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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Tue Feb 23, 2010 7:35 am Post subject: Puzzle 10/02/23 ___ BBDB as VH+ puzzle |
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| Code: | +-----------------------+
| . . 5 | 8 . . | . . . |
| . 7 . | 2 . . | . . . |
| 6 . 3 | . 1 5 | . . 7 |
|-------+-------+-------|
| 7 5 . | 3 2 . | 8 . . |
| . . 4 | 5 . 9 | . . 1 |
| . . 8 | . 7 . | . . 3 |
|-------+-------+-------|
| . . . | 9 . . | 6 7 . |
| . . . | . . . | 4 5 . |
| . . 6 | . 5 8 | . . . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Tue Feb 23, 2010 8:41 pm Post subject: |
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A total of four steps, three of which were the same.
| Quote: | Type 1 UR13 in r19c78 deletes 13 in r1c7,
Now we have two URs; a Type 1 on 29 and a Type 4 on 47. However both share a common cell, r1c2, so the individual deletions of both URs must be determined and then all of the deletions made at the same time. (I assume this is legal for VH & VH+ steps.)
Type 1 UR29 in r13c27 deletes 29 in r1c2,
Type 4 UR49 in r19c12 with x-wing overlay on 4 deletes 9 from r1c12.
A xy-wing 14-9 with vertex in r1c2 completes the puzzle.
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Ted |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Tue Feb 23, 2010 9:18 pm Post subject: |
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I found a one step AIC: | Quote: | | (1)r4c3 = r4c6 - (1=3)r7c6 - r7c2 = (3-6)r5c2 = r6c2 - (6=1)r6c4; r4c6,r6c12<>1 |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Tue Feb 23, 2010 11:33 pm Post subject: |
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Essentially the same as Ted's first three moves. Except rather than using the commonality of the Type 1 29 and Type 4 49 URs, after playing the 29 UR the 49 UR can be played as a Hidden UR, even though one of the 9s has been removed.
However, for my last move I continued on the same theme and examined the implications of the 14-49-19 DP. |
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