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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Tue Dec 30, 2008 7:23 am Post subject: Set H Puzzle 25 |
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Code: | +-----------------------+
| . 1 9 | . . 8 | . 2 . |
| 4 6 . | . 2 . | . 9 . |
| 2 . . | . . 7 | . 4 . |
|-------+-------+-------|
| . . . | 9 . 6 | . . . |
| . 9 . | . 8 . | . . . |
| 6 . 2 | 7 . 3 | . . 9 |
|-------+-------+-------|
| . . . | . . . | 7 . 4 |
| 5 8 6 | . . . | . . . |
| . . . | . . 9 | 6 . 2 |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Wed Dec 31, 2008 12:50 am Post subject: |
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Took me five steps, UR, XY-Wing, W-Wing, multi-coloring and Remote Pairs. |
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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Wed Dec 31, 2008 8:31 am Post subject: |
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Code: | .---------------------.---------------------.---------------------.
| 37 1 9 | 4 356 8 | 35 2 67 |
| 4 6 78 | 135 2 *15 | 135 9 78 |
| 2 35 358 | 136 9 7 | 13 4 68 |
:---------------------+---------------------+---------------------:
| 8 U[3]45 135 | 9 U[1]45 6 | 2 7 *-35 |
| 137 9 1357 |*15 8 2 | 4 6 *35 |
| 6 U45 2 | 7 U45 3 | 8 1 9 |
:---------------------+---------------------+---------------------:
| 9 2 13 | 13568 1356 15 | 7 58 4 |
| 5 8 6 | 2 7 4 | 9 3 1 |
| 13 7 4 | 1358 135 9 | 6 58 2 |
'---------------------'---------------------'---------------------' |
the UR on {4,5} r46c25 says (3)r4c2 = (1)r4c5
so lets use that...
step 1...45UR[(3)r4c2 = (1)r4c5] - (1=5)r5c4 - (5)r5c9 = (5)r4c9; r4c9 <> 3
Code: | .---------------------.---------------------.---------------------.
| 37 1 9 | 4 356 8 | 35 2 67 |
| 4 6 78 |U13[5] 2 15 |U13[5] 9 78 |
| 2 *35 *58 |U13[6] 9 7 |U13 4 *68 |
:---------------------+---------------------+---------------------:
| 8 *34 *13 | 9 14 6 | 2 7 5 |
| 17 9 57 | 15 8 2 | 4 6 3 |
| 6 45 2 | 7 45 3 | 8 1 9 |
:---------------------+---------------------+---------------------:
| 9 2 *13 | 13568 1356 -15 | 7 58 4 |
| 5 8 6 | 2 7 4 | 9 3 1 |
| 13 7 4 | 1358 135 9 | 6 58 2 |
'---------------------'---------------------'---------------------' |
the 13UR in r23c47 says that if 6 is not in r3c4 then the 5's have to exist in r2c47... 13UR[(6)r3c4 = (5)r2c47]...and vice versa...
huge chain can be formed from this to eliminate 1 from r7c7
step2...(1=3)r7c3 - (3)r4c3 = (3)r4c2 - (3=5)r3c2 - (5=8)r3c3 - (8=6)r3c9 - 13UR[(6)r3c4 = (5)r2c47] - (5=1)r2c6; r7c6 <> 1
obviously this is overkill.
brings this bug+3 grid
Code: | .---------------.---------------.---------------.
| 37 1 9 | 4 356 8 | 35 2 67 |
| 4 6 78 | 35 2 1 | 35 9 78 |
| 2 35 58 | 36 9 7 | 1 4 68 |
:---------------+---------------+---------------:
| 8 34 13 | 9 14 6 | 2 7 5 |
| 17 9 57 | 15 8 2 | 4 6 3 |
| 6 45 2 | 7 45 3 | 8 1 9 |
:---------------+---------------+---------------:
| 9 2 13 | 136 136 5 | 7 8 4 |
| 5 8 6 | 2 7 4 | 9 3 1 |
| 13 7 4 | 8 13 9 | 6 5 2 |
'---------------'---------------'---------------' |
but coloring on 1's does the trick eliminates the 1 from r4c5.
step3...(1)......r4c3 = r7c3 - r9c1 = r9c5; r4c5 <> 1 |
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