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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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 Posted: Sun Jan 24, 2010 11:02 pm Post subject: Jan 25 VH |
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| Finned X-Wing in 1's r29c14. 1 in r9c6 can be eliminated by the fin principle as it shares the same box as the fin. This solves the puzzle in one step. |
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gindaani
Joined: 06 Mar 2009
Posts: 79
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| Posted: Sun Jan 24, 2010 11:14 pm Post subject: |
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23-5 xy wing is another one stepper, though it unravels slower than typical after the xy-wing.
Edit: That was for the Jan 23 puzzle. The Jan 25 puzzle wasn't even available when I posted this.
Last edited by gindaani on Tue Jan 26, 2010 4:30 pm; edited 1 time in total |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jan 25, 2010 1:13 am Post subject: |
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| Skyscraper on 1 for me. |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Mon Jan 25, 2010 3:06 am Post subject: |
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| w-wing 83 in row 1 and 3 does it also |
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Earl
Joined: 30 May 2007
Posts: 677
Location: Victoria, KS
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| Posted: Mon Jan 25, 2010 3:39 am Post subject: Jan 25 Vh |
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Remote pairs (36-38) will also do it in a single step.
Earl |
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Ema Nymton
Joined: 17 Apr 2009
Posts: 89
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| Posted: Mon Jan 25, 2010 1:24 pm Post subject: |
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.
Given:
| Code: |
+-------------+----------------+----------+
| 7 2 38 | 5 9 368 | 4 36 1 |
| 13 6 9 | 134 34 7 | 8 5 2 |
| 5 48 1348 | 2 38 1368 | 7 36 9 |
+-------------+----------------+----------+
| 48 3 4568 | 7 1 489 | 69 2 58 |
| 9 7 68 | 38 5 2 | 36 1 4 |
| 2 1 458 | 3489 6 3489 | 39 7 58 |
+-------------+----------------+----------+
| 6 489*1348 | 13489 348 5 | 2 49*7 |
| 48*5 2 | 6 7 489 | 1 49 3 |
| 13 49 7 | 1349 2 1349 | 5 8 6 |
+-------------+----------------+----------+
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A) reference: r7c2, r7c8, r8c1-
Does the set-up of the numbers eliminate the '4' only from r7c3?
B) reference: r2c1, r2c4, r9c1, r9c4-
Does the set-up of the numbers eliminate the '1' from r9c6?
Ema
Again with the questions?
~@:o?
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jan 25, 2010 3:06 pm Post subject: |
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So much stuff on <1>.
We can eliminate <1> from:
R9C16 by colouring wrap
R3C3 by an ER
R2C4 by skyscraper
etc. |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jan 25, 2010 3:53 pm Post subject: |
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| Quote: | A) reference: r7c2, r7c8, r8c1-
Does the set-up of the numbers eliminate the '4' only from r7c3? |
That's an xyz wing. The 489 (or xyz) sees a 49 (xz) and a 48 (xy). Look for the common number that appears three times - in this case a 4. Then if you find another number that sees all three of the 489, 49 and 48 - whack the 4.
Alternatively, you might also wanna look for a better explanation. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jan 25, 2010 4:44 pm Post subject: |
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| cgordon wrote: | | Quote: | A) reference: r7c2, r7c8, r8c1-
Does the set-up of the numbers eliminate the '4' only from r7c3? |
That's an xyz wing. The 489 (or xyz) sees a 49 (xz) and a 48 (xy). Look for the common number that appears three times - in this case a 4. Then if you find another number that sees all three of the 489, 49 and 48 - whack the 4.
Alternatively, you might also wanna look for a better explanation. |
Alternatively, although that is indeed an XYZ-Wing, the 489 is a naked triple in box 7, thus eliminating all other 489s in that box and rendering the Wing unnecessary. |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jan 25, 2010 6:07 pm Post subject: |
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Oh - Right - that too... And there's me trying to impress!!  |
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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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| Posted: Mon Jan 25, 2010 10:11 pm Post subject: |
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Ema,
Try to assign any candidate in the Grid Reference. You will find that 1 in r9c6 is eliminated. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Jan 25, 2010 10:31 pm Post subject: |
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| Quote: | B) reference: r2c1, r2c4, r9c1, r9c4-
Does the set-up of the numbers eliminate the '1' from r9c6? |
I don't know if the 1 is eliminated via other means or not. But the four cells mentioned would be an X-Wing were it not for the extra 1 (the "fin") in r7c4.
