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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Wed May 19, 2010 6:08 pm Post subject: Puzzle 10/05/19: BBDB XY |
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Final step perfect for np() folk. Earlier steps a challenge.
Code: | +-----------------------+
| 3 7 . | . 5 8 | . 1 9 |
| 1 9 . | . . . | . . . |
| . . 5 | . . . | . . . |
|-------+-------+-------|
| . . . | 3 . 5 | . 7 2 |
| 9 . . | . 2 . | . 5 . |
| 2 . . | 7 . 4 | . . 3 |
|-------+-------+-------|
| . . . | . . . | 4 . 5 |
| 4 . . | 5 7 . | . 9 . |
| 5 . . | 2 . 3 | 7 . . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Thu May 20, 2010 2:56 pm Post subject: |
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Danny, I don't think that I met the challenge.
AUR46 r12c34 with SL4 in r1c34 & r12c4; r2c3<>6,
Flightless xyz-wing 168 in r8c9 with transport: (1)r8c9 - (1=6)r8c6 - r5c6 = r5c7 - r13c7 = r23c9; r9c9<>6
xy-wing 2-46 with vertex 26 in r1c7; r2c4<>4,
ANP(68=7)r4c19 - (7=8_r2c9; r3c7<>8
ER2 with hinge in box9 SL r1c37; r7c3<>2
(8)r3c9 - (8=6)r3c1 - r4c1 = (6-4)r4c3 = (4-8)r2c3 = (8)r2c9; r3c9<>8
BUG+1 forces r4c2=8
Ted |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Thu May 20, 2010 5:43 pm Post subject: |
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Thanks, that was a fun puzzle! For me a 'finned xy-wing' was my advanced step ... hopefully this is OK as I haven't had even a sip of burgundy (yet!)
xy-wing(246) r2c4<>4
skyscraper(2) r7c3<>2
w-wing(68) (8=6)r3c1-r1c3=r1c7-(6=8)r5c7; r3c7<>8
"finned" xy-wing(268) (26)r1c3 pincers (68)r3c1, (28=3)r8c3-(3=1)r7c3-(1=8)r6c3; r2c3<>8
BUG+1; r4c2=8 |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Thu May 20, 2010 8:35 pm Post subject: |
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Well this answer of mine is a bit of a dog's breakfast but I'd like to stick it up for discussion's sake.
1. Simple XY Wing 246 ; r2c4 <>4
2. Bifurcation along a discontinuous loop or "Bloated Baphomet"
There's a baphomet (discontinuous loop) which causes r6c3 <> 6
(18=6)r6c3-r1c3=r1c7-r5c7=r6c8-(6)r6c3 This loop shown in orange/green
BUT how about a bifurcated extension ? Follow it around again but start at r7c3 follow the same chain but when you get to the second orange cell at r5c7 instead take the strong link (pink) at r5c6 and continue the chain:
(123=6)r7c3-r1c3=r1c7-r5c7=r5c6-r8c6=r7c5-r7c3 and thus r7c3 <> 6
In effect this is either a simultaneous bifurcation or a "bloated" baphomet or you can view pincers for 6 at r1c3 r7c5 for the second elimination.
The result is r67c3<>6. I have no doubt this can be tidied up (or destroyed altogether!!)
3. XYZ wing 678 r3c7 <> 8 solves puzzle.
Last edited by Mogulmeister on Thu May 20, 2010 8:43 pm; edited 1 time in total |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Thu May 20, 2010 8:41 pm Post subject: |
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Afterthought - I wonder if Danny/Wapiti will see fish ? Ted will see something even more incredible and I will cement my reputation as "the barbarian at the gate" or worse......either way I'm off for a beer!
Cheers,
Mogul |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Thu May 20, 2010 9:45 pm Post subject: |
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Mogul
For me your move seems to be a "standard" colour trap
So here buddies of blue and orange are eliminated. I tried this but it didn't seem to help me.
I completely missed the xyz-wing - but for me this doesn't leave me with a basics-only grid? I've probably missed something in basics.
Peter |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Thu May 20, 2010 9:50 pm Post subject: |
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I started with an XY-Wing (264) and XYZ-Wing (678). I saw the Finned X-Wing (2) but didn't see much potential with it. There was a potential DP (18-89-19) in boxes 456. R4c3 needed to be 4 or 6 to kill it and either number solved box 7 the same way. |
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ronk
Joined: 07 May 2006 Posts: 398
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Posted: Thu May 20, 2010 11:08 pm Post subject: |
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peterj wrote: | For me your move seems to be a "standard" colour trap
...
