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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Apr 05, 2008 11:43 am Post subject: LA Times / Freep 4 April, 2008 |
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Any creative ideas?
Code: | Puzzle: FP040408
+-------+-------+-------+
| 2 . . | . 4 . | . . 5 |
| . . . | 5 . . | . 7 . |
| . 5 . | . . 1 | . 3 . |
+-------+-------+-------+
| . . 7 | 8 1 . | 6 . . |
| . . 9 | . 5 . | 2 . . |
| . . 1 | . 3 2 | 7 . . |
+-------+-------+-------+
| . 9 . | 4 . . | . 1 . |
| . 6 . | . . 5 | . . . |
| 8 . . | . 6 . | . . 7 |
+-------+-------+-------+ |
Keith |
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Steve R
Joined: 24 Oct 2005 Posts: 289 Location: Birmingham, England
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Posted: Sat Apr 05, 2008 12:57 pm Post subject: |
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Code: | +----------------------------------------+
| 2 7 8 | 3 4 9 | 1 6 5 |
| 1349 134 346 | 5 28 68 | 48 7 29 |
| 49 5 46 | 267 278 1 | 48 3 29 |
------------------------------------------
| 5 2 7 | 8 1 4 | 6 9 3 |
| 34 348 9 | 67 5 67 | 2 48 1 |
| 6 48 1 | 9 3 2 | 7 5 48 |
------------------------------------------
| 37 9 23 | 4 278 78 | 5 1 6 |
| 17 6 34 | 17 9 5 | 3 248 48 |
| 8 14 5 | 12 6 3 | 9 24 7 |
+----------------------------------------+ |
You can use a generalised XY-wing with pivot r78c1. These two cells must contain 1 or 3, just like a bivalent cell (13). The pincers r5c1 and r9c2 then eliminate 4 from r56c2.
Steve |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Apr 05, 2008 1:27 pm Post subject: |
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Really?
It seems correct, but I do not recall seeing this before!
In Steve's grid there is a skyscraper that takes out <4> in R8C9, but that does not solve the puzzle. It gets you here:
Code: | +----------------+----------------+----------------+
| 2 7 8 | 3 4 9 | 1 6 5 |
| 1349 134 346 | 5 28 68 | 48 7 29 |
| 49 5 46 | 267 278 1 | 48 3 29 |
+----------------+----------------+----------------+
| 5 2 7 | 8 1 4 | 6 9 3 |
|-34 34# 9 | 67 5 67 | 2 8 1 |
| 6 8 1 | 9 3 2 | 7 5 4 |
+----------------+----------------+----------------+
| 37# 9 23 | 4 278 78 | 5 1 6 |
| 17@ 6 24 | 17 9 5 | 3 24 8 |
| 8 14@ 5 | 12 6 3 | 9 24 7 |
+----------------+----------------+----------------+ |
Can I make this similar argument:
R8C1 and R9C2 , @, must contain one of <47>.
Either way, one of the pincer cells # is <3>, and we can take out <3> in R5C1.
(I do see that there are short chains that solve R5C12. I tried Medusa coloring, starting with R9C2, but there are not strong links for <3> or <4> in C12 that allow you to get to the <34> pair in B4.)
Keith
Last edited by keith on Sat Apr 05, 2008 5:21 pm; edited 1 time in total |
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Victor
Joined: 29 Sep 2005 Posts: 207 Location: NI
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Posted: Sat Apr 05, 2008 4:48 pm Post subject: |
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And, not as exciting as Steve's stuff, the ER based on r9 takes out the 4 in r6c2, exposing a type 4 in 34s in r2c12. Same effect as Keith's skys, I guess - still a little work to do. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Apr 05, 2008 5:11 pm Post subject: |
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Quote: | I tried Medusa coloring, starting with R9C2, but there are not strong links for <3> or <4> in C12 that allow you to get to the <34> pair in B4 |
Keith, Medusa will color the 1 in r2c2 as "A." The 1 and 3 in r2c1 and r2c3, respectively, will be colored "B." Thus the 4 in r2c2 will be "B", eliminating the 3 and exposing a 14 pair in column 2. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Apr 05, 2008 6:42 pm Post subject: |
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Marty R. wrote: | Quote: | I tried Medusa coloring, starting with R9C2, but there are not strong links for <3> or <4> in C12 that allow you to get to the <34> pair in B4 |
Keith, Medusa will color the 1 in r2c2 as "A." The 1 and 3 in r2c1 and r2c3, respectively, will be colored "B." Thus the 4 in r2c2 will be "B", eliminating the 3 and exposing a 14 pair in column 2. |
Marty,
Thanks. I did not take it that far. I confined my search to B47 in the hopes of finding a short chain like Steve did.
Keith |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Apr 06, 2008 12:11 am Post subject: |
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From that other forum:
Quote: | These turn out to be 4-link XY-chains. As Steve observed, sort of an extended XY-wing. |
Ah, but as Steve described it, a "generalized XY-Wing" has more status and, to use a word often seen here, much more elegant than an XY-Chain. |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun Apr 06, 2008 1:33 am Post subject: |
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I used multi-coloring to remove <4> from r5c8, r6c2 & r8c9. If I then use the "generalized XY-wing with pivot r78c1" noted by Steve, the puzzle is completed.
Steve, is your generalized solution a valid technique?
Ted |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sun Apr 06, 2008 2:29 am Post subject: |
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Marty R. wrote: | From that other forum:
Quote: | These turn out to be 4-link XY-chains. As Steve observed, sort of an extended XY-wing. |
Ah, but as Steve described it, a "generalized XY-Wing" has more status and, to use a word often seen here, much more elegant than an XY-Chain. |
Marty,
This is new to you?
Keith |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Apr 06, 2008 3:50 am Post subject: |
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Quote: | This is new to you? |
Yes, if you mean the generalized XY-Wing, no if you mean XY-Chains. |
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