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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Sat Apr 24, 2010 4:20 pm Post subject: Puzzle 10/04/24 (B) |
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| Code: | +-----------------------+
| 8 2 9 | 6 . 3 | 1 4 . |
| 1 . . | . 4 . | 5 . . |
| 4 . . | . . . | . 3 . |
|-------+-------+-------|
| 7 . . | 4 . . | . . 6 |
| . 6 . | . . . | 3 . . |
| 2 . . | . . 9 | . . . |
|-------+-------+-------|
| 6 7 . | . 9 . | . . 2 |
| 9 . 2 | . . . | . 1 . |
| . . . | 2 . . | 9 . . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Mon Apr 26, 2010 4:48 am Post subject: |
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XYZ-Wing (258)
Type 4 UR (89)
ERs (4,1,1)
XY-Wing (158) |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Mon Apr 26, 2010 7:14 am Post subject: |
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For me a different two-step route.. involving your xyz-wing, is this valid logic?
kite(4); r7c3<>4
Consider the xyz-wing(258), r4c8=8, a short xy-chain/xy-wing (8=1)r4c3-(1=5)r7c3-(5=8)r7c8 extending the 8 results in two ways of looking at it
1) A contradiction so r4c8<>8 and so the xyz-wing disintegrates to an xy-wing allowing r7c7<>8
2) Extension of the 8 to r7c8 allowing r7c7<>8
Either way r7c7<>8, r6c8<> 8 and r4c8<>8
(Or you can do it as two xy-wings....) |
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