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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Tue Apr 13, 2010 8:40 pm Post subject: Puzzle 10/04/13 ___ BBDB |
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Code: | +-----------------------+
| . . . | . . . | 2 . . |
| . 1 . | 7 . 6 | . . . |
| . . 9 | . 2 . | 3 7 . |
|-------+-------+-------|
| . 9 . | . . . | 5 . . |
| . . 1 | . 5 . | . 3 . |
| . 3 . | . . 9 | . . 7 |
|-------+-------+-------|
| 1 . 2 | 6 . . | 8 . 3 |
| . . 5 | . 3 . | . 1 2 |
| . . . | . . 2 | 6 9 . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Wed Apr 14, 2010 7:46 am Post subject: |
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Quote: | Two steps for this toughie:
1)A powerful UR at r58c46 which starts the damage by showing that r5c6 must be 7.
2)Another x chain/colouring idea on 4s which shows up a contradiction.
(8=4)r3c2-r3c6=r12c5-r6c5=r6c3-r9c3=r9c2-(4)r3c2 so r3c2 <>4
If you prefer to see this diagrammatically there is a tinypic url below.
Let green = "is 4" and orange = "not 4" this puts two 4s in column 2 so therefore r3c2 <> 4. Puzzle implodes.
http://i44.tinypic.com/34qwfoz.png
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Last edited by Mogulmeister on Wed Apr 14, 2010 8:58 am; edited 1 time in total |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Wed Apr 14, 2010 8:08 am Post subject: |
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Took me a bunch of moves! Lots of variety..
Quote: | Type 1 UR(48); r5c6=7
Kite(8); r6c5<>8
x-wing(6); r14c19<>6
xy-wing(468); r4c56<>4
Multi-colour wrap(4); r3c2<>4, r9c3<>4 |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Wed Apr 14, 2010 4:00 pm Post subject: |
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type 1 UR48 in r58c46 forces r5c6=7,
Looking at the 4s in column 6 we see that r3c6=4 or r48c6=4
(4)r48c6 = (4)r3c6
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(4)r4c6 - r6c5 = r6c3 - r9c3 = (4)r9c2; r3c2<>4
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(4)r8c6 - r8c4 = r5c4 - r6c5 = r6c3 - r9c3 = (4)r9c2; r3c2<>4
Thus r3c2<>4 to complete the puzzle.
Ted |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Wed Apr 14, 2010 4:03 pm Post subject: |
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Yep same as mine. |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Wed Apr 14, 2010 4:04 pm Post subject: |
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Mogulmeister wrote: | Quote: | Two steps for this toughie:
1)A powerful UR at r58c46 which starts the damage by showing that r5c6 must be 7.
2)Another x chain/colouring idea on 4s which shows up a contradiction.
(8=4)r3c2-r3c6=r12c5-r6c5=r6c3-r9c3=r9c2-(4)r3c2 so r3c2 <>4
If you prefer to see this diagrammatically there is a tinypic url below.
Let green = "is 4" and orange = "not 4" this puts two 4s in column 2 so therefore r3c2 <> 4. Puzzle implodes.
http://i44.tinypic.com/34qwfoz.png
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I did not read your post until after I posted my own solution. We had the same path essentially, but yours is definitely cleaner; good solution
Ted |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Wed Apr 14, 2010 5:05 pm Post subject: |
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Hi Ted
I didn't mean it that way....I was trying to say that obviously a lot of the good stuff you and Norm are doing is rubbing off if we're converging on the similar solutions !
Last edited by Mogulmeister on Wed Apr 14, 2010 7:53 pm; edited 1 time in total |
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Luke451
Joined: 20 Apr 2008 Posts: 310 Location: Southern Northern California
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Posted: Wed Apr 14, 2010 6:08 pm Post subject: |
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There is a subtle difference, not that important to me, but a big issue to some.
Ted's net requires the interaction of three assumptions:
-if r3c6 is (4) then r3c2 cannot be (4)
-if r4c6 is (4) then r3c2 cannot be (4)
-if r8c6 is (4) then r3c2 cannot be (4)
The AIC used by the Master of the Moguls is a series of statements, and it makes no assumptions.
Some players feel if they have a choice, it's better to not make any assumptions. |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Wed Apr 14, 2010 7:52 pm Post subject: |
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Luke, the a priori argument if I'm not mistaken ? |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu Apr 15, 2010 2:14 am Post subject: |
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I agree Luke. That is why I indicated a preference for MMs solution.
Ted |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Thu Apr 15, 2010 8:20 pm Post subject: |
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I did my typical twice as many moves, using eight of them, including various types of wings, URs and ending with multi-coloring. |
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