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Puzzle 10/04/18 (B)

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Sun Apr 18, 2010 4:38 pm    Post subject: Puzzle 10/04/18 (B) Reply with quote

Single stepper ... and it doesn't use a chain, ALS, M-Wing, W-Wing, extension, transport, or pseudocell.

Code:
 +-----------------------+
 | 4 2 . | . . 9 | 3 8 . |
 | 3 5 . | . . 6 | 2 . . |
 | . . 8 | 4 . . | 7 . . |
 |-------+-------+-------|
 | . . 3 | 9 7 . | 5 6 . |
 | . . . | 6 . . | . . . |
 | 6 7 . | . . . | . . . |
 |-------+-------+-------|
 | 7 8 1 | 3 . . | . 5 . |
 | 5 . . | 8 . . | 1 3 . |
 | . . . | . . . | . . 8 |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Sun Apr 18, 2010 6:25 pm    Post subject: Reply with quote

One Step:
Quote:
ur 15 r9c68<>2, r9c68<>4
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Mon Apr 19, 2010 7:17 am    Post subject: Reply with quote

Sometimes I get impatient to share. That turns out to be especially true with this puzzle. Please forgive me for not waiting longer for others to post a message.

Code:
 after basics
 +--------------------------------------------------------------------------------+
 |  4       2       7       | *15     *15      9       |  3       8       6       |
 |  3       5       9       |  7       8       6       |  2       14      14      |
 |  1       6       8       |  4       23      23      |  7       9       5       |
 |--------------------------+--------------------------+--------------------------|
 |  28      14      3       |  9       7       1248    |  5       6       124     |
 |  289     149     245     |  6       12345   123458  |  48      1247    12347   |
 |  6       7       245     |  125     12345   123458  |  489     124     12349   |
 |--------------------------+--------------------------+--------------------------|
 |  7       8       1       |  3       2469    24      |  469     5       249     |
 |  5       49      246     |  8       2469    247     |  1       3       2479    |
 |  29      3       246     | *15+2   *15+2469 12457   |  469     247     8       |
 +--------------------------------------------------------------------------------+
 # 94 eliminations remain

Code:
There is the <15> UR Type 3 eliminations in [r9] for <2469> => r 9c68<>24   (Dan's)
There is the <15> UR Type 3 eliminations in [b8] for <2469> => r89c6 <>24

But, most interesting of all, is r9c6=1|5 must be true to prevent the <15> DP. This results in r9c6<>247.

All of these UR eliminations result in r8c6,r9c8=7 to crack the puzzle.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Tue Apr 20, 2010 12:50 am    Post subject: Reply with quote

Quote:
Single stepper ... and it doesn't use a chain, ALS, M-Wing, W-Wing, extension, transport, or pseudocell.

Thanks for boosting my confidence. This borders on the impossible and I can't do a thing with it. I haven't read Dan's or your comments.
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Tue Apr 20, 2010 7:56 am    Post subject: Reply with quote

Danny, very neat!

I got completely waylaid looking for giant fish in 2s - so nearly a Sashimi Jellyfish (only a single in one of the columns) and a Finned Swordfish (no eliminations)....

Found this a tough puzzle!
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Tue Apr 20, 2010 3:23 pm    Post subject: Reply with quote

This puzzle was tough because of the UR being the best way to proceed (from what my solver found). I now open it up to all of the techniques originally barred. Have fun!!!
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Tue Apr 20, 2010 4:03 pm    Post subject: Reply with quote

daj95376 wrote:
Sometimes I get impatient to share. That turns out to be especially true with this puzzle. Please forgive me for not waiting longer for others to post a message.

Code:
 after basics
 +--------------------------------------------------------------------------------+
 |  4       2       7       | *15     *15      9       |  3       8       6       |
 |  3       5       9       |  7       8       6       |  2       14      14      |
 |  1       6       8       |  4       23      23      |  7       9       5       |
 |--------------------------+--------------------------+--------------------------|
 |  28      14      3       |  9       7       1248    |  5       6       124     |
 |  289     149     245     |  6       12345   123458  |  48      1247    12347   |
 |  6       7       245     |  125     12345   123458  |  489     124     12349   |
 |--------------------------+--------------------------+--------------------------|
 |  7       8       1       |  3       2469    24      |  469     5       249     |
 |  5       49      246     |  8       2469    247     |  1       3       2479    |
 |  29      3       246     | *15+2   *15+2469 12457   |  469     247     8       |
 +--------------------------------------------------------------------------------+
 # 94 eliminations remain


But, most interesting of all, is r9c6=1|5 must be true to prevent the <15> DP. This results in r9c6<>247.

