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daj95376
Joined: 23 Aug 2008
Posts: 3854
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 Posted: Tue Oct 12, 2010 5:29 am Post subject: Puzzle 10/10/12: C XY |
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| Code: | +-----------------------+
| . . . | . . 1 | . . . |
| . 3 . | . . 5 | 2 . . |
| . . 1 | 9 6 . | . 7 . |
|-------+-------+-------|
| . . 6 | 2 . . | . . . |
| . . 9 | . . 8 | 1 . 2 |
| 3 2 . | . 1 4 | . . . |
|-------+-------+-------|
| . 8 . | . 2 . | 4 1 7 |
| . . 2 | . . . | 3 8 . |
| . . . | . 8 . | 6 . 5 |
+-----------------------+
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Play this puzzle online at the Daily Sudoku site |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Tue Oct 12, 2010 12:26 pm Post subject: |
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A nice wing...
| Quote: | | w-wing(67) with 2 SL ; (7=6)r6c4 - r6c9=r1c9 - r1c2=r8c2 - (6=7)r8c6 ; r4c6<>7, r89c4<>7 |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Tue Oct 12, 2010 3:08 pm Post subject: |
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Initially I was just having fun with ADPs and found the following. Only the first portion of step two and the third step are needed to complete the puzzle.
BUG-Lite+3 (457)r358c12 External SIS: r1c3=5,r8c456=7; r8c12,r9c46<>7
(5)r1c3-(7)r1c3=r1c4-r2c5=(7)r8c5;
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(7)r8c456;
AUR(78)r12c34
Mixed SIS: r1c3=5,r2c5=7; r1c3<>8
(5)r1c3;
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(7)r2c5-(7=8)r2c3;
External SIS: r2c5=7,r6c3=8; r2c4<>7
(7)r2c5;
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(8)r6c3-(8=7)r2c3;
AUR(15)r48c12 External SIS: r8c4=1,r6c3=5; r1c4, r2c3<>7
(1)r8c4-(4)r8c4=r8c5-(4=7)r2c5;
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(5)r6c3-(5=7)r1c3;
Afterwords, I got just a bit more serious and found this one stepper.
| Quote: | xy-wing 67-8 vertex (67)r6c3; r1c9<>8
plus transport: (8)r6c9-r6c3=r4c1-r3c1=r3c7; r1c7<>8 |
[Edited comment ]
Ted
Last edited by tlanglet on Tue Oct 12, 2010 5:42 pm; edited 1 time in total |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Tue Oct 12, 2010 3:44 pm Post subject: |
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Ted, your external ADP moves are impressive! I suppose it's a bit like looking for Kraken cells/rows/blocks etc. except there are fewer starting points. I occasionally look for internal ones where there is an obvious strong link to use. But having persevered I am at least able to follow your logic..
FWIW I think the second step elimination on 8 is needed to open up the bivalue (57)r1c3 for your last move. |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Tue Oct 12, 2010 5:36 pm Post subject: |
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| peterj wrote: | | Ted, FWIW I think the second step elimination on 8 is needed to open up the bivalue (57)r1c3 for your last move. |
Peter, Thanks for your comments.
And yes, I messed up again in manipulating my post at the last minute by xx the positions of step one and two, but failed to correct the comment.........
Ted |
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