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Nataraj Special Holiday "?" #2

 
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Sun Dec 26, 2010 12:27 pm    Post subject: Nataraj Special Holiday "?" #2 Reply with quote

Code:
*-----------*
 |...|2..|1..|
 |...|.73|9..|
 |9.3|...|.7.|
 |---+---+---|
 |.1.|9.5|.6.|
 |8..|4.7|..5|
 |.5.|6.2|.1.|
 |---+---+---|
 |.6.|...|3.8|
 |..1|85.|...|
 |..8|..4|...|
 *-----------*


This one did need some chain work...
Quote:
I am not sure I can get away with describing this AIC as w-wing-like...

AIC ; (3=9)r5c8 - r6c9=r8c9 - r8c6=r79c5 - (9=4)r1c5-(4=3)r1c9 ; r1c8<>3, r46c9<>3

Alternate chains using the SL8 in r1 and SL3 in c8...
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Sun Dec 26, 2010 7:11 pm    Post subject: Reply with quote

I used three moves, each involving an identical sequence of cells in a chain. I wonder if they could be combined in some manner.

BUG-Lite+3 (348) internal SIS: r4c1=2,r46c7=7; r789c1<>2
BUG-Lite (348)[(2)r4c1=(7)r46c7]-(7=6)r9c7-(6=29)r79c5-(9=4)r1c5-(4=3)r1c9-r46c9=r5c8-(3=9)r5c2-(9=2)r9c2; r789c1<>2

Kraken cell (249)r7c3; r7c3<>4,r8c2<>2
(2)r7c3;
||
(4)r7c3-(4=5)r7c1-(5=7)r9c1-(7=6)r9c7-(6=29)r79c5-(9=4)r1c5-(4=3)r1c9-r46c9=r5c8-(3=9)r5c2-r6c3=r7c3*-(9=2)r9c2;
||
(9)r7c3-(9=2)r9c2;

(3=4)r8c2-(4=5)r7c1-(5=7)r9c1-(7=6)r9c7-(6=29)r79c5-(9=4)r1c5-(4=3)r1c9-r46c9=(3)r5c8; r5c2<>3

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sun Dec 26, 2010 10:58 pm    Post subject: Reply with quote

I'm now suspicious of my too-easy solution, three ERs, 9,9,4.
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