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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Sun Oct 07, 2012 6:46 am Post subject: Menneske 2897824 |
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Code: |
*-----------*
|.8.|9..|.7.|
|5.1|8..|2.3|
|6..|3..|..8|
|---+---+---|
|...|.8.|521|
|...|5.2|...|
|254|.9.|...|
|---+---+---|
|8..|..9|..2|
|1.5|..8|7.9|
|.2.|..4|.6.|
*-----------*
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Luke451
Joined: 20 Apr 2008 Posts: 310 Location: Southern Northern California
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Posted: Sun Oct 07, 2012 2:45 pm Post subject: |
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Lotsa ways home for this guy.
Code: | *--------------------------------------------------*
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 467 67 | 2 49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
|----------------+----------------+----------------|
|*79+3 36 *79+6 | 4 8 37 | 5 2 1 |
| 37 1 8 | 5 67 2 | 369 39 4 |
| 2 5 4 | 16 9 136 | 36 8 7 |
|----------------+----------------+----------------|
| 8 34 67 | 67 5 9 | 34 1 2 |
| 1 346 5 | 2 36 8 | 7 34 9 |
|*79+3 2 *79 | 17 13 4 | 8 6 5 |
*--------------------------------------------------* |
Internal outs of (79)AUR:
(3=6)r4c2-(6)r3c3=(3)r49c1 ==>r5c1<>3
or maybe external:
"Unique" S-wing:
(7)r7c3=(7)r5c1-(7=6)r5c5-(6)r6c4=(6)r7c4 ==>r7c4<>7 |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Oct 07, 2012 4:21 pm Post subject: |
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Code: | *-----------------------------------------------------*
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 467 67 | 2 49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
|-----------------+------------------+----------------|
| 379 36 A679 | 4 8 37 | 5 2 1 |
| B37 1 8 | 5 C67 2 | 369 39 4 |
| 2 5 4 | D16 9 136 | 36 8 7 |
|-----------------+------------------+----------------|
| 8 34 -67 | E67 5 9 | 34 1 2 |
| 1 346 5 | 2 36 8 | 7 34 9 |
| 379 2 79 | 17 13 4 | 8 6 5 |
*-----------------------------------------------------* |
I also used the DP 79. Either r49c1=3-->r5c1=7(B) or r4c3=6(A). B=7-->E=6 via BCDE; r7c3<>6. |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Sun Oct 07, 2012 6:40 pm Post subject: |
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aur externals still mystify me!
so I am back to "almost" xy-wings:
Code: |
*--------------------------------------------------*
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 c467 67 | 2 b49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
|----------------+----------------+----------------|
| 379 36 679 | 4 8 37 | 5 2 1 |
| 37 1 8 | 5 c67 2 | 369 a39 4 |
| 2 5 4 | 16 9 136 | 36 8 7 |
|----------------+----------------+----------------|
| 8 34 67 | 67 5 9 | 34 1 2 |
| 1 346 5 | 2 c36 8 | 7 4-3 9 |
| 379 2 79 | 17 13 4 | 8 6 5 |
*--------------------------------------------------*
als xy-wing
(3=9)r5c8-(9=4)r2c8-(4=3)als:r258c5 => -3r8c8; stte
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ronk
Joined: 07 May 2006 Posts: 398
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Posted: Mon Oct 08, 2012 12:23 am Post subject: |
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Luke451 wrote: | Code: | *--------------------------------------------------*
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 467 67 | 2 49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
|----------------+----------------+----------------|
|*79+3 36 *79+6 | 4 8 37 | 5 2 1 |
| 37 1 8 | 5 67 2 | 369 39 4 |
| 2 5 4 | 16 9 136 | 36 8 7 |
|----------------+----------------+----------------|
| 8 34 67 | 67 5 9 | 34 1 2 |
| 1 346 5 | 2 36 8 | 7 34 9 |
|*79+3 2 *79 | 17 13 4 | 8 6 5 |
*--------------------------------------------------* |
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Two moves using UR(79)r49c13 can be applied simultaneously:
overlapping x-wing for digit 9 ==> r4c1<>7
external DP busters (7)r5c1 = (7)r7c3 ==> r4c3<>7
stte |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Mon Oct 08, 2012 1:51 am Post subject: |
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ronk wrote: | external DP busters (7)r5c1 = (7)r7c3 ==> r4c3<7> |
(7=3)r5c1-(3=6)aur:r49c13 => -7r4c3
3 in r5c1 forces a 6 in r4c3 due to the dp
Thanks ronk! |
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Luke451
Joined: 20 Apr 2008 Posts: 310 Location: Southern Northern California
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Posted: Mon Oct 08, 2012 5:34 am Post subject: |
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arkietech wrote: | ronk wrote: | external DP busters (7)r5c1 = (7)r7c3 ==> r4c3<7> |
(7=3)r5c1-(3=6)aur:r49c13 => -7r4c3
3 in r5c1 forces a 6 in r4c3 due to the dp |
I think it's simpler than that. Simpler than any of the UR related moves offered above, including my own.