The Finned X-Wing technique in that grid shown would eliminate the 1 from r9c6. |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Mon Jan 25, 2010 10:45 pm Post subject: |
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| Quote: | B) reference: r2c1, r2c4, r9c1, r9c4-
Does the set-up of the numbers eliminate the '1' from r9c6? |
Let me redeem myself here - it's an ER!!
There are only two <1>s in C1.
If R9C1 is a <1> obviously R9C6 cannot be a 1.
If R2C1 is a <1> then R3C6 is the only <1> left in box2 - ergo R9C6 still cannot be a <1> |
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Wendy W
Joined: 04 Feb 2008
Posts: 144
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| Posted: Tue Jan 26, 2010 12:39 am Post subject: |
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Like a new convert, I am seeing skyscrapers everywhere...one took out the 8 from R4C6; then an xyz wing took out the 9 from R6C4; then another skyscaper took out the 1 from R2C4 and solved the puzzle.
LUV 'EM! |
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strmckr
Joined: 18 Aug 2009
Posts: 64
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| Posted: Tue Jan 26, 2010 5:49 am Post subject: |
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my path...
singles first:
| Code: | .----------------.-------------------.------------.
| 7 2 38 | 5 9 368 | 4 36 1 |
| 134@ 6 9 | 134@ 34 7 | 8 5 2 |
| 5 48 1348 | 2 348 13468 | 7 36 9 |
:----------------+-------------------+------------:
| 48 3 4568 | 7 1 489 | 69 2 58 |
| 9 7 68 | 38 5 2 | 36 1 4 |
| 2 1 458 | 3489 6 3489 | 39 7 58 |
:----------------+-------------------+------------:
| 6 489 1348@|13489@ 348 5 | 2 49 7 |
| 48 5 2 | 6 7 489 | 1 49 3 |
| 134@ 49 7 | 1349 2 1349 | 5 8 6 |
'----------------'-------------------'------------' |
hybrid wing: 1- r2c1 =1= r2c4 -1- r7c4 =1= r7c3 =3= r9c1 -3 => r9c1<>1, r2c1<>3
singles to the end. |
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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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| Posted: Tue Jan 26, 2010 8:39 am Post subject: |
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here is a walkthrough...
1-25-10-VH
I almost make a blunder. but I saw a useless xy-wing extension, that proved fatal. |
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Wendy W
Joined: 04 Feb 2008
Posts: 144
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| Posted: Tue Jan 26, 2010 4:00 pm Post subject: |
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| Wow, way cool, Norm! |
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kragzy
Joined: 01 May 2007
Posts: 112
Location: Australia
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| Posted: Sun Feb 07, 2010 10:30 pm Post subject: |
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Dulaby's recent posts don't make sense (e.g. the 6 is a given in Box 5).
Like Wendy, I'm a new convert to skyscrapers and now I can't believe that I resisted learning about them for so long. (Thanks to Keith and others for helping me with a couple "diabolicals" recently).
I used a skyscraper on 1 to solve this puzzle and now, going back to it, I cannot find any XY or XYZ wings that solve it. Is this a first for DailySudoku? A puzzle that cannot be solved with standard wings alone? |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sun Feb 07, 2010 11:01 pm Post subject: |
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After basics: | Code: | +-------------------+-------------------+-------------------+
| 7 2 38 | 5 9 368 | 4 36 1 |
| 13 6 9 | 134 34 7 | 8 5 2 |
| 5 48 1348 | 2 38 1368 | 7 36 9 |
+-------------------+-------------------+-------------------+
| 48 3 4568 | 7 1 489 | 69 2 58 |
| 9 7 68 | 38 5 2 | 36 1 4 |
| 2 1 458 | 3489 6 3489 | 39 7 58 |
+-------------------+-------------------+-------------------+
| 6 489 13 | 13489 348 5 | 2 49 7 |
| 48 5 2 | 6 7 489 | 1 49 3 |
| 13 49 7 | 1349 2 1349 | 5 8 6 |
+-------------------+-------------------+-------------------+
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There is a UR, but in terms of this site's usual methods for VH puzzles, an X-wing 8 and a couple of XYZ-wings will do it.
Keith |
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kragzy
Joined: 01 May 2007
Posts: 112
Location: Australia
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| Posted: Mon Feb 08, 2010 12:07 am Post subject: |
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I must be losing my grip. I can see the X wing on 8 (removes 8s from R3C3,6 and R7C4) and I can see XYZ wings on 368 (B2), 458 (B4) and 489 (B7), but none of them produce a result. At least not for me.
Please show me the one/s that I am missing before I slash my wrists!  |
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