| View previous topic :: View next topic | 
	
	
		| Author | Message | 
	
		| garytorborg 
 
 
 Joined: 19 Jan 2011
 Posts: 28
 
 
 | 
			
				|  Posted: Wed Mar 23, 2011 9:43 pm    Post subject: More UR goodies? |   |  
				| 
 |  
				| Hmmm.  I'm stuck in a puzzle that I suspect has some more of those hidden URs like the last one.  Can anyone help? 
 
  	  | Code: |  	  | +--------------+--------------+---------------+
 | 89   89  5   | 167 167  2   | 3    146 467  |
 | 3    4   167 | 8   167  9   | 17   5   2    |
 | 2    17  167 | 3   5    4   | 8    9   67   |
 +--------------+--------------+---------------+
 | 79   5   8   | 47  479  3   | 6    2   1    |
 | 19   6   3   | 2   8    15  | 4    7   59   |
 | 4    179 2   | 167 1679 156 | 59   8   3    |
 +--------------+--------------+---------------+
 | 158  2   9   | 146 3    7   | 15   146 4568 |
 | 6    3   17  | 5   124  8   | 1279 14  479  |
 | 1578 178 4   | 9   126  16  | 1257 3   5678 |
 +--------------+--------------+---------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 
 All those "167s" have to mean something...
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
 | 
			
				|  Posted: Wed Mar 23, 2011 10:50 pm    Post subject: |   |  
				| 
 |  
				| Look at R3.  You can eliminate 1 in R2C3. 
 Otherwise, I don't see anything.
 
 Keith
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
 | 
			
				|  Posted: Thu Mar 24, 2011 12:22 am    Post subject: Re: More UR goodies? |   |  
				| 
 |  
				|  	  | garytorborg wrote: |  	  | Hmmm.  I'm stuck in a puzzle that I suspect has some more of those hidden URs like the last one.  Can anyone help? 
 
  	  | Code: |  	  | +--------------+--------------+---------------+
 | 89   89  5   | 167 167  2   | 3    146 467  |
 | 3    4   167 | 8   167  9   | 17   5   2    |
 | 2    17  167 | 3   5    4   | 8    9   67   |
 +--------------+--------------+---------------+
 | 79   5   8   | 47  479  3   | 6    2   1    |
 | 19   6   3   | 2   8    15  | 4    7   59   |
 | 4    179 2   | 167 1679 156 | 59   8   3    |
 +--------------+--------------+---------------+
 | 158  2   9   | 146 3    7   | 15   146 4568 |
 | 6    3   17  | 5   124  8   | 1279 14  479  |
 | 1578 178 4   | 9   126  16  | 1257 3   5678 |
 +--------------+--------------+---------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 
 All those "167s" have to mean something...
 | 
 You can play with the potential 58 UR in boxes 79. R79c1 must be 1 or 7. This pseudo cell combines with r8c3 to force r9c2<>17. R79c9 must be 4,6 or7. This combines with r13c9 to form a 467 pseudo cell, forcing r8c9<>47. Under both scenarios, r1c12=89 and r9c2=8, bringing us here, where I still don't see anything.
 
 
  	  | Code: |  	  | +-------------+--------------+--------------+
 | 8   9   5   | 167 167  2   | 3    146 467 |
 | 3   4   167 | 8   167  9   | 17   5   2   |
 | 2   17  167 | 3   5    4   | 8    9   67  |
 +-------------+--------------+--------------+
 | 79  5   8   | 47  479  3   | 6    2   1   |
 | 19  6   3   | 2   8    15  | 4    7   59  |
 | 4   179 2   | 167 1679 156 | 59   8   3   |
 +-------------+--------------+--------------+
 | 15  2   9   | 46  3    7   | 15   46  8   |
 | 6   3   17  | 5   124  8   | 1279 14  479 |
 | 157 8   4   | 9   126  16  | 1257 3   567 |
 +-------------+--------------+--------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
 | 
			
