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Free Press Mar 12, 2010

 
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Sat Mar 13, 2010 6:13 pm    Post subject: Free Press Mar 12, 2010 Reply with quote

Not yet done.
Code:
Puzzle: FP031210
+-------+-------+-------+
| . . . | 7 . 8 | . . . |
| 6 . . | . . . | 1 . 3 |
| . 4 . | . 5 . | . 2 . |
+-------+-------+-------+
| . . 5 | . 2 1 | . 7 . |
| 7 . . | . . . | . . 9 |
| . . . | 4 8 . | 5 . . |
+-------+-------+-------+
| . 3 . | . . . | . 9 . |
| 2 . 9 | . 6 . | . . 7 |
| . . . | 8 . 2 | . . . |
+-------+-------+-------+
Keith
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nataraj



Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria

PostPosted: Sat Mar 13, 2010 7:03 pm    Post subject: Reply with quote

After skyscraper/kite in (6), this is where I found a potential DP:

Code:

+--------------------------+--------------------------+--------------------------+
| 35      25      23       | 7       1       8        | 9       46      46       |
| 6       78      78       | 2       4       9        | 1       5       3        |
| 9       4       1        | 36      5       36       | 7       2       8        |
+--------------------------+--------------------------+--------------------------+
| 348     68      5        | 9       2       1        | 348     7       46       |
| 7       128     248      | 56      3       56       | 248     148     9        |
| 13      9       236      | 4       8       7        | 5       136     12       |
+--------------------------+--------------------------+--------------------------+
| 1458    3       468      | 15      7       45       | 2468    9       125      |
| 2       158     9        | 135     6       345      | 48      148     7        |
| 145     1567    467      | 8       9       2        | 346     134     15       |
+--------------------------+--------------------------+--------------------------+

36-65-53 in cols 4 and 6

To prevent the DP, r8c46 must be 1 or 4 . Together with r8c78 this pseudocell forms a triple 148, which sets r8c2=5.

I also needed an m-wing later on - (2) r6c3=r5c7 using a SL in (6) in row 7: r6c9 and r5c3 cannot be "2".
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Sat Mar 13, 2010 7:26 pm    Post subject: Reply with quote

Nataraj,

Nice DP!

Keith
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Sat Mar 13, 2010 8:34 pm    Post subject: Reply with quote

A one stepper
Code:
 *-----------------------------------------------------------*
 | 35    25    23    | 7     1     8     | 9     46    46    |
 | 6     78    78    | 2     4     9     | 1     5     3     |
 | 9     4     1     | 36    5     36    | 7     2     8     |
 |-------------------+-------------------+-------------------|
 | 348   68    5     | 9     2     1     | 3468  7     46    |
 | 7     128   248   | 56    3     56    | 248   148   9     |
 | 13    9     236   | 4     8     7     | 5     136   12    |
 |-------------------+-------------------+-------------------|
 | 1458  3     468   | 15    7     45    | 2468  9     125   |
 | 2     158   9     | 135   6     345   | 48    148   7     |
 | 145   1567  467   | 8     9     2     | 346   1346  15    |
 *-----------------------------------------------------------*
(6)r4c2=r9c2-r7c3=(6-2)r7c7=r7c9-r6c9=(2-6)r6c3=(6)r6c8;
r4c79,r6c3<>6
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Sat Mar 13, 2010 9:21 pm    Post subject: Reply with quote

Quote:
To prevent the DP, r8c46 must be 1 or 4 . Together with r8c78 this pseudocell forms a triple 148, which sets r8c2=5


of course this is excellent logic.

on the other side of the logic fence we have this way of looking at it.



notice how the 3's and the 6's are in a perfect x-wing.
this means that there exists no other 3's or 6's in the rows of the DP cells.

taking a look at the 5's, this isn't the case.
in row three we see that there is only two 5's, the DP 5's.
in row eight we see that there are three 5's. the DP 5's and a external 5 in r8c2.
the 5 in r8c2 has to be placed in order to avoid the DP. this is because if that 5 were eliminated then the DP would exist.

of course this does exactly the same thing as nataraj's logic tells us, but may come in handy if a locked set cannot be formed, or if some strong inference is useful in a chain.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sat Mar 13, 2010 10:21 pm    Post subject: Reply with quote

Excellent observation Norm.
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Sun Mar 14, 2010 3:54 pm    Post subject: Reply with quote

Nataraj, I also started with the DP 356, but missed the subset 148. Instead, I extended the 1 & 4 to delete 5 in r79c1 forcing r1c1=5. Not nearly as useful as yours.

I also looked at the 6-cell DP 46 in r149c789 but could not work out any deletions.

Ted
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nataraj



Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria

PostPosted: Sun Mar 14, 2010 4:05 pm    Post subject: Reply with quote

storm_norm wrote:
may come in handy if a locked set cannot be formed, or if some strong inference is useful in a chain.


I like that logic. It is similar to the "type 3" unique rectangles.
Indeed, I seem to find more puzzles where the UR is either type 3 or has other strong links than those with any useful pseudocells...
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