 58 267 58 | 267 26 1 |
| 27 1 26 | 9 267 3 | 5 4 8 |
'---------------------'---------------------'---------------------' |
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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Sun May 04, 2008 8:14 am Post subject: |
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here is a beginning volley on the extreme monster.
this image should show a w-wing that has been extended.
the pair is {2,6} in r7c4 and r8c8, and the strong link is on 6 in row 6.
sorry i am not yet fluent in the correct notation to express this.
if you follow around from r7c4 is not 2
then r7c4 is 6, r7c23 is not 6, r9c3 is 6, r6c3 is not 6, r6c8 is 6, r8c8 is 2
other way...
r8c8 is not 2, r8c8 is 6, r6c8 is not 6, r6c3 is 6, r79c3 is not 6, r7c1 is 6, r7c4 is 2
since either r7c4 and r8c8 is a 2 then we can eliminate any 2's they see.
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Victor
Joined: 29 Sep 2005 Posts: 207 Location: NI
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Posted: Sun May 04, 2008 10:50 am Post subject: |
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At a quick look, this is indeed a serious puzzle. Your starter is very attractive - I like pairs like this that can be linked in some useful way. There's one easy move as well: there's a kite in 6s in c2 & r6 that removes 6 from r7c8.
And here's one of my XY-chain-extended AICs that may or may not be much help. Say r5c3 is 8. Then r4c2 must be 4, r4c9 must be 2, and r4c1 must be 8. That's a contradiction (two 8s in the same box) and so we can remove the 8 from r5c3.
Last edited by Victor on Sun May 04, 2008 11:33 am; edited 1 time in total |
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Victor
Joined: 29 Sep 2005 Posts: 207 Location: NI
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Posted: Sun May 04, 2008 11:31 am Post subject: |
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That takes us to here. Code: |
+---------------+---------------+----------------+
| 6 2 9 | 3 8 45 | 47 1 457 |
| 3 45 7 | 125 12 245 | 8 9 6 |
| 158 458 148 | 7 9 6 | 24 25 3 |
+---------------+---------------+----------------+
| 128 468 5 | 1268 3 9 | 124 7 24 |
| 289 3 246 | 1268 126 7 | 1249 2568 2459 |
| 1289 7 1268 | 4 5 28 | 3 268 29 |
+---------------+---------------+----------------+
| 2578 568 268 | 26 4 1 | 679 3 79 |
| 4 9 3 | 58 67 58 | 267 26 1 |
| 27 1 26 | 9 267 3 | 5 4 8 |
+---------------+---------------+----------------+
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I can offer one more mini-AIC. If r5c3 is 2, then r4c2 is 4, r7c2 is 6, and r9c3 is 2. This contradiction means that we can remove 2 from r5c3. Doesn't seem to help much.
PS. I suppose you can see your sort-of-W-wing as W-wing + ER.The right-hand 6 in r6 sees the 26 under it directly, while the left-hand 6 'sees' the other 26 via the ER in box 7. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun May 04, 2008 11:42 pm Post subject: |
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Victor,
Your last posted grid is messed up somehow. It should be:
Code: | +---------------+---------------+-----------------+
| 6 2 9 | 3 8 45 | 47 1 457 |
| 3 45 7 | 125 12 245 | 8 9 6 |
| 158 458 148 | 7 9 6 | 24 25 3 |
+---------------+---------------+-----------------+
| 28 468 5 | 1268 3 9 | 1246 7 24 |
| 289 3 246 | 1268 126 7 | 12469 2568 2459 |
| 1289 7 1268 | 4 5 28 | 3 268 29 |
+---------------+---------------+-----------------+
| 2578 568 268 | 26 4 1 | 679 3 79 |
| 4 9 3 | 58 67 58 | 267 26 1 |
| 27 1 26 | 9 267 3 | 5 4 8 |
+---------------+---------------+-----------------+ |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun May 04, 2008 11:49 pm Post subject: |
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Since that W-Wing step, there has been an X-Wing on <2> in r38. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Mon May 05, 2008 12:27 am Post subject: |
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After applying the X-Wing (that removes <2>s from c78 of b6), some Medusa multi-coloring reveals the following AIC that solves the puzzle:
(5)r8c6-(5=5)r1c69-(5=5)r5c89-(5=2)r3c8-(2=6)r8c8-(6=8)r6c8-(8=8)r68c6-(8=5)r8c4-(5)r8c6; r8c6<>5
For those who don't follow Eureka notation: If r1c6 is <5>, then r8c6 is not <5>. If r1c6 is not <5>, then r1c9 is <5> and r5c8 is <5>, r3c8 is <2>, r8c8 is <6>, r6c8 is <8> (remember that the <2> is gone from this cell... though the AIC would work in any case), so r8c6 is <8>, r8c4 is <5> and r8c6 is not <5>. Either way, r8c6 is not <5>. |
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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Mon May 05, 2008 3:33 am Post subject: |
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yay, we got that one done |
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