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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun Aug 17, 2008 4:03 am Post subject: Help with a BUG-like puzzle |
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This is todays fiendish puzzle from Vanhegan.:
Code: | *-----------*
|...|6.9|8.2|
|.9.|..5|...|
|..5|..3|...|
|---+---+---|
|1..|...|6.8|
|..6|...|7..|
|2.4|...|..9|
|---+---+---|
|...|2..|1..|
|...|8..|.7.|
|3.7|1.6|...|
*-----------* |
Basics get me to this point where I get confused (which is not unusual).
Code: |
*-----------------------------------------------------------*
| 7 4 3 | 6 1 9 | 8 5 2 |
| 68 9 12 | 47 28 5 | 34 36 17 |
| 68 12 5 | 47 28 3 | 49 69 17 |
|-------------------+-------------------+-------------------|
| 1 3 9 | 5 7 2 | 6 4 8 |
| 5 8 6 | 9 4 1 | 7 2 3 |
| 2 7 4 | 3 6 8 | 5 1 9 |
|-------------------+-------------------+-------------------|
| 4 56 8 | 2 39 7 | 1 39 56 |
| 9 1256 12 | 8 35 4 | 23 7 56 |
| 3 25 7 | 1 59 6 | 29 8 4 |
*-----------------------------------------------------------* |
All cells are bivalue except for r8c2 which has four candidates, not the normal three we (I) associate with a normal BUG situation. In fact, we have three <5>s in box 7, row 8 and column 2 but all in column 2 are restricted to box 7. On the other hand, the <2>s candidate meets all the normal criteria for a BUG. I tried both the <2> and the <5> and thereby know the correct answer, but I don't have a valid explanation.
Would someone please turn on the light!
Ted |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun Aug 17, 2008 4:19 am Post subject: |
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That is very interesting. I've never seen a BUG+2 with both extra digits in the same cell.
If you remove <2> and <5> from r8c2 a BUG results. So, we know that cell must be <2> or <5>.
However, also look at r78c29: this is a Type 1 UR and r8c2 cannot be <5> or <6>.
Between these two constraints, r8c2 must be 2. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun Aug 17, 2008 5:18 am Post subject: |
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Just looking at it in a slightly different way, after the UR, the 12 pair in c2 should finish it off.
From a terminology standpoint, isn't that a BUG+1 with the +1 having four rather than the usual three candidates? I've seen BUG+2 (BUG+3) used when there are two (three) non-bivalue cells. |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun Aug 17, 2008 3:34 pm Post subject: |
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Asellus wrote: |
However, also look at r78c29: this is a Type 1 UR and r8c2 cannot be <5> or <6>. |
Asellus, I was so focused on the BUG that I failed to notice the UR.
In this case the UR deleted one of the extra candidates, but what if that was not possible. As I previously noted, I tried setting r8c2 to both <2> and <5> and found that only the <2> provided a valid solution. Is this T & E the only option if another deletion is not available?
Ted |
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ravel
Joined: 21 Apr 2006 Posts: 536
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Posted: Sun Aug 17, 2008 6:49 pm Post subject: |
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Marty R. wrote: | From a terminology standpoint, isn't that a BUG+1 with the +1 having four rather than the usual three candidates? I've seen BUG+2 (BUG+3) used when there are two (three) non-bivalue cells. | I have seen both interpretations of the n in BUG+n, number of extra candidates beyond bivalue cells and number of cells with more than 2 candidates. Not the first terminology problem ...
tlanglet wrote: | As I previously noted, I tried setting r8c2 to both <2> and <5> and found that only the <2> provided a valid solution. Is this T & E the only option if another deletion is not available? | I dont talk again about T&E Its a contradiction chain, but with the UR available, a less elegant way to solve it. |
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Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
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Posted: Sun Aug 17, 2008 11:20 pm Post subject: |
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tanglet wrote: | Is this T & E the only option if another deletion is not available? |
Not at all. Remember: In a Deadly Pattern where the extra digit(s) is(are) confined to a single cell, you are not so much placing the extra digit as removing the potential DP digits. So here, you remove the <1> and <6> from r8c2 and are left with a 25 naked pair that solves the puzzle. No T&E involved. |
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