				|  Posted: Thu Mar 24, 2011 1:39 am    Post subject: |   |  
				| 
 |  
				| Marty, R6C2 is not 9.  Also, look at R3.  R2C3 is not 1.Which gets us here:  	  | Code: |  	  | +----------------+----------------+----------------+ | 8    9    5    | 167  167  2    | 3    146  467  |
 | 3    4    6-7  | 8    167  9    | 17#  5    2    |
 | 2    17   167  | 3    5    4    | 8    9    67   |
 +----------------+----------------+----------------+
 | 79   5    8    | 47   479  3    | 6    2    1    |
 | 19   6    3    | 2    8    15   | 4    7    59   |
 | 4    17   2    | 167  1679 156  | 59   8    3    |
 +----------------+----------------+----------------+
 | 15@  2    9    | 46   3    7    | 15@  46   8    |
 | 6    3    17#  | 5    124  8    | 1279 14   479  |
 | 157  8    4    | 9    126  16   | 1257 3    567  |
 +----------------+----------------+----------------+
 | 
 The W-wing solves it.
 
 Keith
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Asellus 
 
 
 Joined: 05 Jun 2007
 Posts: 865
 Location: Sonoma County, CA, USA
 
 | 
			
				|  Posted: Thu Mar 24, 2011 7:56 am    Post subject: |   |  
				| 
 |  
				| Forgoing DPs, I used the otherwise useless 15 W-Wing in r5c6|r7c7 with transports: (1)r5c6-(1=6)r9c6 and (1)r7c7-ALS[(1)r78c8=(6)r7c8]; r9c9<>6
 
 (Alternately, that second transport can be a short XY-Chain via box 3 to <6> in r3c9.)
 
 After simplification (no <6> in r7c4), repeat with different transports:
 (1)r5c6-(1=9)r5c1 and (1)r7c7-(1=4)r7c4-(4=7)r4c4-(7=9)r4c1; r1c1<>9
 
 That solves the puzzle.
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| daj95376 
 
 
 Joined: 23 Aug 2008
 Posts: 3854
 
 
 | 
			
				|  Posted: Fri Mar 25, 2011 2:04 am    Post subject: |   |  
				| 
 |  
				| Okay, since Ted doesn't seem interested, here's a UR step that helps: 
 
  	  | Code: |  	  | <58> UR r79c19 w/external SIS r1c1=8 and/or r5c9=5 
 (8=9)r1c1 - (9=1)r5c1 - (1=5)r5c6 - UR[(5)r5c9 = (8)r1c1]  =>  r1c1=8
 +--------------------------------------------------------------+
 | #89    89    5     |  167   167   2     |  3     146   467   |
 |  3     4     167   |  8     167   9     |  17    5     2     |
 |  2     17    167   |  3     5     4     |  8     9     67    |
 |--------------------+--------------------+--------------------|
 |  79    5     8     |  47    479   3     |  6     2     1     |
 |  19    6     3     |  2     8     15    |  4     7    #59    |
 |  4     179   2     |  167   1679  156   |  59    8     3     |
 |--------------------+--------------------+--------------------|
 | *58+1  2     9     |  146   3     7     |  15    146  *58+46 |
 |  6     3     17    |  5     124   8     |  1279  14    479   |
 | *58+17 178   4     |  9     126   16    |  1257  3    *58+67 |
 +--------------------------------------------------------------+
 # 69 eliminations remain
 
 r7      Naked  Pair                     <> 15   r7c48
 
 r3  b1  Locked Candidate 2              <> 1    r2c3
 
 c2348 Jellyfish (2222)                <> 1    r1c5,r6c56,r8c57   -or-
 r2579   Jellyfish (2224)                <> 1    r1c5,r6c56,r8c57
 
 r9  b8  Locked Candidate 1              <> 1    r9c17
 
 | 
 
  	  | Code: |  	  | +-----------------------------------------------------+ |  8    9    5    |  167  67   2    |  3    146  467  |
 |  3    4    67   |  8    167  9    |  17   5    2    |
 |  2    17   167  |  3    5    4    |  8    9    67   |
 |-----------------+-----------------+-----------------|
 |  79   5    8    |  47   479  3    |  6    2    1    |
 |  19   6    3    |  2    8    15   |  4    7    59   |
 |  4    17   2    |  167  679  56   |  59   8    3    |
 |-----------------+-----------------+-----------------|
 |  15   2    9    |  46   3    7    |  15   46   8    |
 |  6    3    17   |  5    24   8    |  279  14   479  |
 |  57   8    4    |  9    126  16   |  257  3    567  |
 +-----------------------------------------------------+
 # 48 eliminations remain
 
