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May 30 VH

 
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Clement



Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania

PostPosted: Wed May 29, 2013 10:23 pm    Post subject: May 30 VH Reply with quote

Code:

+------------+----------+--------------+
| *28  3  24  | 9   1 6  | *58   7   45  |
| 1   68 5   | 2   4 7  | 689  6-89 3   |
| 9   46 7   | 35  8 35 | 26   126 146 |
+------------+----------+--------------+
| 4   2  8   | 136 7 13 | 69   5   169 |
| 6   5  3   | 14  9 2  | 7    14  8   |
| 7   9  1   | 46  5 8  | 3    46  2   |
+------------+----------+--------------+
| 3   7  69  | 158 2 15 | 4    68-9 #569 |
| 25-8 48 246 | 58  3 9  | 1    268 7   |
| *258 1  29  | 7   6 4  | *2589 3   59  |
+------------+----------+--------------+
X-Wing on 8 in r19c17; r8c1<>8, r2c7<>8 and
XYZ-Wing 569 with apex in r7c9; r7c8<>9; stte.
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Wed May 29, 2013 11:21 pm    Post subject: Re: May 30 VH Reply with quote

Clement wrote:
X-Wing on 8 in r19c17; r8c1<>8, r2c7<>8 and
XYZ-Wing 569 with apex in r7c9; r7c8<>9; stte.


All i needed was the x-wing for lclste.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu May 30, 2013 1:26 am    Post subject: Re: May 30 VH Reply with quote

arkietech wrote:
Clement wrote:
X-Wing on 8 in r19c17; r8c1<>8, r2c7<>8 and
XYZ-Wing 569 with apex in r7c9; r7c8<>9; stte.


All i needed was the x-wing for lclste.


The X-Wing did it for me as well.
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hughwill



Joined: 05 Apr 2010
Posts: 424
Location: Birmingham UK

PostPosted: Thu May 30, 2013 10:14 am    Post subject: Re: May 30 VH Reply with quote

Looks to me as though the X wing on 8 and the XYZ on 569 are both
single shots.....
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TerenceF



Joined: 21 Dec 2007
Posts: 26
Location: Takapuna, NZ

PostPosted: Mon Jun 03, 2013 4:59 am    Post subject: Reply with quote

As an alternative, from the same starting point, there is an XY chain starting at r1c9 which eliminates the 5 from r7c9 thus:

If r1c9 = 5 then r7c9<>5 AND
If r1c9 = 4 then r1c3=2 so r9c3=9 so r9c9=5 so r7c9<>5

THis forces r7c8 = 8 which solves the puzzle.
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