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Earl
Joined: 30 May 2007
Posts: 677
Location: Victoria, KS
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 Posted: Sat Oct 03, 2009 2:04 pm Post subject: Oct 3 DB |
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The October 3 DB is colorful and complex. Is there a single simple step?
A Solution: coloring in 9's, but a bit tricky
Earl
| Code: |
+-------+-------+-------+
| . . . | 4 . . | . 3 . |
| . . 8 | . . . | 6 7 . |
| . . . | 7 2 . | 8 . . |
+-------+-------+-------+
| . . 7 | . 8 . | 3 . 5 |
| . . . | . . . | . . . |
| 1 . 4 | . 5 . | 2 . . |
+-------+-------+-------+
| . . 5 | . 6 4 | . . . |
| . 2 1 | . . . | 9 . . |
| . 8 . | . . 5 | . . . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Sat Oct 03, 2009 4:47 pm Post subject: |
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specially if you can't color  | Code: | *-----------------------------------------------------------*
| 67 67 29 | 4 19 8 | 5 3 12 |
| 29 14 8 | 5 3 19 | 6 7 124 |
| 5 14 3 | 7 2 6 | 8 19 149 |
|-------------------+-------------------+-------------------|
| 269 69 7 | 19 8 129 | 3 4 5 |
| 8 5 29 | 3 4 279 | 17 6 179 |
| 1 3 4 | 6 5 79 | 2 89 789 |
|-------------------+-------------------+-------------------|
| 379 79 5 | 12 6 4 | 17 128 1378 |
| 4 2 1 | 8 7 3 | 9 5 6 |
| 37 8 6 | 129 19 5 | 4 12 37 |
*-----------------------------------------------------------*
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| Quote: | | (9)r5c3=(9)r1c3-(9=1)r1c5-(1)r2c6=(1-2)r4c6=(2)r5c6-(2)r5c3 => r5c3=9 |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Sat Oct 03, 2009 9:18 pm Post subject: |
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In Dan's grid there are three UR's, but they do not solve it. 
Keith |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Oct 04, 2009 1:10 am Post subject: |
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| I can always turn a one-stepper into a five. I used three URs, an XY-Wing with pincer transport and finished with Remote Pairs. |
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ttt
Joined: 06 Dec 2008
Posts: 42
Location: vietnam
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| Posted: Sun Oct 04, 2009 8:25 am Post subject: |
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| keith wrote: | | In Dan's grid there are three UR's, but they do not solve it. |
| Code: | *-----------------------------------------------------------*
| 67 67 29 | 4 19 8 | 5 3 12 |
| 29 14 8 | 5 3 19 | 6 7 124 |
| 5 14 3 | 7 2 6 | 8 #19 149 |
|-------------------+-------------------+-------------------|
| 269 69 7 |#19 8 129 | 3 4 5 |
| 8 5 29 | 3 4 279 | 17 6 179 |
| 1 3 4 | 6 5 79 | 2 89 789 |
|-------------------+-------------------+-------------------|
| 379 79 5 |*12 6 4 | 17 *128 1378 |
| 4 2 1 | 8 7 3 | 9 5 6 |
| 37 8 6 |*129 19 5 | 4 *12 37 |
*-----------------------------------------------------------* |
Perhaps, this one can: AUR(12)r79c48 => at least one of [(1)r4c4, (1)r3c8] must be true
(1)r4c4=(1)r3c8-(1=2)r1c9-(2)r1c3=(2)r2c1-(2=69)r4c12 => r4c4<>9
ttt |
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Steve R
Joined: 24 Oct 2005
Posts: 289
Location: Birmingham, England
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| Posted: Sun Oct 04, 2009 3:22 pm Post subject: |
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The puzzle can also be solved using the swordfish for 9 in rows 2, 4 and 7:
| Code: | *-----------------------------------------------------------*
| 67 67 29 | 4 19 8 | 5 3 12 |
| F29 14 8 | 5 3 F19 | 6 7 124 |
| 5 14 3 | 7 2 6 | 8 19 149 |
|------------------+---------------------+------------------|
| F269 F69 7 | fin19 8 F129 | 3 4 5 |
| 8 5 29 | 3 4 279 | 17 6 179 |
| 1 3 4 | 6 5 79 | 2 89 789 |
|------------------+--------------------+-------------------|
| F379 F79 5 | 12 6 4 | 17 128 1378 |
| 4 2 1 | 8 7 3 | 9 5 6 |
| 37 8 6 | 129 19 5 | 4 12 37 |
*-----------------------------------------------------------* |
It eliminates 9 from r56c6.
Put more simply:
r56c6 contains 9 => three 9s must be placed in columns 1 and 2.
Steve |
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