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BB, 1-1-09

 
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Sun Jun 21, 2009 12:40 am    Post subject: BB, 1-1-09 Reply with quote
Just curious to see some solutions if anyone's interested in doing it. It would be embarrassing to tell how many moves it took me, all of them ordinary, except for an extremely rare (for me) jellyfish.

Code:

+-------+-------+-------+
| . . . | . 3 . | . . . |
| . 2 7 | 6 . 5 | 9 3 . |
| . 5 . | 1 . 2 | . 8 . |
+-------+-------+-------+
| . 4 8 | 3 . 6 | 1 2 . |
| 3 . . | . . . | . . 8 |
| . 9 1 | 4 . 8 | 3 6 . |
+-------+-------+-------+
| . 3 . | 8 . 7 | . 9 . |
| . 1 2 | 9 . 3 | 8 5 . |
| . . . | . 2 . | . . . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Sun Jun 21, 2009 2:18 am    Post subject: Reply with quote
I needed three steps:
Quote:
x-wing 7
w-wing 47
x-wing 4
Nice puzzle Very Happy
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Sun Jun 21, 2009 3:25 am    Post subject: Reply with quote
Quote:
I needed three steps:

Thanks, that was about 1/3 of mine. Embarassed
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
PostPosted: Sun Jun 21, 2009 4:31 am    Post subject: Reply with quote
Marty,

You are aware that BB publishes not only the solution, but their explanation of the path to get there?

Keith
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Sun Jun 21, 2009 4:44 am    Post subject: Reply with quote
keith wrote:
Marty,

You are aware that BB publishes not only the solution, but their explanation of the path to get there?

Keith

Actually, Keith, I wasn't aware of that. I never clicked on the "Show answer."

Thanks.
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Sun Jun 21, 2009 2:36 pm    Post subject: Reply with quote
Cool

Thanks Keith
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Sun Jun 21, 2009 2:40 pm    Post subject: Reply with quote
Another three step solution is;
Quote:
Kraken x-wing 4 in r28c19 with fin in r8c5 deletes r1c1, r7c9, r79c1,
x-wing 7 r59c28,
xy-wing 457 with pivot 57 in r6c9.

Ted
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storm_norm



Joined: 18 Oct 2007
Posts: 1741
PostPosted: Sun Jun 21, 2009 9:52 pm    Post subject: Reply with quote
Code:
.---------------------.---------------------.---------------------.
| 14689  68     469   | 7      3     *49    | 25    *14     25    |
| 14     2      7     | 6      8      5     | 9      3      14    |
| 49     5      3     | 1      49     2     | 67     8      67    |
:---------------------+---------------------+---------------------:
| 57     4      8     | 3      57     6     | 1      2      9     |
| 3      67     56    | 2      19    *19    | 457    47     8     |
| 2      9      1     | 4      57     8     | 3      6      57    |
:---------------------+---------------------+---------------------:
| 456    3      456   | 8      146    7     | 246    9      1246  |
| 467    1      2     | 9      46     3     | 8      5      467   |
| 46789  678    469   | 5      2     *14    | 467   *147    3     |
'---------------------'---------------------'---------------------'

two stepper,
mixed w-wing strong link on 1 in row 9 connects {1,9}r5c6 and {1,4}r1c8,
so now the 9 and the 4 must be true. extend the 9 up to{4,9}r1c6, now the (4)r1c6 is true or the (4)r1c8 is true.
this eliminates the 4's in r1c13

after the dust settles the xy-wing {4,5,7} solves it, eliminates the 4 from r7c7

-----

just one note on the mixed w-wing since there seems to be a desire for some explanation of terms.

the normal w-wing connects two identical bi-value cells via a strong link on one of the values.
(B=A) - A = A - (A=B); the B's become pincers.

the "mixed w-wing" substitues one of the end B candidates with another candidate I will call C.
(B=A) - A = A - (A=C)
at this point, you can see that either B is true or C is true.
If a bi-value cell {BC} exists that see's the {AC} cell, then by extension the B's would again become pincers.
(B=A) - A = A - (A=C) - (C=B); B's are pincers.

Code:
w-wing;        (B=A) - A = A - (A=B);         B's are pincers

"mixed w-wing" (B=A) - A = A - (A=C) - (C=B); B's are pincers

the example    (4=1) - 1 = 1 - (1=9) - (9=4); 4's are pincers


I wouldn't claim that this type of mixed w-wing is very common but I have noticed Marty and Asellus impliment the logic in previously posted puzzles.
The key is recognizing which candidates can be true once the relationship is made between the bi-value cells and the strongly linked candidates.
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