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JV
Joined: 09 Jan 2011 Posts: 24 Location: Devon, England
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Posted: Thu Feb 24, 2011 1:08 pm Post subject: spot the square |
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When I joined a few weeks ago, I was embarrassingly crass (frustration perhaps, though that's a reason rather than an excuse). Anyway, it's been good fun catching up, doing old DAZ puzzles, etc.
Here's an oddity, a difficult looking puzzle that needs just one move.
Menneske 5816838 after a couple of straighforward moves:
Code: |
+----------------+---------------+----------------+
| 235 359 1 | 6 79 8 | 479 459 279 |
| 2568 5689 7 | 25 3 4 | 689 1589 1289 |
| 4 5689 5689 | 257 1 579 | 6789 3 2789 |
+----------------+---------------+----------------+
| 1 7 36 | 48 2 36 | 489 489 5 |
| 568 2 4568 | 9 68 1 | 348 7 38 |
| 9 348 348 | 478 5 37 | 1 2 6 |
+----------------+---------------+----------------+
| 3578 1 3589 | 578 789 579 | 2 6 4 |
| 5678 5689 2 | 1 4 5679 | 379 89 3789 |
| 678 4689 489 | 3 6789 2 | 5 189 1789 |
+----------------+---------------+----------------+
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I'll pose it like a puzzle from a Sunday paper: can you find cell X and candidate a such that X = a quickly produces an impossibility? No advanced techniques needed - just look at it.
(I'll leave it to somebody else to explain - maybe of the APE or ALS ilk?)
JV |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Fri Feb 25, 2011 12:28 pm Post subject: |
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Code: | +--------------------------------------------------------------+
| 235 359 1 | 6 79 8 | 479 459 279 |
| 2568 5689 7 | 25 3 4 | 689 1(5)89 1289 |
| 4 5689 5689 | 257 1 579 | 6789 3 2789 |
|--------------------+--------------------+--------------------|
| 1 7 36 | 48 2 36 | 489 489 5 |
| 568 2 4568 | 9 68 1 | 348 7 38 |
| 9 348 348 | 478 5 37 | 1 2 6 |
|--------------------+--------------------+--------------------|
| 3578 1 3589 | 578 789 579 | 2 6 4 |
| 5678 5689 2 | 1 4 5679 | 379 89 3789 |
| 678 4689 489 | 3 6789 2 | 5 189 1789 |
+--------------------------------------------------------------+
# 107 eliminations remain
| ************** AIC *************** |
(5)r2c8 - (5=2)r1c8579 - r1c1 = r2c1 - (2=5)r2c5 - (5)r2c8
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JV
Joined: 09 Jan 2011 Posts: 24 Location: Devon, England
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Posted: Sat Feb 26, 2011 2:45 pm Post subject: |
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Thanks: very neat! (I didn't think of using the ALS in r1, & indeed didn't notice it.)
Most of us would see this via the ALS in box1r23, because you can see without thought that r2c8 = 5 removes 2 & 5 from r2c12, & 5 from r3c23. Can one express this in Eureka? - i.e. restricting it to r23. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun Feb 27, 2011 2:24 am Post subject: |
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Try this:
(5=2)r2c4 - ALS[(2)r2c1=(5)r2c12|r3c23] - (5)r1c12=(5)r1c8 |
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JV
Joined: 09 Jan 2011 Posts: 24 Location: Devon, England
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Posted: Sun Feb 27, 2011 9:25 am Post subject: |
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Thanks, Asellus: very neat. I didn't think of starting with r2c4, but wouldn't have had the confidence to do it anyway. |
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