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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Thu Mar 11, 2010 10:04 am Post subject: An interesting Menneske |
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Code: | Puzzle: M6573410sh(13)
+-------+-------+-------+
| . 1 . | 4 2 8 | . . . |
| 7 . . | . 3 . | . . . |
| . 4 . | 7 . 5 | . . . |
+-------+-------+-------+
| 6 . 4 | . . . | 2 . 1 |
| 8 7 . | . . . | . 6 9 |
| 1 . 5 | . . . | 7 . 4 |
+-------+-------+-------+
| . . . | 9 . 6 | . . . |
| . . . | . 1 . | 5 . 6 |
| . . . | 2 7 4 | . 3 . |
+-------+-------+-------+ | Keith |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu Mar 11, 2010 1:48 pm Post subject: |
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I found some uncommon moves. Great Fun!
ALS A 1479 in r138c8
ALS B 149 in r79c7
shared exclusive = 9
shared common = 1 & 4 (which I guess is unusual)
r3c7<>1 & r7c8<>4
My understanding of MUGs is very shaky, but ......
Code: | *--------------------------------------------------*
| 359 1 #369 | 4 2 8 |#69 79 57 |
| 7 56 #68 | 1 3 9 |#468 24 25 |
| 2 4 #89 | 7 6 5 |#89 1 3 |
|----------------+----------------+----------------|
| 6 9 4 | 3 8 7 | 2 5 1 |
| 8 7 2 | 5 4 1 | 3 6 9 |
| 1 3 5 | 6 9 2 | 7 8 4 |
|----------------+----------------+----------------|
| 34 8 13 | 9 5 6 | 14 27 27 |
| 49 2 7 | 8 1 3 | 5 49 6 |
| 59 56 169 | 2 7 4 | 19 3 8 |
*--------------------------------------------------* |
MUG 689 in r123c37 marked #. To prevent the deadly pattern, either r1c3=3 or r2c7=4
(3-6)r1c3 = (6)r1c7
(4-6)r2c7 = (6)r1c7
Thus r1c7=6 under both constraints.
This results in a BUG+2 pattern that sets r1c1=9 & r9c3=9. These two pincers delete 9 in r13c3 and r89c1 to complete the puzzle.
Ted |
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arkietech
Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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Posted: Thu Mar 11, 2010 2:30 pm Post subject: |
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There are several AIC or xy-chains that will solve this one in a single step. Here is one: Code: | *-----------------------------------------------------------*
| 39-5 1 369 | 4 2 8 | 69 b79 a57 |
| 7 g56 68 | 1 3 9 | 468 24 2-5 |
| 2 4 89 | 7 6 5 | 189 19 3 |
|-------------------+-------------------+-------------------|
| 6 9 4 | 3 8 7 | 2 5 1 |
| 8 7 2 | 5 4 1 | 3 6 9 |
| 1 3 5 | 6 9 2 | 7 8 4 |
|-------------------+-------------------+-------------------|
| 34 8 137 | 9 5 6 | 14 1247 27 |
| 49 2 79 | 8 1 3 | 5 c479 6 |
|e59 f56 169 | 2 7 4 |d19 3 8 |
*-----------------------------------------------------------*
(5=7)r1c9 - (7=9)r1c8 - r8c8 = r9c7 - (9=5)r9c1 - r9c2 = (5)r2c2;
r1c1,r2c9<>5 |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu Mar 11, 2010 2:44 pm Post subject: |
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A one step solution.
