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daj95376
Joined: 23 Aug 2008 Posts: 3854
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Posted: Sun Sep 05, 2010 1:01 am Post subject: Puzzle 10/09/05: A |
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Code: | +-----------------------+
| . . 4 | 7 5 1 | . . . |
| . . . | . . . | . . . |
| 7 . 3 | . 4 9 | 1 . . |
|-------+-------+-------|
| 4 . . | . 2 . | 5 . . |
| 5 . 7 | 6 1 3 | . . 4 |
| 8 . 1 | . 7 5 | 3 . . |
|-------+-------+-------|
| . . 5 | 1 . 7 | . 8 . |
| . . . | . . . | 9 1 . |
| . . . | . 9 . | . . 5 |
+-----------------------+
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JC Van Hay
Joined: 13 Jun 2010 Posts: 494 Location: Charleroi, Belgium
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Posted: Sun Sep 05, 2010 11:01 am Post subject: |
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A two steps solution :
Quote: | Type 1 UR (29)R56C28 : r6c8<>29=6
XY Wing (-256), pivot at R3C2 : => r1c7<>2 | Or a one step proof :
Quote: | Colouring the bivalues in B1 leads to r2c9<>28. Interpretation :
7-SIS AIC written as a 4-SIS ALS Chain : [(28)R3C9 (26)R1C7] [(62)R1C1 (12)R2C1] [1R9 7R9] 7C9 : "ANP(28=6) ANP(6=12) AHP(1=17) 7C9" : NP(28)r3c9,r1c7=(7)r2c9 : => r2c9<>28=7 |
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peterj
Joined: 26 Mar 2010 Posts: 974 Location: London, UK
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Posted: Sun Sep 05, 2010 2:57 pm Post subject: |
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Same as JC
JC, I am struggling a bit to see all the ALS in your solution, but it did lead me to what I assume is a similar AIC using 3 hub cells...
Quote: | (7)r9c7=(7-1)r9c2=(1-5)r2c2=(5-4)r2c8=r2c7 ; r2c7<>7 |
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JC Van Hay
Joined: 13 Jun 2010 Posts: 494 Location: Charleroi, Belgium
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Posted: Sun Sep 05, 2010 4:54 pm Post subject: |
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Peter, marvelous interpretation I understand your confusion : I overlooked I already eliminated (6)r3c9 by colouring . Furthermore, I stopped colouring too early to see your simpler step ! Congratulations Thank you for the checking.
Regards,
JC |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Mon Sep 06, 2010 12:41 am Post subject: |
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Same as JC. |
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