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Puzzle 10/08/23: B

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Mon Aug 23, 2010 3:24 am    Post subject: Puzzle 10/08/23: B Reply with quote
Code:
 +-----------------------+
 | 6 . . | 4 . . | 7 5 2 |
 | . . . | 8 . . | . . 3 |
 | . . 2 | . . . | . . 9 |
 |-------+-------+-------|
 | 2 4 . | 6 . . | . . 1 |
 | . . . | . 7 . | . 3 4 |
 | . . . | . . 8 | . . . |
 |-------+-------+-------|
 | 9 . . | . . . | . 7 . |
 | 1 . . | . 8 . | 4 . . |
 | 3 8 4 | 7 9 . | . . . |
 +-----------------------+

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JC Van Hay



Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
PostPosted: Mon Aug 23, 2010 8:52 am    Post subject: Reply with quote
Quote:
From NP(35)R4C56 : 5-SIS XY Chain : (13)R1C5 (35)R4C5 (53)R4C6 (32)R8C6 (21)R5C6 : => r123c6<>1
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Mon Aug 23, 2010 5:51 pm    Post subject: Reply with quote
Again, an "almost" does the trick.........

Quote:
Axy-wing -135 vertex (35)r3c4, pincers (13)r1c5 & (15)r7c4 with fin (1)r3c4
If xy-wing is true; r7c5<>1
If fin is true (1)r3c4-r6c4=r6c2-r123c2=r2c3-r2c78=(1)r3c8; r3c4<>1 contradiction, thus xy-wing is true

Ted
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK
PostPosted: Mon Aug 23, 2010 7:20 pm    Post subject: Reply with quote
This is basically the same move as JCs but from a different angle
Quote:
w-wing(13) with pseudocell (1=2)r5c6-(2=3)r8c6 - r4c6=r4c5 - (3=1)r1c5 ; r123c6<>1
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Tue Aug 24, 2010 4:37 am    Post subject: Reply with quote
DP 16-26-12; r2c8=4
Chain of some sort; r3c4<>1, which sets up
XY-Wing (351)
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