To expand on Danny's post, his statement that "r9c6=1|5" is a result of looking at the implications of the UR candidate digits on non-UR cells in the houses of the UR. Consider the following.

The two UR candidate digits are 1 & 5. We can look at the outside row, column or box implications since any one is sufficient; using row1 and row9, we find:
Digit 1: No outside 1s in row1; r9c6 has a 1 in row9.
Digit 5: No outside 5s in row1; r9c6 has a 5 in row5.
Thus to prevent the deadly pattern r9c6=1 or r9c6=5 from which we can conclude that r9c6<>247.
Also note that in this case, looking at rows or boxes provides the exact same result.

Looking at columns, the steps are slightly more involved but results in a more positive event.
Digit 1: 1s in r6c4 & r56c5
Digit 5: 5s in r6c4 & r56c5
Thus, r456c6<>1 & r56c6<>5 which makes r9c6=1, a more positive result that completes the puzzle without additional deletions.

Ted
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Tue Apr 20, 2010 4:47 pm    Post subject: Reply with quote

To capsulate Ted's observation:

The beauty of having a Locked Pair in a UR is that it automatically eliminated the row/column and box containing it from consideration. We can then focus our attention on the row/column and box containing the remaining two cells. In this grid, that's [r9] and [b8].

This is why I always resolve basics and X-Wings before searching for a UR pattern.
(UR Types 4/6 need an X-Wing pattern for one candidate.)
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Tue Apr 20, 2010 4:52 pm    Post subject: Reply with quote

daj95376 wrote:
This puzzle was tough because of the UR being the best way to proceed (from what my solver found). I now open it up to all of the techniques originally barred. Have fun!!!


I did manage without using your barred steps - but I was hoping for a monster fish pattern in 2s, instead a two step

Quote:
Finned Swordfish (2) in columns r569c348 fin at r8c3; r9c1<>2
xy-wing(248); r5c1<>8
Plenty of other finned fish in there also - including a Sashimi Finned x-wing!
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Tue Apr 20, 2010 5:06 pm    Post subject: Reply with quote

peterj wrote:
I was hoping for a monster fish pattern in 2s ...

There are four (total) fish eliminations -- r56c3,r6c9,r9c1<>2 -- that can be derived through various X-Wing/Swordfish patterns after basics. Together, they are insufficient to crack the puzzle.

BTW: I noticed your use of Tarek's "Sashimi finned" preference over RonK and my choice of "Sashimi" by itself. No, I don't want to reopen that discussion in this forum. Very Happy
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ronk



Joined: 07 May 2006
Posts: 398

PostPosted: Tue Apr 20, 2010 5:20 pm    Post subject: Reply with quote

tlanglet wrote:
Looking at columns, the steps are slightly more involved but results in a more positive event.
Digit 1: 1s in r6c4 & r56c5
Digit 5: 5s in r6c4 & r56c5
Thus, r456c6<>1 & r56c6<>5 which makes ...

As you say, at least one of r6c4=1, r56c5=1, r6c4=5 and r56c5=5 must be true. However, I don't see how your conclusions follow.
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daj95376



Joined: 23 Aug 2008
Posts: 3854

PostPosted: Tue Apr 20, 2010 5:31 pm    Post subject: Reply with quote

Welcome back ronk Exclamation

We now have another active member to keep my misconceptions and wanton rantings in check. He also does a much more thorough check of details than I.

Regards, Danny
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Tue Apr 20, 2010 6:21 pm    Post subject: Reply with quote

ronk wrote:
tlanglet wrote:
Looking at columns, the steps are slightly more involved but results in a more positive event.
Digit 1: 1s in r6c4 & r56c5
Digit 5: 5s in r6c4 & r56c5
Thus, r456c6<>1 & r56c6<>5 which makes ...

As you say, at least one of r6c4=1, r56c5=1, r6c4=5 and r56c5=5 must be true. However, I don't see how your conclusions follow.

Ronk,

I jumped to a conclusion after looking at only half the constraints: (1)r6c4|r56c5 - r456c6 = (1)r9c6

I totally forgot to deal with the 5s. Embarassed Embarassed

Ted
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