Code: | *-----------------------------------------------------------*
| 359 1 369 | 4 2 8 | 69 79 57 |
| 7 5-6 #68 | 1 3 9 |#468 24 25 |
| 2 4 89 | 7 6 5 | 189 19 3 |
|-------------------+-------------------+-------------------|
| 6 9 4 | 3 8 7 | 2 5 1 |
| 8 7 2 | 5 4 1 | 3 6 9 |
| 1 3 5 | 6 9 2 | 7 8 4 |
|-------------------+-------------------+-------------------|
| 34 8 137 | 9 5 6 | 14 1247 27 |
| 49 2 79 | 8 1 3 | 5 479 6 |
| 59 56 169 | 2 7 4 | 19 3 8 |
*-----------------------------------------------------------*
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Note the two cells r2c37 marked #. Together they form an ALS, but they can also be viewed as an "almost" pair 68 with an extra digit 4 in r2c7. This arrangement has also been called a "hidden" pair. (How about the term "finned" pair?)
When viewed in this manner, either the 68 pair is true or r2c7=4 is true.
If the 68 pair is true, then r2c2<>6,
If r2c7=4 is true, then: (4)r2c7 - (4=1)r7c7 - (1=9)r9c7 - (9=5)r9c1 - (5=6)r9c2; r2c2<>6
Thus, both conditions result in r2c2<>6 to complete the puzzle.
Ted |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Thu Mar 11, 2010 8:25 pm Post subject: |
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I played the 79 W-Wing, then finished with an XY-Chain very similar to Dan's which made the same elimination in r1c1. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Thu Mar 11, 2010 8:55 pm Post subject: |
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W-wing variants.
After basics: Code: | +----------------+----------------+----------------+
| 359 1 369 | 4 2 8 | 69 79a 57 |
| 7 56 68 | 1 3 9 | 468 24 25 |
| 2 4 89 | 7 6 5 | 189 19 3 |
+----------------+----------------+----------------+
| 6 9 4 | 3 8 7 | 2 5 1 |
| 8 7 2 | 5 4 1 | 3 6 9 |
| 1 3 5 | 6 9 2 | 7 8 4 |
+----------------+----------------+----------------+
| 34 8 137 | 9 5 6 | 14 1247 27 |
| 49 2 79b | 8 1 3 | 5 4-79 6 |
| 59 56 169 | 2 7 4 | 19 3 8 |
+----------------+----------------+----------------+ | 9 in a forces 7 in b, and 9 in b forces 7 in a. Taking out 7 in R8C8. Code: | +-------------+-------------+-------------+
|3-59 1 369 | 4 2 8 | 69 79a 57b |
| 7 56 68 | 1 3 9 | 468 24 25 |
| 2 4 89 | 7 6 5 | 89 1 3 |
+-------------+-------------+-------------+
| 6 9 4 | 3 8 7 | 2 5 1 |
| 8 7 2 | 5 4 1 | 3 6 9 |
| 1 3 5 | 6 9 2 | 7 8 4 |
+-------------+-------------+-------------+
| 34 8 13 | 9 5 6 | 14 27 27 |
| 49@ 2 7 | 8 1 3 | 5 49@ 6 |
| 59c 56 169 | 2 7 4 | 19 3 8 |
+-------------+-------------+-------------+ | ab are a pseudocell 59 forming a W-wing with c, taking out 5 in R1C1.
Keith |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu Mar 11, 2010 11:57 pm Post subject: |
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keith wrote: | W-wing variants.
After basics: Code: | +-------------+-------------+-------------+
|3-59 1 369 | 4 2 8 | 69 79a 57b |
| 7 56 68 | 1 3 9 | 468 24 25 |
| 2 4 89 | 7 6 5 | 89 1 3 |
+-------------+-------------+-------------+
| 6 9 4 | 3 8 7 | 2 5 1 |
| 8 7 2 | 5 4 1 | 3 6 9 |
| 1 3 5 | 6 9 2 | 7 8 4 |
+-------------+-------------+-------------+
| 34 8 13 | 9 5 6 | 14 27 27 |
| 49@ 2 7 | 8 1 3 | 5 49@ 6 |
| 59c 56 169 | 2 7 4 | 19 3 8 |
+-------------+-------------+-------------+ | ab are a pseudocell 59 forming a W-wing with c, taking out 5 in R1C1.
Keith |
Pseudocells to the rescue! Cool move Keith!
Ted |
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