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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sat May 29, 2010 2:29 pm Post subject: Puzzle 10/05/29: (A) |
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Code: | +-----------------------+
| . 9 . | 1 . . | . 2 8 |
| 6 8 . | . 9 . | 5 . . |
| . . 5 | . . . | 9 . . |
|-------+-------+-------|
| 3 . . | . . . | 6 . 2 |
| . 6 . | . 7 . | 8 3 . |
| . . . | . . 9 | . . . |
|-------+-------+-------|
| . 2 6 | 3 8 . | 4 . . |
| 8 . . | . 5 . | . . 9 |
| 4 . . | 9 . . | . 8 . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Sun May 30, 2010 10:00 am Post subject: |
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Wing..
Quote: | w-wing(17) (1=7)r4c3-r9c3=r9c7-(7=1)r6c7; r6c2<>1 |
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tlanglet
Joined: 17 Oct 2007 Posts: 2468 Location: Northern California Foothills
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Posted: Sun May 30, 2010 2:16 pm Post subject: |
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The solution already posted by Peter seems to be the killer for this puzzle. For fun, I also looked for an ANP() solution.
ANP(24=7)r3c56 - (7=1)r7c6 - (1=2)r9c5 - (2=4)r3c5; r3c8<>4
ANP(14=2)r4c5|r5c6 - (2=4)r3c6 - r8c6 = (4)r8c4; r5c4<>4
ANP(12=7)r8c6|r9c5 - (7=1)r8c2 - r46c2 = r4c3 - r4c5 = (1)r6c7; r7c6<>1
Ted |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sun May 30, 2010 2:45 pm Post subject: |
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Maybe,
But it took me three XY-wings and two X-wings: XY 1-24, 1-47, X 1, 1, XY -127.
Keith |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sun May 30, 2010 10:09 pm Post subject: |
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I didn't notice a W-Wing, but an M-Wing on 17 plus pincer transport did it. |
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Wendy W
Joined: 04 Feb 2008 Posts: 144
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Posted: Mon May 31, 2010 12:13 am Post subject: |
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A la Keith. I liked those two X-wings on 1, right in a row. |
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