So here buddies of blue and orange are eliminated. I tried this but it didn't seem to help me. |
A nice example of Multi-Coloring Type 2, as coined by Angus Johnson circa 2005. It would be interesting to know if the "trap" and "wrap" terms preceded or followed the "multi-color" term. |
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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Thu May 20, 2010 11:49 pm Post subject: |
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Code: | Puzzle 10/05/19: BBDB XY (after basics)
*--------------------------------------------------------------------*
| 3 7 246 | 46 5 8 | 26 1 9 |
| 1 9 2468 | 46 3 27 | 5 24 678 |
| 68 2468 5 | 9 1 27 | 2368 234 678 |
|----------------------+----------------------+----------------------|
| 68 1468 1468 | 3 689 5 | 19 7 2 |
| 9 3 7 | 18 2 16 | 68 5 4 |
| 2 5 168 | 7 689 4 | 19 68 3 |
|----------------------+----------------------+----------------------|
| 7 126 1236 | 18 68 9 | 4 23 5 |
| 4 1268 12368 | 5 7 16 | 23 9 168 |
| 5 168 9 | 2 4 3 | 7 68 168 |
*--------------------------------------------------------------------*
r1 b9 turbot fish/ER <> 2 r7c3
<26+4> XY-Wing r1c7/r1c4+r2c8 <> 4 r2c4 complementary
<24+6> XY-Wing r2c8/r1c7+r2c4 <> 6 r1c4,r2c9
r1 b6 turbot fish/ER <> 6 r6c3
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Code: | after Locked Candidate 1
skip: finned Franken Swordfish r15b8\c367 => r7c3<>6
*--------------------------------------------------------------------*
| 3 7 26 | 4 5 8 | 26 1 9 |
| 1 9 248 | 6 3 27 | 5 24 78 |
| 68 2468 5 | 9 1 27 | 2368 234 678 |
|----------------------+----------------------+----------------------|
| 68 1468 1468 | 3 89 5 | 19 7 2 |
| 9 3 7 | 18 2 16 | 68 5 4 |
| 2 5 18 | 7 689 4 | 19 68 3 |
|----------------------+----------------------+----------------------|
| 7 126 136 | 18 68 9 | 4 23 5 |
| 4 1268 12368 | 5 7 16 | 23 9 168 |
| 5 168 9 | 2 4 3 | 7 68 168 |
*--------------------------------------------------------------------*
<67+8> XYZ-Wing r3c9/r2c9+r3c1 <> 8 r3c7 important
r12c34 <64> UR Type 3.1123 r4c3<>18 extraneous -- for np()
necessary for XY-Chain
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Code: | leaving
+-----------------------------------------------------+
| 3 7 26 | 4 5 8 | 26 1 9 |
| 1 9 248 | 6 3 27 | 5 24 78 |
| 68 248 5 | 9 1 27 | 236 234 78 |
|-----------------+-----------------+-----------------|
| 68 148 4618 | 3 89 5 | 19 7 2 |
| 9 3 7 | 1 2 6 | 8 5 4 |
| 2 5 18 | 7 89 4 | 19 6 3 |
|-----------------+-----------------+-----------------|
| 7 12 13 | 8 6 9 | 4 23 5 |
| 4 28 238 | 5 7 1 | 23 9 6 |
| 5 6 9 | 2 4 3 | 7 8 1 |
+-----------------------------------------------------+
# 34 eliminations remain (including those of UR Type 3)
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one solution wrote: | (4=28)r38c2 - (2)r7c2 = r7c8 - (2=4)r2c8 => r2c3<>4.
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wapati
Joined: 10 Jun 2008 Posts: 472 Location: Brampton, Ontario, Canada.
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Posted: Fri May 21, 2010 3:05 am Post subject: |
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daj95376 wrote: |
Code: | leaving
+-----------------------------------------------------+
| 3 7 26 | 4 5 8 | 26 1 9 |
| 1 9 248 | 6 3 27 | 5 24 78 |
| 68 248 5 | 9 1 27 | 236 234 78 |
|-----------------+-----------------+-----------------|
| 68 148 4618 | 3 89 5 | 19 7 2 |
| 9 3 7 | 1 2 6 | 8 5 4 |
| 2 5 18 | 7 89 4 | 19 6 3 |
|-----------------+-----------------+-----------------|
| 7 12 13 | 8 6 9 | 4 23 5 |
| 4 28 238 | 5 7 1 | 23 9 6 |
| 5 6 9 | 2 4 3 | 7 8 1 |
+-----------------------------------------------------+
# 34 eliminations remain (including those of UR Type 3)
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one solution wrote: | (4=28)r38c2 - (2)r7c2 = r7c8 - (2=4)r2c8 => r2c3<>4.
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I have been trying this method but I always look for agreement.
That is I would try the NP and look for what is set in the binary cells, then try the "fin" and see what is set.
When they agree I set that value. It is working well for me on paper.
BTW, I did see a finned swordfish on twos, not of any use tho. |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Fri May 21, 2010 7:01 am Post subject: |
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Thanks guys - feedback appreciated- the pull of the pub plus a mistransposition before the XYZ wing left me with a false ending!
I liked the ANP to finish as suggested in the hint. Nice one Danny!
Ronk - I would wager that the multi-colouring term was first and the "trap" and "wrap" followed. I had an absence from the game for over a year and when I left I don't recall the colloquialisms but on returning, those terms seemed to be ubiquitous.
wapati wrote: |
I have been trying this method but I always look for agreement.
That is I would try the NP and look for what is set in the binary cells, then try the "fin" and see what is set.
When they agree I set that value. It is working well for me on paper.
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I do the same with these and have found it to be fairly sound. |
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