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		| daj95376 
 
 
 Joined: 23 Aug 2008
 Posts: 3854
 
 
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				|  Posted: Tue Apr 13, 2010 8:40 pm    Post subject: Puzzle 10/04/13 ___ BBDB |   |  
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				|  	  | Code: |  	  | +-----------------------+ | . . . | . . . | 2 . . |
 | . 1 . | 7 . 6 | . . . |
 | . . 9 | . 2 . | 3 7 . |
 |-------+-------+-------|
 | . 9 . | . . . | 5 . . |
 | . . 1 | . 5 . | . 3 . |
 | . 3 . | . . 9 | . . 7 |
 |-------+-------+-------|
 | 1 . 2 | 6 . . | 8 . 3 |
 | . . 5 | . 3 . | . 1 2 |
 | . . . | . . 2 | 6 9 . |
 +-----------------------+
 
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 Play this puzzle online at the Daily Sudoku site
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		| Mogulmeister 
 
 
 Joined: 03 May 2007
 Posts: 1151
 
 
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				|  Posted: Wed Apr 14, 2010 7:46 am    Post subject: |   |  
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				|  	  | Quote: |  	  | Two steps for this toughie: 
 1)A powerful UR at r58c46 which starts the damage by showing that r5c6 must be 7.
 
 2)Another x chain/colouring idea on 4s which shows up a contradiction.
 
 (8=4)r3c2-r3c6=r12c5-r6c5=r6c3-r9c3=r9c2-(4)r3c2 so r3c2 <>4
 
 If you prefer to see this diagrammatically there is a tinypic url below.
 
 Let green = "is 4" and orange = "not 4" this puts two 4s in column 2 so therefore r3c2 <> 4. Puzzle implodes.
 
 http://i44.tinypic.com/34qwfoz.png
 
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 Last edited by Mogulmeister on Wed Apr 14, 2010 8:58 am; edited 1 time in total
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		| peterj 
 
 
 Joined: 26 Mar 2010
 Posts: 974
 Location: London, UK
 
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				|  Posted: Wed Apr 14, 2010 8:08 am    Post subject: |   |  
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				| Took me a bunch of moves! Lots of variety.. 
 
  	  | Quote: |  	  | Type 1 UR(48); r5c6=7 Kite(8); r6c5<>8
 x-wing(6); r14c19<>6
 xy-wing(468); r4c56<>4
 Multi-colour wrap(4); r3c2<>4, r9c3<>4
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Wed Apr 14, 2010 4:00 pm    Post subject: |   |  
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				| type 1 UR48 in r58c46 forces r5c6=7, 
 Looking at the 4s in column 6 we see that r3c6=4 or r48c6=4
 (4)r48c6 = (4)r3c6
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 (4)r4c6 - r6c5 = r6c3 - r9c3 = (4)r9c2; r3c2<>4
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 (4)r8c6 - r8c4 = r5c4 - r6c5 = r6c3 - r9c3 = (4)r9c2; r3c2<>4
 Thus r3c2<>4 to complete the puzzle.
 
 Ted
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		| Mogulmeister 
 
 
 Joined: 03 May 2007
 Posts: 1151
 
 
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				|  Posted: Wed Apr 14, 2010 4:03 pm    Post subject: |   |  
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				| Yep same as mine. |  | 
	
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Wed Apr 14, 2010 4:04 pm    Post subject: |   |  
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				|  	  | Mogulmeister wrote: |  	  |  	  | Quote: |  	  | Two steps for this toughie: 
 1)A powerful UR at r58c46 which starts the damage by showing that r5c6 must be 7.
 
 2)Another x chain/colouring idea on 4s which shows up a contradiction.
 
 (8=4)r3c2-r3c6=r12c5-r6c5=r6c3-r9c3=r9c2-(4)r3c2 so r3c2 <>4
 
 If you prefer to see this diagrammatically there is a tinypic url below.
 
 Let green = "is 4" and orange = "not 4" this puts two 4s in column 2 so therefore r3c2 <> 4. Puzzle implodes.
 
 http://i44.tinypic.com/34qwfoz.png
 
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 I did not read your post until after I posted my own solution. We had the same path essentially, but yours is definitely cleaner; good solution
 
 Ted
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		| Mogulmeister 
 
 
 Joined: 03 May 2007
 Posts: 1151
 
 
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				|  Posted: Wed Apr 14, 2010 5:05 pm    Post subject: |   |  
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				| Hi Ted I didn't mean it that way....I was trying to say that obviously a lot of the good stuff you and Norm are doing is rubbing off if we're converging on the similar solutions !
 
  
 Last edited by Mogulmeister on Wed Apr 14, 2010 7:53 pm; edited 1 time in total
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		| Luke451 
 
 
 Joined: 20 Apr 2008
 Posts: 310
 Location: Southern Northern California
 
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				|  Posted: Wed Apr 14, 2010 6:08 pm    Post subject: |   |  
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				| There is a subtle difference, not that important to me, but a big issue to some. 
 Ted's net requires the interaction of three assumptions:
 -if r3c6 is (4) then r3c2 cannot be (4)
 -if r4c6 is (4) then r3c2 cannot be (4)
 -if r8c6 is (4) then r3c2 cannot be (4)
 
 The AIC used by the Master of the Moguls is a series of statements, and it makes no assumptions.
 
 Some players feel if they have a choice, it's better to not make any assumptions.
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		| Mogulmeister 
 
 
 Joined: 03 May 2007
 Posts: 1151
 
 
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				|  Posted: Wed Apr 14, 2010 7:52 pm    Post subject: |   |  
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				| Luke, the a priori argument if I'm not mistaken ? |  | 
	
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Thu Apr 15, 2010 2:14 am    Post subject: |   |  
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				| I agree Luke. That is why I indicated a preference for MMs solution. 
 Ted
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Thu Apr 15, 2010 8:20 pm    Post subject: |   |  
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				| I did my typical twice as many moves, using eight of them, including various types of wings, URs and ending with multi-coloring. |  | 
	
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