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Two UR Type 1's and an xy-wing make short work of this fun puzzle.

re'born,
The extended xyz-wing with pivot at r8c4 and pincers at r8c6 and r4c3 implies one of the endpoints is a 5.

I think you should add the strong link on <3> in R2 that extends the wing. ...

Extend an xyz-wing a little and transport:

*-----------------------------------------------------------*
| 5 2 4 | 6 1379 179 | 179 8 13 |
| 1 9 +38 |+38 ...

oh my, that is not looking good. I think I had that backwards.

should be (1=4)r9c1- (4)r2c1 = (4-1)r2c3 = (1)r6c3; r5c1 <> 1

or it could be (1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r6c3; r ...

Thanks for the keen explanation, daj! Here is the process I'm using to find kraken eliminations:

Find a potential x-wing with one too many cells. Observe the potential eliminations of the x-wing. T ...

If you forgo the pleasant (1 Cool

UR, the same cells point to a Kraken x-wing that eliminates 8 from r5c3, solving the puzzle. I'm really starting to enjoy finding those.

Very good. Now, how about the ...

(1=4)r9c1 - (4)r8c3 = (4-1)r2c3 = (1)r2c1; r5c1 <> 1

Would you explain your last link:
(1)r2c3=r2c1

If you forgo the pleasant UR, the same cells point to a Kraken x-wing that eliminates 8 from r5c3, solving the puzzle. I'm really starting to enjoy finding those.

Incidentally, this same eliminatio ...

Consider the set of cells {r689c4, r9c7}[2469]. The max multiplicity of this set appears to be 6 (1,2,2,1), but closer inspection reveals that 4 and 6 cannot both appear twice. Thus the max multiplici ...

Thanks, daj. The hints help and I think for the first time I'm getting what a kraken x-wing is. It is like transport. The indirect exclusion is a little shady for me. I get it, but only doing a little ...

I'm particulary fond of this puzzle because it contains a Kraken X-Wing that performs 6/7 eliminations. Fortunately, you don't need it to solve the puzzle. If you get energetic, you can search for i ...

OK, nice work and thanks for taking the time. But back to my fragment:

+--------------+-------+-------+
| . . . | . . . | . . . |
| . . . | . . . | . . . |
| . . . | . . . | ...

After the empty rectangle eliminates 9 from r9c2, you get the above grid and the seemingly useless xyz-wing on 8 marked ABC. Both A and B are weakly linked to (8)r9c6=X which is strongly linked to ( Cool

...

An empty rectangle in box 9 kills the 9 in r9c2. A transported xyz-wing with pivot r9c3 then eliminates 8 from r5c5. This cracks the puzzle.

I can't see a transport.

I couldn't at first either. ...

From Steve's deduction, we are left with (after a single and a naked pair)

*-----------------------------------------------------------*
| 589 2 3 | 59 7 4 | 158 1569 168 ...

Uh, yeah. Sorry everyone. I didn't copy things down correctly and I'll go slink away now.

[Edit: Post deleted because I couldn't copy the puzzle down correctly.]

cells {a b}, {a b} that are connected by w-wings on both digits In that case, the cells {a b} are a remote pair. Obviously. Why this is remarkable, I do not know. The first W-wing destroys the ...

Love your astute observations, re'born!
(How long's it been, bout a year? since you last posted here....)

Let me see if I understood the concept by re-phrasing it:

When the ends (pincers) of an ...

The other {2,8} w-wing transports nicely to give r5c3=2. From there a skyscraper on 8 kills it off.