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Puzzle 10/10/10: B XY

 
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daj95376



Joined: 23 Aug 2008
Posts: 3854
PostPosted: Sun Oct 10, 2010 3:29 am    Post subject: Puzzle 10/10/10: B XY Reply with quote
Code:
 +-----------------------+
 | . . 2 | . 9 . | . 7 . |
 | . 9 . | . 5 . | 3 . . |
 | 6 . . | . . 3 | . 2 . |
 |-------+-------+-------|
 | . . . | 3 . . | . 1 2 |
 | 2 3 . | . 4 . | 5 9 8 |
 | . . 8 | . . 5 | . 6 3 |
 |-------+-------+-------|
 | . 2 . | . 3 . | . . 6 |
 | 8 . 9 | 5 2 4 | . . 7 |
 | . . . | 8 6 1 | 2 5 . |
 +-----------------------+

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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK
PostPosted: Sun Oct 10, 2010 8:36 am    Post subject: Reply with quote
So many w-wings!
Quote:
w-wing(15) ; (5=1)r1c2 - r6c2=r5c3 - (1=5)r7c3 ; r3c3<>5
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Sun Oct 10, 2010 11:15 pm    Post subject: Reply with quote
Quote:
Extended vertex of potential xy-wing: (5=1)r7c3-(1=7)r5c3-(47=5)als:r49c1; r7c1<>5

Ted
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Sun Oct 10, 2010 11:40 pm    Post subject: Reply with quote
Quote:
Another one step solution is a m-wing: (1=7)r2c1-r2c3=(7-1)r5c3=r6c2; r1c2<>1=5

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Mon Oct 11, 2010 1:52 pm    Post subject: Reply with quote
Type 3 UR (47) boxes 46. Either r4c2=5 or r6c2=1. The 5 forces r7c3=1; r5c3<>1.
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