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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Sat Sep 18, 2010 4:58 am Post subject: Puzzle 10/09/18: C |
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| Code: | +-----------------------+
| 3 . . | 5 1 . | . 4 . |
| . 4 . | 7 . . | . . . |
| . . 8 | . 3 . | . . 5 |
|-------+-------+-------|
| 9 . . | . . . | 5 1 . |
| 8 . 6 | . . . | . 3 2 |
| . . . | . . . | . 8 7 |
|-------+-------+-------|
| . . . | . . . | . . . |
| 4 . . | 8 2 9 | . . . |
| . . 3 | . 7 4 | . . 8 |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Sat Sep 18, 2010 9:20 am Post subject: |
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Interesting puzzle for me. Few bivalues initially but some interesting xy moves - the second one makes 11 eliminations (I think).
| Quote: | xy-chain (6=4)r4c9 - (4=9)r5c7 - (9=1)r5c4 - (1=6)r9c4 ; r4c4<>6
xy-cycle (2=6)r1c2 - (6=1)r8c2 - (1=7)r8c3 - (7=2)r1c3 - loop ; r1c67<>2, r2c13<>2, r3c1<>2, r8c79<>1, r7c1<>1, r9c12<>1, r9c2<>6 |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Sat Sep 18, 2010 10:14 am Post subject: |
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First step (could have been simpler ... ) equivalent to Peter's first step ... What about the second one  Well observed and interesting second Peter's move ... 
| Quote: | AIC with ALS : (6=45)R56C5 (5=1379)R456C6,R5C4 9C7 : (6)r6c5=(9)r6c7 : r6c7<>6
X Wing (7)R18 : r37c7<>7 |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Sat Sep 18, 2010 1:51 pm Post subject: |
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A fun puzzle with a twist for me. I am not sure how to determine the possible eliminations for one step plus an interesting Kraken cell.
ANQ(1235=4)r6c1236-(4=237)als:r4c236-(23=6)r4c4-(6=1)r9c4*-(1=9)r5c4-(9=4)r5c7-(4=6)r4c9; r6c4*<>1, contradiction r4c4=6 & r4c9=6 =>r4c4<>6
The initial ANQ sets up a contradiction within the resultant chain that does not directly involve the ANQ. I assume that both the ANQ based deletion plus the contradiction are valid.
Kraken cell (17)r8c3; r8c9=3
(1)r8c3-(1=3)r8c9
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(7)r8c3-(7=2)r1c3-(2=6)r1c2-(6=1)r8c2-(1=3)r8c9
Ted |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Sun Sep 19, 2010 1:42 am Post subject: |
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| tlanglet wrote: | The initial ANQ sets up a contradiction within the resultant chain that does not directly involve the ANQ. I assume that both the ANQ based deletion plus the contradiction are valid.
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Your contradiction is the same as Peter's 4-cell XY-Chain. It results in 43 eliminations -- including subsequent basics -- and makes the rest of the chain extraneous. Sorry! |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Sep 19, 2010 10:31 pm Post subject: |
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| I screwed around with a half-dozen moves and was getting nowhere before spotting the four-cell XY-Loop, which I think is the same as Peter's XY-Cycle. |
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