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kuskey
Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
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 Posted: Thu Dec 30, 2010 5:18 am Post subject: Dec 30 VH |
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| Either a BUG+1 or a 237 xy-wing will solve it. |
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Willzzz
Joined: 22 Aug 2008
Posts: 5
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| Posted: Thu Dec 30, 2010 10:04 am Post subject: |
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| After basics there is so little left that the solution is not far away. |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Thu Dec 30, 2010 1:49 pm Post subject: |
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| A Very Easy with a bug or a wing !! |
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Ema Nymton
Joined: 17 Apr 2009
Posts: 89
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| Posted: Thu Dec 30, 2010 2:12 pm Post subject: |
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A teaching moment please. The setup after basic.
| Code: |
+----------+-----------+---------+
| 5 18 37A| 27B48 234 | 9 6 12 |
| 18 4 36*| 9 68 23C | 7 5 12 |
| 2 9 67 | 67 5 1 | 4 8 3 |
+----------+-----------+---------+
| 3 7 5 | 8 1 6 | 2 4 9 |
| 4 18 9 | 3 2 5 | 18 7 6 |
| 18 6 2 | 4 7 9 | 18 3 5 |
+----------+-----------+---------+
| 6 2 4 | 5 9 8 | 3 1 7 |
| 9 5 8 | 1 3 7 | 6 2 4 |
| 7 3 1 | 26 46 24 | 5 9 8 |
+----------+-----------+---------+
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The alignment of cells marked with ABC make it that cell r2c3 cannot be '3'
Please explain BUG+1 and how it works (use little words). Thank you.
Ema Nymton
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Thu Dec 30, 2010 3:22 pm Post subject: |
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| Quote: | | Please explain BUG+1 and how it works (use little words). Thank you. |
When there’s just ONE TRIPLE left – e.g. in this puzzle it’s a 234 – look for the two pairs that line up with the triple – here it’s 23 and 24 – look for the no. that occurs three times – here it is obviously a 2. Replace the triple with this no.
Last edited by cgordon on Thu Dec 30, 2010 8:40 pm; edited 1 time in total |
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Julian
Joined: 28 Jul 2010
Posts: 9
Location: Menlo, GA
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| Posted: Thu Dec 30, 2010 4:35 pm Post subject: |
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| If I just look at column six, I don't see why row 1 can't be a 3 or a 4. It was the XY 237 that eventually said it had to be a 2. |
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Julian
Joined: 28 Jul 2010
Posts: 9
Location: Menlo, GA
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| Posted: Thu Dec 30, 2010 4:40 pm Post subject: |
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| I got it. There would be two solutions if the r1c6 was anything but a 2. |
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kuskey
Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
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| Posted: Thu Dec 30, 2010 4:45 pm Post subject: Dec 30 VH |
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| Ema, don't overlook the fact that the pincers -the no. 3- in A and C also eliminate the 3 in r1c6. It matters little in this puzzle because that 3 gets eliminated a few steps later. However, a successful solution may rest on that second eliminatlion. Take all the eliminations a particular technique offers, you may need them. |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Dec 30, 2010 6:14 pm Post subject: |
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Ema,
BUG stands for the ridiculous words Bivalue Universal Grave and refers to a grid that has all bivalue cells. All the numbers can be interchanged to make two solutions, thus, the requirement for one unique solution hasn't been met. BUG+1 or BUG+2, etc. means that all the cells are bivalue except one or two.
See Julian's and Craig's comments for how to proceed. |
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