Ron is pointing out that the (79) UR solves the puzzle without the need for a chain at all.
Code: | *--------------------------------------------------*
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 467 67 | 2 49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
|----------------+----------------+----------------|
|*79+3 36 *79+6 | 4 8 37 | 5 2 1 |
| 37 1 8 | 5 67 2 | 369 39 4 |
| 2 5 4 | 16 9 136 | 36 8 7 |
|----------------+----------------+----------------|
| 8 34 67 | 67 5 9 | 34 1 2 |
| 1 346 5 | 2 36 8 | 7 34 9 |
|*79+3 2 *79 | 17 13 4 | 8 6 5 |
*--------------------------------------------------* |
There's a hidden rectangle that takes out (7)r4c1 due to the x-wing overlay on (9) and the naked (79)r9c3.
More simply, if the (7) ended up in r4c1, the DP would be forced:
At the same time, the "external outs" (7r5c1 = 7r7c3) pinch off (7)r4c3.
Each condition exists independently, but when both are applied they solve the puzzle. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Mon Oct 08, 2012 10:23 am Post subject: |
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The X-wing overlaying a UR has been called a "Type 6" UR. Code: | +-------------+-------------+-------------+
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 467 67 | 2 49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
+-------------+-------------+-------------+
|79+3 36 79+6 | 4 8 37 | 5 2 1 |
|-37 1 8 | 5 67 2 | 369 39 4 |
| 2 5 4 | 16 9 136 | 36 8 7 |
+-------------+-------------+-------------+
| 8 34 67 | 67 5 9 | 34 1 2 |
| 1 346 5 | 2 36 8 | 7 34 9 |
|79+3 2 79 | 17 13 4 | 8 6 5 |
+-------------+-------------+-------------+ |
To avoid the DP, either R4C13 is 36, or R9C1 is 3. Either way, R5C1 is 7.
Keith |
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aran
Joined: 19 Apr 2010 Posts: 70
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Posted: Mon Oct 08, 2012 10:30 am Post subject: |
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Or
7r4c6=(3+7)r95c1 :=><7>r4c13 |
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ronk
Joined: 07 May 2006 Posts: 398
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Posted: Mon Oct 08, 2012 11:42 am Post subject: |
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aran wrote: | Or
7r4c6=(3+7)r95c1 :=><7>r4c13 |
Not sure what that means but, with external DP busters only ...
(7)r4c6 = (7)r5c1 ==> r4c13<>7, stte
Using external DP busters in r4 and c1 only is sufficient because the 4th AUR cell r9c3 contains only the two UR digits. |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Mon Oct 08, 2012 1:39 pm Post subject: |
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I need to seriously reviewed these posts; I sense another learning session coming on.
My non-AUR solution was a two stepper.
Finned x-wing(9)r18c12 with fin 9r1c3
[(9-6)r1c3=r1c1-(6=5=9)r78 => -9r5c1] = [x-wing(9)r18c12 => -9r5c1] => -9r5c1
xy-wing(59-8)r4c2,r1c2,r6c1 => -8r1c1,r6c2
Ted |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Mon Oct 08, 2012 4:01 pm Post subject: |
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Another "simple" example for using the <79>UR. (Almost the same as Keith's solution.)
Code: | after basics
+-----------------------------------------------------+
| 4 8 3 | 9 2 5 | 1 7 6 |
| 5 79 1 | 8 467 67 | 2 49 3 |
| 6 79 2 | 3 147 17 | 49 5 8 |
|-----------------+-----------------+-----------------|
| *79+3 36 *79+6 | 4 8 37 | 5 2 1 |
| 7-3 1 8 | 5 67 2 | 369 39 4 |
| 2 5 4 | 16 9 136 | 36 8 7 |
|-----------------+-----------------+-----------------|
| 8 34 67 | 67 5 9 | 34 1 2 |
| 1 346 5 | 2 36 8 | 7 34 9 |
| *79+3 2 *79 | 17 13 4 | 8 6 5 |
+-----------------------------------------------------+
# 38 eliminations remain
(3)r49c1 - (3)r5c2
(6)r4c3 - (6=3)r4c2 - (3)r5c2
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Mon Oct 08, 2012 5:14 pm Post subject: |
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daj95376 wrote: | (Almost the same as Keith's solution.) |
Yes, I didn't post it for a day because I thought it was very similar to others. Then, I saw we were slicing and dicing this every way possible.
A variant is that the 36 pair in R4 and the 3 in R9C1 respectively cause R4C6 and R5C1 to be pincers on 7.
Keith |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Mon Oct 08, 2012 7:59 pm Post subject: |
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keith wrote: | Then, I saw we were slicing and dicing this every way possible.
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The same reason for my post. |
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