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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Tue Aug 03, 2010 4:23 pm Post subject: Puzzle 10/08/03: C |
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| Code: | +-----------------------+
| 7 3 . | . . 2 | . 1 . |
| 2 . . | . . . | . 4 . |
| . . 6 | . . 1 | 2 . . |
|-------+-------+-------|
| . . . | 9 . 7 | 5 8 . |
| . . . | . 6 5 | . . . |
| 5 . 7 | 3 8 . | 1 . 2 |
|-------+-------+-------|
| . . 5 | 1 . 6 | 3 . . |
| 3 1 . | 8 . . | . 2 . |
| . . . | . . 3 | . . . |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Tue Aug 03, 2010 5:16 pm Post subject: |
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ALS xz
A={2,4,6}
B={2,4,7,8,9}
x= 2; linked at r47c2
z= 4; r4c9<>4
| Code: | +----------------------+----------------------+----------------------+
| 7 3 89 | 456 459 2 | 689 1 5689 |
| 2 5 1 | 67 379 8 | 679 4 3679 |
| 489 48 6 | 57 3579 1 | 2 357 35789 |
+----------------------+----------------------+----------------------+
| A46 A26 23 | 9 1 7 | 5 8 3-4 |
| 1 48 38 | 2 6 5 | 479 37 3479 |
| 5 9 7 | 3 8 4 | 1 6 2 |
+----------------------+----------------------+----------------------+
| B89 B27 5 | 1 247 6 | 3 B79 B48 |
| 3 1 4 | 8 57 9 | 67 2 567 |
| 689 267 289 | 457 2457 3 | 48 579 1 |
+----------------------+----------------------+----------------------+
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I saw the ALS first before I noticed it was also a real xx XY chain with pincers at r4c1 & r7c9 |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Tue Aug 03, 2010 7:51 pm Post subject: |
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| 4-SIS AIC : 2R7 4R7 4R4 6R4 => r4c2<>2 |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Tue Aug 03, 2010 8:31 pm Post subject: |
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Mm, nice ALS-XZ - I'm still some way off naturally spotting those!
This grid has a lot of xy options - especially xy-chains in r4 and r7.
I was looking for m-wings, here's one with a pseudo-cell at the front - I am sure there are more!
| Code: | | m-wing(24) (2=3)r4c3-(3=4)r4c9 - r7c9=(4-2)r7c5=r7c2; r4c2<>2, r9c3<>2 |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Aug 05, 2010 4:32 am Post subject: |
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ER (5)
Potential DP (45) in boxes 28; all DP killers lead to r79c8=95. |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Thu Aug 05, 2010 6:48 pm Post subject: |
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| Marty R. wrote: | ER (5)
Potential DP (45) in boxes 28; all DP killers lead to r79c8=95. |
I don't think I'm seeing the same results from that AUR; mine is r9c5<>5. Would you please elaborate? |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Aug 05, 2010 9:32 pm Post subject: |
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| ronk wrote: | | Marty R. wrote: | ER (5)
Potential DP (45) in boxes 28; all DP killers lead to r79c8=95. |
I don't think I'm seeing the same results from that AUR; mine is r9c5<>5. Would you please elaborate? |
R9c5 being<>5 is certainly compatible with my r9c8 being=5. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Aug 05, 2010 10:27 pm Post subject: |
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However, to further elaborate, this is my grid after an ER on 5:
| Code: |
+-------------+------------+---------------+
| 7 3 89 | 456 459 2 | 689 1 5689 |
| 2 5 1 | 67 379 8 | 679 4 3679 |
| 489 48 6 | 57 379 1 | 2 357 35789 |
+-------------+------------+---------------+
| 46 26 23 | 9 1 7 | 5 8 34 |
| 1 48 38 | 2 6 5 | 479 37 3479 |
| 5 9 7 | 3 8 4 | 1 6 2 |
+-------------+------------+---------------+
| 89 27 5 | 1 247 6 | 3 79 48 |
| 3 1 4 | 8 57 9 | 67 2 567 |
| 689 267 289 | 457 2457 3 | 48 579 1 |
+-------------+------------+---------------+
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Play this puzzle online at the Daily Sudoku site
The DP killers are:
1) 3679 pseudo cell in box 2
2) R9c4 or r9c5=7
3) R9c5=2
All three lead to r79c8=95. I could've also said all three lead to r7c9 and r9c7=48 or r7c1=8 or r8c5=5 or, as you mentioned, r9c5<>5. |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Thu Aug 05, 2010 11:03 pm Post subject: |
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In a Ruud thread that was lost during the crash of the Players' Forums, I once asked (paraphrased), "What restrictions apply to what can be done to resolve a UR pattern." His reply (paraphrased), "None."
Marty, congratulations on taking Ruud's reply to the limit!!!
| Code: | *--------------------------------------------------------------------*
| 7 3 89 | 45+6 45+9 2 | 689 1 5689 |
| 2 5 1 | 67 379 8 | 679 4 3679 |
| 489 48 6 | 57 379 1 | 2 357 35789 |
|----------------------+----------------------+----------------------|
| 46 26 23 | 9 1 7 | 5 8 34 |
| 1 48 38 | 2 6 5 | 479 37 3479 |
| 5 9 7 | 3 8 4 | 1 6 2 |
|----------------------+----------------------+----------------------|
| 89 27 5 | 1 247 6 | 3 79 48 |
| 3 1 4 | 8 57 9 | 67 2 567 |
| 689 267 289 | 45+7 45+27 3 | 48 579 1 |
*--------------------------------------------------------------------*
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| Code: | (6)r1c4 - (6=89=5)r1c379 - (5)r8c7 = (5-9)r9c8 = (9)r7c8
(9)r1c5 - (9=68=5)r1c379 - (5)r8c7 = (5-9)r9c8 = (9)r7c8
(7)r7c45 - (7=5)8c5 - (5)r9c45 = (5-9)r9c8 = (9)r7c8
(2)r9c5 - r7c5 = r7c2 - r4c3 = (2-3)r4c3 = r5c3 - (3=7)r5c8 - (7=9)r7c8 - (79=5)r9c8
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In every instance, r7c8=9 and r9c8=5 !!! |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Aug 06, 2010 12:22 am Post subject: |
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| Quote: | | Marty, congratulations on taking Ruud's reply to the limit!!! |
Thanks Danny. I use those URs like that fairly frequently, although it's far from my favorite technique. But, as they say, "ya do what ya gotta do." |
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ronk
Joined: 07 May 2006
Posts: 398
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| Posted: Fri Aug 06, 2010 1:13 am Post subject: |
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Marty R. & daj95376, now that you've shown the way, here's a somewhat simpler POV using candidates external to the AUR. At least one of DP busters r9c8=5, r3c4=5 and r7c5=4 must ultimately be true.
| Code: | (5)r9c8
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(5)r3c4 - (5)r3c89 = (5)r13c9 - (5)r8c9 = (5)r9c8
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(4-2)r7c5 = (2)r7c2 - (2)r4c2 = (2-3)r4c3 = (3)r5c3 - (3=79)als:r57c8 - (79=5)aals:r9c8 => r9c8=5 |
Marty R., that's a bit complicated but still very nice.
Last edited by ronk on Fri Aug 06, 2010 7:14 am; edited 1 time in total |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Aug 06, 2010 6:37 am Post subject: |
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| [Fixed!] |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Thu Aug 12, 2010 6:57 pm Post subject: |
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Another one step solution..............
ANP(89=2)r19c3-r9c5=(2-4)r7c5=r7c9-(4=3)r4c9-r4c3=(3)r5c3; r5c3<>8
Ted |
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