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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Fri Feb 12, 2010 6:54 pm Post subject: Puzzle 10/02/12 (A) |
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| Code: | +-----------------------+
| 2 8 . | . . . | 7 . . |
| 4 3 . | . . . | . . 8 |
| . . 7 | . 5 . | 4 2 . |
|-------+-------+-------|
| . . . | 4 . . | . . . |
| . . 3 | . 7 . | . 5 9 |
| . . . | . . 3 | . . 4 |
|-------+-------+-------|
| 3 . 1 | . . . | 9 . . |
| . . 4 | . 9 . | . 1 6 |
| . 7 . | . 1 5 | . 4 . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sat Feb 13, 2010 5:26 am Post subject: |
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Four and one-half steps.
| Quote: | 1. ER (8)
2. X (8)
3. XY (586)
3.5 Pincer transport on above
4. XY (175) |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Sat Feb 13, 2010 8:41 am Post subject: |
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One step but a loooong AIC. | Code: | *--------------------------------------------------------------------*
| 2 8 569 | 169 3 4 | 7 69 15 |
| 4 3 569 | 12679 26 1267 | 15 69 8 |
| 169 169 7 | 689 5 68 | 4 2 3 |
|----------------------+----------------------+----------------------|
| 15678 156 268 | 4 268 9 | 1268 3 17 |
| 68 4 3 | 126 7 126 | 268 5 9 |
| 16789 169 2689 | 5 268 3 | 1268 78 4 |
|----------------------+----------------------+----------------------|
| 3 256 1 | 268 4 268 | 9 78 57 |
| 58 25 4 | 2378 9 278 | 358 1 6 |
| 689 7 689 | 368 1 5 | 38 4 2 |
*--------------------------------------------------------------------*
(7)r6c1 = (7)r6c8 - (7)r7c8 = (7-5)r7c9 = (5)r7c2 - (5)r4c2 = (5-7)r4c1 =
(7)r6c1; r6c1=7
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sat Feb 13, 2010 9:31 am Post subject: |
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Hello Dan,
This is only a comment that you may find useful. Your chain is perfectly fine.
I recently wrote a new chain() module for my solver, and I implemented Eureka notation in the output. However, I recalled RonK's criticism of redundancy in Eureka notation making for longer looking chains. So, I implemented a truncated version of Eureka notation. Here's how your chain would look using the truncated notation.
(7)r6c1 = (7)r6c8 - (7)r7c8 = (7-5)r7c9 = (5)r7c2 - (5)r4c2 = (5-7)r4c1 = (7)r6c1; r6c1=7
(7)r6c1 = r6c8 - r7c8 = (7-5)r7c9 = r7c2 - r4c2 = (5-7)r4c1 = (7)r6c1; r6c1=7
Note: I still keep the final parentheses information.
Regards, Danny |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Sat Feb 13, 2010 1:49 pm Post subject: |
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| daj95376 wrote: | Hello Dan,
This is only a comment that you may find useful. Your chain is perfectly fine.
I recently wrote a new chain() module for my solver, and I implemented Eureka notation in the output. However, I recalled RonK's criticism of redundancy in Eureka notation making for longer looking chains. So, I implemented a truncated version of Eureka notation. Here's how your chain would look using the truncated notation.
(7)r6c1 = (7)r6c8 - (7)r7c8 = (7-5)r7c9 = (5)r7c2 - (5)r4c2 = (5-7)r4c1 = (7)r6c1; r6c1=7
(7)r6c1 = r6c8 - r7c8 = (7-5)r7c9 = r7c2 - r4c2 = (5-7)r4c1 = (7)r6c1; r6c1=7
Note: I still keep the final parentheses information.
Regards, Danny |
Thanks Danny I like it.! |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sat Feb 13, 2010 3:53 pm Post subject: |
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| arkietech wrote: | | Thanks Danny I like it.! |
Great! I was hoping to get a grass-roots movement going on using the truncated Eureka notation, and your chain seemed like the perfect place to start because it used just two values across eight cells.
Regards, Danny |
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Luke451
Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California
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| Posted: Sun Feb 14, 2010 12:01 am Post subject: |
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| daj95376 wrote: | | arkietech wrote: | | Thanks Danny I like it.! |
Great! I was hoping to get a grass-roots movement going on using the truncated Eureka notation, and your chain seemed like the perfect place to start because it used just two values across eight cells. |
I'm on that train with you, all aboard! "Short form" Eureka is already in common use.
If you'll forgive a reference from the "Other Forum," DonM recently acknowledged as much:
| Quote: | | I might also add that, one can still use the 'short form' of Eureka notation whereby after the first placement of a digit in parentheses, subsequently, it doesn't have to be notated at all until a different digit is used. |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sun Feb 14, 2010 5:12 pm Post subject: |
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| Code: | r5c3 2-String Kite <> 8 r9c7
r58 X-Wing <> 8 r469c1,r46c7
<58+6> XY-Wing r8c1/r5c1+r7c2 <> 6 r9c1,r46c2
<17+5> XY-Wing r4c9/r4c2+r7c9 <> 5 r7c2
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