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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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 Posted: Wed Dec 01, 2010 12:07 am Post subject: Dec 1 VH |
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| XY-Wing 34 36 46 Pivoted in r9c7 eliminating 4 in r4c3 solves it. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed Dec 01, 2010 2:13 am Post subject: |
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Two alternatives.
W-Wing (46); r5c1<>4
XY-Chain; r4c9<>2 |
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kuskey
Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
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| Posted: Wed Dec 01, 2010 5:34 am Post subject: Dec 1 VH |
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| and another w-wing on 46 (c37) a strong link in 4 (r4) eliminating 6 in r9c7 solves it |
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Florida Bob
Joined: 25 Jul 2007
Posts: 12
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| Posted: Wed Dec 01, 2010 7:35 pm Post subject: Dec. 1 |
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| I can usually do these pretty easily however this one was a problem. With the first response, row 9, col 7 must be a 7 not a pivot. As far as the w wings from the 46's in box 7, I don't see them eliminating either the 6 in r9, c7 or the 4 in r5, c1. Perhaps I need to see where you were after the regular eliminations. Please help! |
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Kdelle
Joined: 20 Mar 2008
Posts: 59
Location: Hudson, NH
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| Posted: Wed Dec 01, 2010 8:34 pm Post subject: Re: Dec. 1 |
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| Florida Bob wrote: | | I can usually do these pretty easily however this one was a problem. With the first response, row 9, col 7 must be a 7 not a pivot. As far as the w wings from the 46's in box 7, I don't see them eliminating either the 6 in r9, c7 or the 4 in r5, c1. Perhaps I need to see where you were after the regular eliminations. Please help! |
Bob,
I think this is where we all are after basics:
| Code: |
+------------+------------+---------+
| 259 4 7 | 39 58 239 | 89 6 1 |
| 569 3 569 | 7 58 1 | 89 2 4 |
| 29 1 8 | 6 4 29 | 5 3 7 |
+------------+------------+---------+
| 1 7 24 | 5 6 8 | 34 9 23 |
| 2349 8 249 | 139 7 39 | 46 5 26 |
| 359 6 59 | 2 39 4 | 1 7 8 |
+------------+------------+---------+
| 46 9 1 | 34 23 5 | 7 8 36 |
| 7 5 3 | 8 1 6 | 2 4 9 |
| 8 2 46 | 349 39 7 | 36 1 35 |
+------------+------------+---------+
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Play this puzzle online at the Daily Sudoku site
Can you see those solutions now?
Kathy |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed Dec 01, 2010 9:58 pm Post subject: |
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I went a little farther with basics, although I've been making errors lately.
| Code: |
+-----------+------------+---------+
| 259 4 7 | 39 58 239 | 89 6 1 |
| 569 3 569 | 7 58 1 | 89 2 4 |
| 29 1 8 | 6 4 29 | 5 3 7 |
+-----------+------------+---------+
| 1 7 24 | 5 6 8 | 34 9 23 |
| 349 8 249 | 1 7 39 | 46 5 26 |
| 359 6 59 | 2 39 4 | 1 7 8 |
+-----------+------------+---------+
| 46 9 1 | 34 2 5 | 7 8 36 |
| 7 5 3 | 8 1 6 | 2 4 9 |
| 8 2 46 | 349 39 7 | 36 1 5 |
+-----------+------------+---------+
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Play this puzzle online at the Daily Sudoku site |
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Florida Bob
Joined: 25 Jul 2007
Posts: 12
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| Posted: Wed Dec 01, 2010 10:07 pm Post subject: Dec. 1 |
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Kathy,
Thanks for the reply however, I still don't see it. How did you fill in the 1, 2 & 9 in row 8 (col 5, 7 & 9). That looks like the key to me
Bob |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Wed Dec 01, 2010 10:35 pm Post subject: Re: Dec. 1 |
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| Florida Bob wrote: | Kathy,
Thanks for the reply however, I still don't see it. How did you fill in the 1, 2 & 9 in row 8 (col 5, 7 & 9). That looks like the key to me
Bob |
I'm not Kathy, but if you post your grid maybe we could answer the questions. However, looking at the other 8 rows in those columns, I don't know that anything else could exist in r8c579. Have you accounted for the naked pairs and triples in those columns? |
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buettner
Joined: 19 Apr 2006
Posts: 3
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| Posted: Thu Dec 02, 2010 5:50 am Post subject: December 1 VH |
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| After the basics, I found a UR with 29 at R1C1, R3C1, R3C6 and 239 at R1C6. Invoking uniqueness, R1C6 must be 3, that was the crux, and the rest was easy. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Dec 02, 2010 6:07 am Post subject: Re: December 1 VH |
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| buettner wrote: | | After the basics, I found a UR with 29 at R1C1, R3C1, R3C6 and 239 at R1C6. Invoking uniqueness, R1C6 must be 3, that was the crux, and the rest was easy. |
How were you able to get rid of the 5 in r1c1? |
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peterj
Joined: 26 Mar 2010
Posts: 974
Location: London, UK
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| Posted: Thu Dec 02, 2010 5:00 pm Post subject: |
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There's a nice example of an s-wing(46) which solves b7 - for those interested in a more esoteric wing! (Just another viewpoint on the two w-wings already posted)
| Code: | +-----------------+------------+-----------+
| 259 4 7 | 39 58 239 | 89 6 1 |
| 569 3 569 | 7 58 1 | 89 2 4 |
| 29 1 8 | 6 4 29 | 5 3 7 |
+-----------------+------------+-----------+
| 1 7 24 | 5 6 8 | 34 9 23 |
| 3(4)9 8 249 | 1 7 39 | (46) 5 26 |
| 359 6 59 | 2 39 4 | 1 7 8 |
+-----------------+------------+-----------+
| (4)-6 9 1 | 34 2 5 | 7 8 36 |
| 7 5 3 | 8 1 6 | 2 4 9 |
| 8 2 -4(6) | 349 39 7 | 3(6) 1 5 |
+-----------------+------------+-----------+
s-wing(46) ; (4)r7c1=r5c1 - (4=6)r5c7 - (6)r9c7=r9c3 ; r7c1<>6, r9c3<>4
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