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Puzzle 10/08/21: B

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Sat Aug 21, 2010 6:03 am    Post subject: Puzzle 10/08/21: B Reply with quote
Code:
 +-----------------------+
 | 5 . . | 7 . . | 8 . . |
 | . . . | . 8 6 | . . 5 |
 | . . . | . 9 5 | . 7 . |
 |-------+-------+-------|
 | 2 . . | . . 9 | . . . |
 | . 7 6 | . 4 8 | . 1 . |
 | . 5 1 | 3 7 2 | 4 . 6 |
 |-------+-------+-------|
 | 1 . . | . . 7 | . . 8 |
 | . . 2 | . 5 . | . . . |
 | . 8 . | . . 4 | 7 . 2 |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK
PostPosted: Sat Aug 21, 2010 5:37 pm    Post subject: Reply with quote
An xy-chain one-step..
Quote:
xy-chain (8=3)r3c3 - (3=1)r3c9 - (1=9)r8c9 - (9=3)r5c9 - (3=9)r5c1 - (9=8)r6c1 ; r3c1<>8, r4c3<>8

As found, or this more terse AIC with same pincers (4-SIS!?)

AIC (8=3)r3c3 - r3c9=(3-9)r5c9=(9-8)r6c8=r6c1 ; r3c1<>8
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JC Van Hay



Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
PostPosted: Sat Aug 21, 2010 6:27 pm    Post subject: Reply with quote
Quasi the same one 4-SIS proof as Peter's ...
Quote:
4-SIS AIC : 3C9 9B6 8R6 8C3 : (3)r3c9=(8)r3c3 : => r3c3<>3

Peter, in your 2nd chain, there are 4 Strong Links (4 times the equal sign =). Therefore, you have a 4-SIS AIC : (83)R3C3 3C9 9B6 8R6 Very Happy
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Sun Aug 22, 2010 12:26 am    Post subject: Reply with quote
I used three steps following something of a routine sequence......

Quote:
Type 1 UR (16)r49c45; r9c4<>16=9

Condratiction found pursuing an Flightless AXY-wing 34-9: (6)r8c2-r1c2=r1c8-r89c8=r8c8; r8c2<>6 and
Flightless xy-wing 34-9 vertex (34)r4c2 plus transport (9)r5c1-r5c9=(9)r8c9; r8c78<>9

ANP(34=8)r23c1-(8=3)r3c3-(3=1)r3c9-(1=9)r8c9-(9=4)r8c2-(4=3)r4c2; r5c1<>3

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Sun Aug 22, 2010 6:14 pm    Post subject: Reply with quote
And, following the script, I used six steps, ending with a Finned X-Wing on 3.
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