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Free Press Feb 11, 2010 (Thursday)

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keith

Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

Posted: Sat Feb 13, 2010 7:24 pm Post subject: Free Press Feb 11, 2010 (Thursday)

Quite nice.

Code:

Puzzle: FP021110
+-------+-------+-------+
| . 8 . | 4 1 2 | . . . |
| . . 9 | . 7 . | 6 2 . |
| . 3 . | . . . | . . . |
+-------+-------+-------+
| . 6 . | . . . | . 7 . |
| . . 7 | 9 6 8 | 4 . . |
| . 1 . | . . . | . 3 . |
+-------+-------+-------+
| . . . | . . . | . 6 . |
| . 9 4 | . 3 . | 1 . . |
| . . . | 2 8 4 | . 9 . |
+-------+-------+-------+

Keith

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Sat Feb 13, 2010 8:44 pm Post subject:

Quote:

R3c3 was forced = 2 based on any way to kill a 67-57-56 DP in the middle stack

keith

Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

Posted: Sat Feb 13, 2010 9:16 pm Post subject:

Marty,

I don't see how your DP works.
After basics:

Code:

+----------------+----------------+----------------+
| 7 8 6 | 4 1 2 | 39 5 39 |
| 15 4 9 | 358 7 35 | 6 2 18 |
| 125 3 25 | 568 59 569 | 78 4 178 |
+----------------+----------------+----------------+
| 49 6 258 | 13 24 13 | 2589 7 2589 |
| 3 25 7 | 9 6 8 | 4 1 25 |
| 49 1 28 | 57 24 57 | 289 3 6 |
+----------------+----------------+----------------+
| 8 257 3 | 157 59 1579 | 257 6 4 |
| 25 9 4 | 567 3 567 | 1 8 257 |
| 6 57 1 | 2 8 4 | 357 9 357 |
+----------------+----------------+----------------+

To destroy the DP, there is a 5 in R8B8, or an 89 in R3B2C46? The DP is, I assume, 57 in R6B5, 67 in R8B8, and 56 in R3B2.

Quote:

I used a skyscraper on 2 in R57.

Keith

Last edited by keith on Sat Feb 13, 2010 9:29 pm; edited 1 time in total

arkietech

Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

Posted: Sat Feb 13, 2010 9:23 pm Post subject:

I used a:

Quote:

skyscraper 2

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Sat Feb 13, 2010 10:36 pm Post subject:

Quote:

To destroy the DP, there is a 5 in R8B8, or an 89 in R3B2C46? The DP is, I assume, 57 in R6B5, 67 in R8B8, and 56 in R3B2.

I could've screwed up twice (first on paper), but I just used your grid on Draw/Play and got the same result. What is there that you're contesting?

P.S. I never got as far as checking for X-Wings, which is where I'd have found the skyscraper.

keith

Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

Posted: Sat Feb 13, 2010 11:07 pm Post subject:

Marty,

I'm not contesting anything, I'm asking for an explanation. Here's how I see it:

Code:

The DP to be avoided is:

56 in R3 C46
57 in R6 C46
67 in R8 C46.

OK?

To avoid the DP:

One of R8 C46 is 5. I agree, that forces 2 in R3C3.

Or:

R3 C46 are a pseudocell 89 in R3B2. I do not see how that forces anything useful.

Keith

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Sun Feb 14, 2010 12:22 am Post subject:

Quote:

R3 C46 are a pseudocell 89 in R3B2. I do not see how that forces anything useful.

Keith,

If r3c6=9, then it's pretty obvious how the 2 is forced.

If r3c4=8, I tried again and forced the 2. I'm sorry, I can't explain it, but it's a long and convoluted chain.

But once you get the 9 in r3c5, then the 5 in r7c5, it's easy going.

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