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telflonmail Guest
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Posted: Thu Jan 19, 2006 11:00 pm Post subject: 19-Jan-2006 has 2 answers |
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Hi,
I have done the 19-Jan-2006, [the very hard ] and have found it has 2 correct solutions. This was my last move - where the 5 and 7 could be interchanged and everything would be correct.
5 x x x x 7 x x x
x x x x x x x x x
7 x x x x 5 x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
The 5 and the 7 could be interchanged cleanly to meet suduko. So, which on is the more correct version (or are both) :-)
So, the top left, top middle could be:
5 9 4 1 6 7
3 1 6 2 8 4
7 8 2 3 9 5
or:
7 9 4 1 6 5
3 1 6 2 8 4
5 8 2 3 9 7
I hope I didn't give away too much - this one was pretty straight forward, as long you worked the definite singles first before keeping score of the doubles and triples and eliminate as you go along. |
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David Bryant
Joined: 29 Jul 2005 Posts: 559 Location: Denver, Colorado
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Posted: Thu Jan 19, 2006 11:54 pm Post subject: Does it have 3 solutions? |
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telflonmail wrote: | (for thetop left & center 3x3 boxes)
Code: | 5 9 4 1 6 7
3 1 6 2 8 4
7 8 2 3 9 5
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Huh. That's odd. I worked this one out, too, and this is what I have in that part of the puzzle.
Code: | 5 9 4 6 1 7
3 1 6 2 8 4
7 8 2 5 9 3 |
As you can see, the {5, 7} non-unique rectangle doesn't appear in the solution I found.
Might there possibly be three solutions? Please post your complete solution, and let's compare it with the one Samgj posts in the archives. dcb |
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geoff h
Joined: 07 Aug 2005 Posts: 58 Location: Sydney
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Posted: Fri Jan 20, 2006 7:31 am Post subject: |
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Hi there,
Well, I think I have to concur with David on this one - unfortunately it appears that both of telflonmail's solutions are incorrect and that David's solution is the one true solution.
Here's what I had after 34 moves :
5,7 9 4 1,5,6 1,7 5,7 3 2 8
3 1 6 2 8 4 9 7 5
5,7 8 2 3,5 9 3,5,7 4 1 6
8 6 3 9 5 1 7 4 2
2 7 9 3,8 4 3,8 5 6 1
1 4 5 7 2 6 8 9 3
4 2 1,8 1,5,8 3 7,9 6 5,8 7,9
6 3 1,8 4 1,7 5,7,8,9 2 5,8 7,9
9 5 7 8 6 2 1 3 4
Therefore, when considering Row 1, you can see a pair of 5,7 in r1c1 and r1c6. This means you MUST place Nr 1 in r1c5 and then Nr 6 in r1c4. The puzzle is easily solved from there and the first two boxes then read as follows;
5 9 4 6 1 7
3 1 6 2 8 4
7 8 2 5 9 3
Which is what David came up with.
Cheers,
Geoff |
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telflonmail Guest
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Posted: Wed Feb 01, 2006 9:34 pm Post subject: |
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my bad!
I transcribed two of the givens to the wrong cell when making a larger grid. So kindly ignore above ramble.
Cannot beat a computer generated sudoku |
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jia Guest
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Posted: Thu Feb 09, 2006 9:11 am Post subject: |
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just one solution |
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