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Marty R. · Posted: Wed Aug 25, 2010 1:52 am Post subject: Is this a valid kite?

I don't know if it's valid or I got lucky. At any rate, I never tried something like this. (This is Nataraj's RYO #2).

tlanglet · Posted: Wed Aug 25, 2010 2:15 am Post subject:

Marty,

First, I believe you have a typo in your first statement: If r2c9=2, then r5c9=2. It should be If r2c9=2, then r5c9<>2

My understanding of a kite is based on the condition that the cells in the pivot box are false whereas your statement is based on the condition that the hinge cells are true. Using your example,
If r9c2=2 then r3c7<>2, then r3c12=2, not r2c1
If r3c7=2 thenr2c9<>2, then r5c9=2
If r2c7=2 then both r3c7 & r2c9<>2, then r3c12=2 and r5c9=2

Ted

Marty R. · Posted: Wed Aug 25, 2010 3:46 am Post subject:

Thanks Ted, you're very diplomatic. It wasn't a typo, just screwed-up logic, or lack of same. Embarassed

Marty R. · Posted: Wed Aug 25, 2010 4:20 am Post subject:

keith · Posted: Wed Aug 25, 2010 5:44 am Post subject:

Ted,

I don't understand what the terms "hinge" and "pivot" have to do with a kite.

Marty,

Your first statement is false, for it has two cells 2 in C9.

The pattern of unsolved 2 is:

tlanglet · Posted: Wed Aug 25, 2010 2:20 pm Post subject:

My phraseology is definitely the greatest; sorry.

Ted

daj95376 · Joined: 23 Aug 2008 Posts: 3854

Sudopedia has a great description of a 2-String Kite:

http://www.sudopedia.org/wiki/2-String_Kite

As for me, I think of a Kite as two strong links -- one in a row and one in a column. An endpoint from each strong link must be in the same box. There must also be an empty cell where the row and column intersect.