 W-Wing: (7=1)r2c7 - r1c8 = r8c8 - (1=7)r8c3  =>  r2c3,r8c7<>7   -or-
 W-Wing: (7=1)r2c7 - r7c7 = r7c1 - (1=7)r8c3  =>  r2c3,r8c7<>7   -or-
 W-Wing: (7=1)r2c7 - r7c7 = r8c8 - (1=7)r8c3  =>  r2c3,r8c7<>7
 
 -or-
 
 XY-Chain: (7=1)r2c7 =5r7c7 =1r7c1 =7r8c3     =>  r2c3,r8c7<>7
 
 | 
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| ronk 
 
 
 Joined: 07 May 2006
 Posts: 398
 
 
 | 
			
				|  Posted: Fri Mar 25, 2011 10:27 am    Post subject: |   |  
				| 
 |  
				|  	  | daj95376 wrote: |  	  | ... here's a UR step that helps: 
 
  	  | Code: |  	  | <58> UR r79c19 w/external SIS r1c1=8 and/or r5c9=5 
 (8=9)r1c1 - (9=1)r5c1 - (1=5)r5c6 - UR[(5)r5c9 = (8)r1c1]  =>  r1c1=8
 | 
 | 
 There seems to be a growing tendency to write expressions that result in placements, and I don't understand why. Isn't r1c1<>9 the underlying move here, a move which would still be true even if r1c1 had three or more candidates?
 
 (9)r5c1 = (9)r5c9 - UR[(5)r5c9 = (8)r1c1]  =>  r1c1<>9
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| daj95376 
 
 
 Joined: 23 Aug 2008
 Posts: 3854
 
 
 | 
			
				|  Posted: Fri Mar 25, 2011 5:43 pm    Post subject: |   |  
				| 
 |  
				|  	  | ronk wrote: |  	  | There seems to be a growing tendency to write expressions that result in placements, and I don't understand why. Isn't r1c1<>9 the underlying move here, ...? 
 | 
 Yes, you caught me making the same mistake that I dislike seeing others make. My only excuse is that I was tired from spending the whole day moving furniture so the cleaning lady could get to places that haven't seen sunlight in years. Today, I finish move it all back. Oh Joy!!!
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| wapati 
 
 
 Joined: 10 Jun 2008
 Posts: 472
 Location: Brampton, Ontario, Canada.
 
 | 
			
				|  Posted: Fri Mar 25, 2011 6:19 pm    Post subject: |   |  
				| 
 |  
				| For those who don't see the distinction,  using a UR to set one cell doesn't always get all the eliminations.  If you use the UR to remove all the candidates indicated you may well shorten your solving path.  Geez,  I'm agreeing with ronk!  |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
 | 
			
				|  Posted: Sat Mar 26, 2011 12:49 pm    Post subject: |   |  
				| 
 |  
				| Another perspective of dealing with AURs, is that of using various combinations of strong inferences; each set has the potential of providing different deletions. 
 Ted
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
 | 
			
				|  Posted: Sat Mar 26, 2011 2:30 pm    Post subject: |   |  
				| 
 |  
				| Been away for a while and just had the opportunity to review the details of these earlier posts. The one by Danny using an external strong inference set was short and effective; what more could you want. However, I really liked the technique used by Marty; I think it generally had less probability of success but he made it happen! 
 The great flexibility offered by ADPs is a major attraction to me.
 
 Ted
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		|  |