View previous topic :: View next topic |
Author |
Message |
ttt
Joined: 06 Dec 2008 Posts: 42 Location: vietnam
|
Posted: Sat Dec 06, 2008 9:08 am Post subject: French's forum - 292 hard |
|
|
Hi All,
I’m new , but I know some of you here - especially Adam, Danny, ravel…
Bellow puzzle from French’s forum here : #292-hard.
Code: | *-----------*
|1..|...|..2|
|.34|..1|...|
|.2.|.5.|.6.|
|---+---+---|
|..7|4..|..8|
|...|.9.|...|
|3..|..8|5..|
|---+---+---|
|.5.|.6.|.4.|
|...|7..|89.|
|4..|...|..3|
*-----------*
*-----------------------------------------------------------------------------*
| 1 6789 5689 | 3689 3478 34679 | 3479 3578 2 |
| 56789 3 4 | 2689 278 1 | 79 578 579 |
| 789 2 89 | 389 5 3479 | 13479 6 1479 |
|-------------------------+-------------------------+-------------------------|
| 2569 169 7 | 4 123 2356 | 12369 123 8 |
| 2568 1468 12568 | 12356 9 23567 | 123467 1237 1467 |
| 3 1469 1269 | 126 127 8 | 5 127 14679 |
|-------------------------+-------------------------+-------------------------|
| 2789 5 12389 | 12389 6 239 | 127 4 17 |
| 26 16 1236 | 7 1234 2345 | 8 9 156 |
| 4 16789 12689 | 12589 128 259 | 1267 1257 3 |
*-----------------------------------------------------------------------------* |
01. (hp78)r7c1/r9c2=(8)r79c3-(8=9)r3c3-(9)r79c3=(hp79)r7c1/r9c2
=> loop => r7c1#2, r9c2#16, r1c3#89, r5c3#8, r6c3#9
02. 6’s r6c3=r6c4-r2c4=r2c1 => r1c3, r45c1#6, single r1c3=5
03. 6’s r6c4=r6c3-r9c3=r9c7-r8c9=r5c9 => r5c346#6
04. (hp79=5)r2c89-(5=hp16)r8c29-(6)r8c1=96)r2c1 => r2c1#79
05. 9’s r6c9=r6c2-r1c2=r3c13 => r3c9#9
06. Present as diagram: => r5c79#7
Code: | AALS(46)r5c279
||
(46)r5c79
||
(4)r5c2-(4)r6c2=(4)r6c9—-(4=hp17)r37c9
|| |
|| -(9)r6c9=(9)r4c7-(9=7)r2c7
||
(6)r5c2--(6)r6c3=(6)r6c4-(6)r12c4=(6)r1c6--------------(7)r1c6
| | ||
| --(4)r1c6 ||
| || ||
----------(6)r5c9=(6-5)r8c9=(5)r8c6-(4)r8c6 ||
|| ||
(4)r3c6----(7)r3c6
||
(7)r5c6 |
07. Kraken column: => r2c9#9, some singles
Code: | (8)r1c2-(8)r1c8=(8-5)r2c8=(5)r2c9
||
(8-4)r5c2=(4)r6c2-(4=9)r6c9
||
(8-7)r9c2=(7)r9c7-(7=9)r2c7 |
08. (1)r3c7=(1)r3c9-(1=7)r7c9-(7=5)r2c9-(5=8)r2c8-(8=3)r1c8 => r3c7#3
09. (hp12=6)r56c3-(6)r6c4=(6-5)r4c6=(5-9)r4c1=(9)r4c2 => r4c1#1
10. (9)r4c2=(9-5)r4c1=(5)r4c6-(5)r8c6=(5-6)r8c9=(6-7)r9c7=(7)r9c2 => r9c2#9
11. Kraken cell: => r1c2#9, single r4c2=9
Code: | (9)r1c4
||
(6)r1c4-(6)r1c6=(6)r4c6-(6=9)r4c2
||
(8)r1c4-(8)r1c8=(8-5)r2c8=(5)r2c9-(5)r8c9=(5)r8c6-(5)r4c6=(5-9)r4c1=(9)r4c2 |
12. (6)r4c6=(6)r4c7-(6)r5c9=(6-5)r8c9=(5)r8c6 => r4c6#5, single r4c1=5
13. (6)r9c3=(6-7)r9c7=(7)r9c2-(7=9)r7c1 => r9c3#9, SSTS to the end
Edit: when I use "<>" to show eliminations I can't preview then I had to use " # "...
Thanks to all,
ttt |
|
Back to top |
|
|
Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
|
Posted: Sun Dec 07, 2008 1:33 am Post subject: |
|
|
ttt wrote: | when I use "<>" to show eliminations I can't preview then I had to use " # " |
Try using the "Disable HTML in this post" option. |
|
Back to top |
|
|
Asellus
Joined: 05 Jun 2007 Posts: 865 Location: Sonoma County, CA, USA
|
Posted: Sun Dec 07, 2008 2:13 am Post subject: |
|
|
Some comments on this solution that may help others not so comfortable with all of the notation.
01: This is a 123689 Sue de Coq in b7 and c3. (A naked quad results.)
02: This is a Skyscraper.
03: This can be seen as (multi)coloring. Alternately, it is a Kite in r9 and c9 (for r5c3<>6), with pincer transport from r9c3 to r6c4 (for r5c46<>6).
04: There are some typos:
(hp79=5)r2c79-(5=hp16)r8c29-(6)r8c1=(6)r2c1 => r2c1<>79
An alternate way to write the same thing:
(79)r2c1 - ALS[{79}r2c79=(5)r2c9] - ALS[(5)r8c9=(6)r8c29] - (6)r8c1=[6-(79)]r2c1; r2c1<>79
05: This is an ER (in b1 with conjugate pair in r6).
06: For me, the start of this multiply-branched AIC is clearer this way:
Code: | (4)r6c2 ...
/
(7)r5c79 - {46}r5c79=(46)r5c2 - (6)r6c3 ...
\
(6)r5c9 ... |
The remaining steps are what they are with no further comments except for a typo in 09: r4c2<>1.
After step 13, it is still a multiple step slog until the puzzle is solved.
A note on my "{}" notation: I use this to denote a set, as opposed to a group. A set is true when all of its members are true and false in all other cases. A group of digits is shown in parentheses and is false when all of its members are false and true in all other cases. |
|
Back to top |
|
|
ttt
Joined: 06 Dec 2008 Posts: 42 Location: vietnam
|
Posted: Sun Dec 07, 2008 7:16 am Post subject: |
|
|
Hi Asellus,
Thank you very much!
Asellus wrote: | 06: For me, the start of this multiply-branched AIC is clearer this way:
Code: | (4)r6c2 ...
/
(7)r5c79 - {46}r5c79=(46)r5c2 - (6)r6c3 ...
\
(6)r5c9 ... |
|
In fact, I found this step based on considering (46)r5c279 on row 5 and viewed it as AALS.
Thanks again,
ttt |
|
Back to top |
|
|
|
|
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum
|
Powered by phpBB © 2001, 2005 phpBB Group
|